How do I subtract two time/dates and calculate the hours and minutes
between?
Steve

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my approach would be to convert your two date/times to seconds from
epoch - e.g.
https://www.geeksforgeeks.org/convert-python-datetime-to-epoch/ - then
subtract the number, divide the resultant by 3600 (hours) & get the
modulus for minutes.  There's probably a standard function - it should
be /very/ easy to do.

- Marc

On 12/12/2022 5:01 pm, Steve GS wrote:

How do I subtract two time/dates and calculate the hours and minutes
between?
Steve

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

The difference between two datetime objects is a timedelta object. https://docs.python.org/3/library/datetime.html#timedelta-objects . It has a total_seconds() method.

This is a simple task, unless one of the datetimes has a time zone specified and the other doesn’t.

From: Python-list <python-list-bounces+gweatherby=uchc.edu@python.org> on behalf of Marc Lucke <marc@marcsnet.com>
Date: Monday, December 12, 2022 at 11:37 AM
To: python-list@python.org <python-list@python.org>
Subject: Re: Subtracting dates to get hours and minutes
*** Attention: This is an external email. Use caution responding, opening attachments or clicking on links. ***

my approach would be to convert your two date/times to seconds from
epoch - e.g. https://urldefense.com/v3/__https://www.geeksforgeeks.org/convert-python-datetime-to-epoch/__;!!Cn_UX_p3!hBXQeMkZ3QYS6BI0yTHsADseWTXcDXOhKFkg35NnRMicvYQvwLo9c_ihSaTrG60LywsKQm6UNd7mAAYr$<https://urldefense.com/v3/__https:/www.geeksforgeeks.org/convert-
python-datetime-to-epoch/__;!!Cn_UX_p3!hBXQeMkZ3QYS6BI0yTHsADseWTXcDXOhKFkg35NnRMicvYQvwLo9c_ihSaTrG60LywsKQm6UNd7mAAYr$> - then
subtract the number, divide the resultant by 3600 (hours) & get the
modulus for minutes. There's probably a standard function - it should
be /very/ easy to do.

- Marc

On 12/12/2022 5:01 pm, Steve GS wrote:

How do I subtract two time/dates and calculate the hours and minutes
between?
Steve

-- https://urldefense.com/v3/__https://mail.python.org/mailman/listinfo/python-list__;!!Cn_UX_p3!hBXQeMkZ3QYS6BI0yTHsADseWTXcDXOhKFkg35NnRMicvYQvwLo9c_ihSaTrG60LywsKQm6UNSbh5q0S$<https://urldefense.com/v3/__https:/mail.python.org/mailman/listinfo/python-
list__;!!Cn_UX_p3!hBXQeMkZ3QYS6BI0yTHsADseWTXcDXOhKFkg35NnRMicvYQvwLo9c_ihSaTrG60LywsKQm6UNSbh5q0S$>

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report:
"TypeError: an integer is required (got type tuple)

How do I fix this?

#----------------------------------------------------------------------------- import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
Stopp = datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

# -----------------------------------------------------------------------------

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

Your problem is that datetime.datetime does not accept a tuple as an
argument. It expects an integer value for the first argument, but you
supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes
the sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
st1 = (2022, 12, 13, 5, 3, 30)
dts1 = datetime.datetime(*st1) # NOT datetime.datetime(st1)
dts1 == Startt # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja wrote:

As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report:
"TypeError: an integer is required (got type tuple)

How do I fix this?

#-----------------------------------------------------------------------------
import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
Stopp = datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

# -----------------------------------------------------------------------------

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

I realized it had something to do with tupilation
The simple fix is to add the * into the original code.
Startt = datetime.datetime(*Startt)

I am not sure what "dts1 == Startt # True" does....

Thank you.....


