On 2024-06-09 22:20, HenHanna via Python-list wrote:

Chunk, ChunkC -- nice simple way(s) to write these in Python?

(Chunk '(a a b a a a b b))
==> ((a a) (b) (a a a) (b b))

(Chunk '(a a a a b c c a a d e e e e))
==> ((a a a a) (b) (c c) (a a) (d) (e e e e))

(Chunk '(2 2 foo bar bar j j j k baz baz))
==> ((2 2) (foo) (bar bar) (j j j) (k) (baz baz))

_________________

(ChunkC '(a a b b b))
==> ((a 2) (b 3))

(ChunkC '(a a b a a a b b))
==> ((a 2) (b 1) (a 3) (b 2))

You can make use of itertools.groupby.

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On 6/9/2024 3:50 PM, MRAB wrote:

On 2024-06-09 22:20, HenHanna via Python-list wrote:

Chunk, ChunkC -- nice simple way(s) to write these in Python?


(Chunk  '(a a   b    a a a   b b))
      ==> ((a a) (b)  (a a a) (b b))


(Chunk  '(a a a a   b   c c   a a   d   e e e e))
      ==> ((a a a a) (b) (c c) (a a) (d) (e e e e))


(Chunk  '(2 2   foo   bar bar   j j j   k   baz baz))
      ==> ((2 2) (foo) (bar bar) (j j j) (k) (baz baz))

_________________

(ChunkC  '(a a   b b b))
       ==> ((a 2)  (b 3))

(ChunkC  '(a a   b      a a a   b b))
       ==> ((a 2)  (b 1)  (a 3)   (b 2))

You can make use of itertools.groupby.

Thanks! i'll try it.


Scheme (Gauche)

(use srfi-1) ; span

(define (gp x)
(if (null? x) '()
(let-values (((F L) (span (cut equal? (car x) <>) x)))
(cons F (gp L)))))

(print (gp '(a b b a a a b b b b)))
(print (gp '(c c c a d d d d a e e e e e)))

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XPost: comp.lang.scheme

On 6/9/2024 7:05 PM, avi.e.gross@gmail.com wrote:

I remembered that HenHanna had been hard to deal with in the past and when
my reply to him/her/them bounced as a bad/fake address it came back to me that I am better off not participating in this latest attempt to get us to perform then probably shoot whatever we say down.

A considerate person would ask questions more clearly and perhaps explain what language they are showing us code from and so on.

Life is too short to waste.

-----Original Message-----
From: Python-list <python-list-bounces+avi.e.gross=gmail.com@python.org> On Behalf Of HenHanna via Python-list
Sent: Sunday, June 9, 2024 5:20 PM
To: python-list@python.org
Subject: in Python? -- Chunk -- (ChunkC '(a a b b b)), ==> ((a 2) (b 3))

Chunk, ChunkC -- nice simple way(s) to write these in Python?

(Chunk '(a a b a a a b b))
==> ((a a) (b) (a a a) (b b))

(Chunk '(a a a a b c c a a d e e e e))
==> ((a a a a) (b) (c c) (a a) (d) (e e e e))

(Chunk '(2 2 foo bar bar j j j k baz baz))
==> ((2 2) (foo) (bar bar) (j j j) (k) (baz baz))

_________________

(ChunkC '(a a b b b))
==> ((a 2) (b 3))

(ChunkC '(a a b a a a b b))
==> ((a 2) (b 1) (a 3) (b 2))

i was just curiuos about simple, clever way to write it in Python


in Scheme (Gauche)

(use srfi-1) ;; span

(define (gp x)
(if (null? x) '()
(let-values (((F L) (span (cut equal? (car x) <>) x)))
(cons F (gp L)))))

(print (gp '(a b b a a a b b b b)))
(print (gp '(c c c a d d d d a e e e e e)))

(define (gpC x) (map (lambda (x) (list (car x) (length x))) (gp x)))

(print (gpC '(a b b a a a b b b b)))
(print (gpC '(c c c a d d d d a e e e e e)))

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import itertools

def chunk1(seq):
    return [ ch * len(list(grp)) for (ch, grp) in itertools.groupby(s) ]

def chunk2(seq):
    return [ (ch, len(list(grp))) for (ch, grp) in itertools.groupby(s) ]

s='aaabbccccaa'
print(chunk1(s))
print(chunk2(s))
###################################
Program output:
['aaa', 'bb', 'cccc', 'aa']
[('a', 3), ('b', 2), ('c', 4), ('a', 2)]

Rob Cliffe

On 09/06/2024 22:20, HenHanna via Python-list wrote:

Chunk, ChunkC -- nice simple way(s) to write these in Python?

(Chunk  '(a a   b    a a a   b b))
    ==> ((a a) (b)  (a a a) (b b))

(Chunk  '(a a a a   b   c c   a a   d   e e e e))
    ==> ((a a a a) (b) (c c) (a a) (d) (e e e e))

(Chunk  '(2 2   foo   bar bar   j j j   k   baz baz))
    ==> ((2 2) (foo) (bar bar) (j j j) (k) (baz baz))

_________________

(ChunkC  '(a a   b b b))
     ==> ((a 2)  (b 3))

(ChunkC  '(a a   b      a a a   b b))
     ==> ((a 2)  (b 1)  (a 3)   (b 2))

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

On 6/10/2024 6:29 AM, Rob Cliffe wrote:

import itertools

def chunk1(seq):
    return [ ch * len(list(grp)) for (ch, grp) in itertools.groupby(s) ]

def chunk2(seq):
    return [ (ch, len(list(grp))) for (ch, grp) in itertools.groupby(s) ]

s='aaabbccccaa'
print(chunk1(s))
print(chunk2(s))
###################################
Program output:
['aaa', 'bb', 'cccc', 'aa']
[('a', 3), ('b', 2), ('c', 4), ('a', 2)]

Rob Cliffe

thank you... OMG... For 10 minutes... i was SO mystified by
the question...
How can this code work??? , when it's
> def chunk1(seq):
and it's [s] within the def-body ?

it seemed as if the Compiler was doing a DWIM (Do what i mean) trick.

On 09/06/2024 22:20, HenHanna via Python-list wrote:

Chunk, ChunkC -- nice simple way(s) to write these in Python?


(Chunk  '(a a   b    a a a   b b))
    ==> ((a a) (b)  (a a a) (b b))


(Chunk  '(a a a a   b   c c   a a   d   e e e e))
    ==> ((a a a a) (b) (c c) (a a) (d) (e e e e))


(Chunk  '(2 2   foo   bar bar   j j j   k   baz baz))
    ==> ((2 2) (foo) (bar bar) (j j j) (k) (baz baz))

_________________

(ChunkC  '(a a   b b b))
     ==> ((a 2)  (b 3))

(ChunkC  '(a a   b      a a a   b b))
     ==> ((a 2)  (b 1)  (a 3)   (b 2))

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XPost: comp.lang.scheme

On 6/9/2024, HenHanna wrote:

(Chunk '(a a b a a a b b))
==> ((a a) (b) (a a a) (b b))

Gauche Scheme:

(use gauche.sequence)

(group-sequence '(2 4 4 3 0 5 8 6 6 6))
===>
((2) (4 4) (3) (0) (5) (8) (6 6 6))

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