XPost: comp.theory, comp.lang.c++
Op 04.mrt.2025 om 16:52 schreef olcott:
On 3/4/2025 8:43 AM, Muttley@DastardlyHQ.org wrote:
On Tue, 4 Mar 2025 08:21:39 -0600
olcott <polcott333@gmail.com> wibbled:
On 3/4/2025 4:06 AM, Bonita Montero wrote:
Am 04.03.2025 um 04:07 schrieb olcott:
int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
_DD()
[00002133] 55 push ebp ; housekeeping
[00002134] 8bec mov ebp,esp ; housekeeping
[00002136] 51 push ecx ; make space for local >>>>> [00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404 add esp,+04
[00002144] 8945fc mov [ebp-04],eax
[00002147] 837dfc00 cmp dword [ebp-04],+00
[0000214b] 7402 jz 0000214f
[0000214d] ebfe jmp 0000214d
[0000214f] 8b45fc mov eax,[ebp-04]
[00002152] 8be5 mov esp,ebp
[00002154] 5d pop ebp
[00002155] c3 ret
Size in bytes:(0035) [00002155]
DD correctly emulated by HHH cannot possibly
reach its own "ret" instruction and terminate normally.
The only valid rebuttal is to show all of the steps of
exactly how DD correctly emulated by HHH reaches its
own "ret" instruction.
You're wrong; your program will never stop - like
your halting problem investigations.
I am not wrong and no one can show that I wrong
You're making the assertion, so YOU need to prove the program will halt,
its not for others to prove that it won't.
The code proves that DD correctly emulated by HHH
cannot possibly reach its own "ret" instruction and
terminate normally. This proves that HHH(DD) is correct
to reject its input as non-terminating.
No, it reports its failure to do a correct simulation.
If this is incorrect then someone could point out exactly
how DD correctly emulated by HHH would reach its own "ret"
instruction.
If HHH did not fail to reach the 'ret' instruction Olcott could show a
trace that reaches the 'ret' instruction.
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