-----Original Message-----
From: Python-list <python-list-bounces+gronicus=sga.ninja@python.org> On
Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org
Subject: Re: Subtracting dates to get hours and minutes

Your problem is that datetime.datetime does not accept a tuple as an
argument. It expects an integer value for the first argument, but you
supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes the sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
st1 = (2022, 12, 13, 5, 3, 30)
dts1 = datetime.datetime(*st1) # NOT datetime.datetime(st1)
dts1 == Startt # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja wrote:

As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report:
"TypeError: an integer is required (got type tuple)

How do I fix this?

#--------------------------------------------------------------------- --------
import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30) Stopp = datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

#
---------------------------------------------------------------------- -------

--
https://mail.python.org/mailman/listinfo/python-list

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

On 12/14/2022 12:55 AM, Gronicus@SGA.Ninja wrote:

I realized it had something to do with tupilation
The simple fix is to add the * into the original code.
Startt = datetime.datetime(*Startt)

I am not sure what "dts1 == Startt # True" does....

It demonstrates that the version with the "*" gives the same result as
the first expression. That line is not needed by any code, it's just
there to show you that the proposed expression gives the desired result.

Thank you.....

-----Original Message-----
From: Python-list <python-list-bounces+gronicus=sga.ninja@python.org> On Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org
Subject: Re: Subtracting dates to get hours and minutes

Your problem is that datetime.datetime does not accept a tuple as an argument. It expects an integer value for the first argument, but you supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes the sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
st1 = (2022, 12, 13, 5, 3, 30)
dts1 = datetime.datetime(*st1) # NOT datetime.datetime(st1)
dts1 == Startt # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja wrote:

As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report:
"TypeError: an integer is required (got type tuple)

How do I fix this?

#---------------------------------------------------------------------
--------
import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30) Stopp =
datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

#
----------------------------------------------------------------------
-------

--
https://mail.python.org/mailman/listinfo/python-list

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

So far so good , I can now use a variable in datetime.datetime but it only works if I hard-code the time/date information. Now I want to have the code read from a file but I get: TypeError: function takes at most 9 arguments
(26 given)

I figure that the structure in the file is incorrect. What should it be? The entry in the file is (2022, 12, 13, 5, 3, 30) but when my program tries to use it I get the error.

The program is a bit more sophisticated now but here is the update with a sample of the SPECIFICATIONS.txt file: =====================================================================

# This program compares two Timedate values, subtracts the two and
# converts the difference to seconds and hours.
#

# %A Monday # %a Mon # %B January # %b Jan
# %d 05 day # %m month as 01 # %Y 2020 # %y 20
# %H 24 # %I 12 # %M 30 min # %S Seconds

import time
import datetime
from time import gmtime, strftime ##define strftime as time/date right now
# ======================================================

def GetSpecByItem(GetThisOne): #get line by item in column 4 - 7
ItemValue = "--"

with open("SPECIFICATIONS.txt" , 'r') as infile:
for lineEQN in infile: # loop to find each line in the file for that
dose
if ((lineEQN[4:7]== GetThisOne)):
ItemValue = lineEQN[30:60].strip() # Just the Data
return(ItemValue)

"""
SPECIFICATIONS.txt

IYf HRB Humalog R Date (2018, 12, 4, 10, 7, 00) ##
IYf HRG Humulin R Date (2022, 12, 13, 5, 3, 30) ##
"""
# ====================== Main() ======================================
print()
Startt = "404"
Stopp = "404"

Answer = "Y"
Answer = input("Run test A? (" + Answer + ")" )

if Answer == "Y" or Answer == "y" or Answer == "":
print()
print(" Running Test A:")
# Year Mth Day Hour Min Sec
Startt = 2018, 12, 4, 10, 7, 00
Stopp = 2022, 12, 12, 1, 15, 30
NowTime = 2022, 12, 14, 21, 15, 30
else:
print(" Running Test B:")
Startt = GetSpecByItem("HRG")
Stopp = GetSpecByItem("HRB")
NowTime = strftime("(%Y, %m, %d, %H, %M, %S)")

print()
print("55 NowTime = " + str(NowTime))
print("56 Startt = " + str(Startt))
print("57 Stopp = " + str(Stopp))
print()

NowTime = datetime.datetime(*NowTime)
Startt = datetime.datetime(*Startt)
Stopp = datetime.datetime(*Stopp)

#Start == Startt # True"
#print("Startt test = " + Start)
# =================================================
print()
c = NowTime - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print ("77 Hours = <" + str(hours) + ">")
print ("78 Minutes = <" + str(minutes) + ">")
if hours > 7:
print(" Time to inject Humulin R u500.")

pause = input("Pause")
# ======================================================


-----Original Message-----
From: Python-list <python-list-bounces+gronicus=sga.ninja@python.org> On
Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org
Subject: Re: Subtracting dates to get hours and minutes

Your problem is that datetime.datetime does not accept a tuple as an
argument. It expects an integer value for the first argument, but you
supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes the sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
st1 = (2022, 12, 13, 5, 3, 30)
dts1 = datetime.datetime(*st1) # NOT datetime.datetime(st1)
dts1 == Startt # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja wrote:

As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report:
"TypeError: an integer is required (got type tuple)

How do I fix this?

#--------------------------------------------------------------------- --------
import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30) Stopp = datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

#
---------------------------------------------------------------------- -------

--
https://mail.python.org/mailman/listinfo/python-list

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

On 2022-12-15 18:14, Gronicus@SGA.Ninja wrote:

So far so good , I can now use a variable in datetime.datetime but it only works if I hard-code the time/date information. Now I want to have the code read from a file but I get: TypeError: function takes at most 9 arguments
(26 given)

I figure that the structure in the file is incorrect. What should it be? The entry in the file is (2022, 12, 13, 5, 3, 30) but when my program tries to use it I get the error.

The program is a bit more sophisticated now but here is the update with a sample of the SPECIFICATIONS.txt file: =====================================================================

# This program compares two Timedate values, subtracts the two and
# converts the difference to seconds and hours.
#

# %A Monday # %a Mon # %B January # %b Jan
# %d 05 day # %m month as 01 # %Y 2020 # %y 20
# %H 24 # %I 12 # %M 30 min # %S Seconds

import time
import datetime
from time import gmtime, strftime ##define strftime as time/date right now
# ======================================================

def GetSpecByItem(GetThisOne): #get line by item in column 4 - 7
ItemValue = "--"

with open("SPECIFICATIONS.txt" , 'r') as infile:
for lineEQN in infile: # loop to find each line in the file for that dose
if ((lineEQN[4:7]== GetThisOne)):

You don't need the parentheses, and certainly 2 pairs of them!

ItemValue = lineEQN[30:60].strip() # Just the Data
return(ItemValue)

You're returning a _string_.

I suggest using 'literal_eval' from the 'ast' module to convert the
string safely into a tuple.

However, if the 'for' loop fails to match a line, the function will
return "--", which won't be of any use later on unless you check for it specifically and, say, report an error to the user.

"""
SPECIFICATIONS.txt

IYf HRB Humalog R Date (2018, 12, 4, 10, 7, 00) ##
IYf HRG Humulin R Date (2022, 12, 13, 5, 3, 30) ##
"""
# ====================== Main() ====================================== print()
Startt = "404"
Stopp = "404"

Answer = "Y"
Answer = input("Run test A? (" + Answer + ")" )

if Answer == "Y" or Answer == "y" or Answer == "":
print()
print(" Running Test A:")
# Year Mth Day Hour Min Sec
Startt = 2018, 12, 4, 10, 7, 00
Stopp = 2022, 12, 12, 1, 15, 30
NowTime = 2022, 12, 14, 21, 15, 30

'Startt' and 'Stopp' here are tuples.

else:
print(" Running Test B:")
Startt = GetSpecByItem("HRG")
Stopp = GetSpecByItem("HRB")

'Startt' and 'Stopp' here are _strings_.

NowTime = strftime("(%Y, %m, %d, %H, %M, %S)")

print()
print("55 NowTime = " + str(NowTime))
print("56 Startt = " + str(Startt))
print("57 Stopp = " + str(Stopp))
print()

NowTime = datetime.datetime(*NowTime)
Startt = datetime.datetime(*Startt)
Stopp = datetime.datetime(*Stopp)

These will work if 'Startt' and 'Stopp' are tuples, but not if they're
strings. In the latter case, you're effectively passing multiple single-characters strings into 'datetime'.

#Start == Startt # True"
#print("Startt test = " + Start)
# =================================================
print()
c = NowTime - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print ("77 Hours = <" + str(hours) + ">")
print ("78 Minutes = <" + str(minutes) + ">")
if hours > 7:
print(" Time to inject Humulin R u500.")

pause = input("Pause")
# ======================================================

-----Original Message-----
From: Python-list <python-list-bounces+gronicus=sga.ninja@python.org> On Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org
Subject: Re: Subtracting dates to get hours and minutes

Your problem is that datetime.datetime does not accept a tuple as an argument. It expects an integer value for the first argument, but you supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes the sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
st1 = (2022, 12, 13, 5, 3, 30)
dts1 = datetime.datetime(*st1) # NOT datetime.datetime(st1)
dts1 == Startt # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja wrote:

As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report:
"TypeError: an integer is required (got type tuple)

How do I fix this?

#---------------------------------------------------------------------
--------
import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30) Stopp =
datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

#
----------------------------------------------------------------------
-------

--
https://mail.python.org/mailman/listinfo/python-list

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

It's hard to be sure from what you have offered, but I suspect that you
are taking the string "(2022, 12, 13, 5, 3, 30)" from the file and
using it as is. When you feed that in as a starred argument, the string
gets treated as a sequence where each item is a character in the string.
Your example contains 26 characters, which matches the error message,
so that's probably what is going on.

You need to convert the string into the correct integers, because is the datetime function expects to get integers, not strings. It isn't going
to work with a string that looks like a tuple when it is printed.

Here is one way you could do this. From the input file, extract the
string. Call it dstr. Then you have to get rid of the parentheses and
separate out each item so you can convert it into an integer. So:

items = dstr[1:-2].split(',') # This creates a list of strings.
# print(items) --> ['2022', ' 12', ' 13', ' 5', ' 3', ' 3']

# Create a tuple of integers from the string items
seq = (int(n) for n in items)
# or make it a list instead: seq = [int(n) for n in items]

# And here is the datetime object you wanted
d1 = datetime.datetime(*seq)


On 12/15/2022 1:14 PM, Gronicus@SGA.Ninja wrote:

So far so good , I can now use a variable in datetime.datetime but it only works if I hard-code the time/date information. Now I want to have the code read from a file but I get: TypeError: function takes at most 9 arguments
(26 given)

I figure that the structure in the file is incorrect. What should it be? The entry in the file is (2022, 12, 13, 5, 3, 30) but when my program tries to use it I get the error.

The program is a bit more sophisticated now but here is the update with a sample of the SPECIFICATIONS.txt file: =====================================================================

# This program compares two Timedate values, subtracts the two and
# converts the difference to seconds and hours.
#

# %A Monday # %a Mon # %B January # %b Jan
# %d 05 day # %m month as 01 # %Y 2020 # %y 20
# %H 24 # %I 12 # %M 30 min # %S Seconds

import time
import datetime
from time import gmtime, strftime ##define strftime as time/date right now
# ======================================================

def GetSpecByItem(GetThisOne): #get line by item in column 4 - 7
ItemValue = "--"

with open("SPECIFICATIONS.txt" , 'r') as infile:
for lineEQN in infile: # loop to find each line in the file for that dose
if ((lineEQN[4:7]== GetThisOne)):
ItemValue = lineEQN[30:60].strip() # Just the Data
return(ItemValue)

"""
SPECIFICATIONS.txt

IYf HRB Humalog R Date (2018, 12, 4, 10, 7, 00) ##
IYf HRG Humulin R Date (2022, 12, 13, 5, 3, 30) ##
"""
# ====================== Main() ====================================== print()
Startt = "404"
Stopp = "404"

Answer = "Y"
Answer = input("Run test A? (" + Answer + ")" )

if Answer == "Y" or Answer == "y" or Answer == "":
print()
print(" Running Test A:")
# Year Mth Day Hour Min Sec
Startt = 2018, 12, 4, 10, 7, 00
Stopp = 2022, 12, 12, 1, 15, 30
NowTime = 2022, 12, 14, 21, 15, 30
else:
print(" Running Test B:")
Startt = GetSpecByItem("HRG")
Stopp = GetSpecByItem("HRB")
NowTime = strftime("(%Y, %m, %d, %H, %M, %S)")

print()
print("55 NowTime = " + str(NowTime))
print("56 Startt = " + str(Startt))
print("57 Stopp = " + str(Stopp))
print()

NowTime = datetime.datetime(*NowTime)
Startt = datetime.datetime(*Startt)
Stopp = datetime.datetime(*Stopp)

#Start == Startt # True"
#print("Startt test = " + Start)
# =================================================
print()
c = NowTime - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print ("77 Hours = <" + str(hours) + ">")
print ("78 Minutes = <" + str(minutes) + ">")
if hours > 7:
print(" Time to inject Humulin R u500.")

pause = input("Pause")
# ======================================================

-----Original Message-----
From: Python-list <python-list-bounces+gronicus=sga.ninja@python.org> On Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org
Subject: Re: Subtracting dates to get hours and minutes

Your problem is that datetime.datetime does not accept a tuple as an argument. It expects an integer value for the first argument, but you supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes the sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
st1 = (2022, 12, 13, 5, 3, 30)
dts1 = datetime.datetime(*st1) # NOT datetime.datetime(st1)
dts1 == Startt # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja wrote:

As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report:
"TypeError: an integer is required (got type tuple)

How do I fix this?

#---------------------------------------------------------------------
--------
import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30) Stopp =
datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

#
----------------------------------------------------------------------
-------

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Yes, it works like a charm. On the tupility of it all.
Special thanks for the explanation too…..



Now that the code no longer produces the errors, I see that the year and month not included in the calculation? How do I fix this?



From: anthony.flury <anthony.flury@btinternet.com>
Sent: Thursday, December 15, 2022 1:47 PM
To: Gronicus@SGA.Ninja
Subject: RE: Subtracting dates to get hours and minutes



What is likely happening is that when you read the data from the file you are not reading a tuple, you are reading a 26 charcter string.

You have to convert that string into a tuple - the easiest way will be somthing like this :



timet = tuple(int(x.strip()) for x in timestring[1:-1].split(','))



where timestring is the data you get from the file

The [1:-1] removes the () from the data

The .split(",") method creates a temporary list from the remaining string breaking the string where there are commas

The x.strip() removes spaces from each item in the temporary list.



Note that the * unpack operator doesn't just unpack tuples, it works on an iterable, so when you read the data from the file currently, and then use * on it, it will pass 26 separate characters to the function.





------ Original Message ------
From: Gronicus@SGA.Ninja <mailto:Gronicus@SGA.Ninja>
To: "'Thomas Passin'" <list1@tompassin.net <mailto:list1@tompassin.net> >; python-list@python.org <mailto:python-list@python.org>
Sent: Thursday, 15 Dec, 22 At 18:14
Subject: RE: Subtracting dates to get hours and minutes

So far so good , I can now use a variable in datetime.datetime but it only works if I hard-code the time/date information. Now I want to have the code read from a file but I get: TypeError: function takes at most 9 arguments
(26 given)

I figure that the structure in the file is incorrect. What should it be? The entry in the file is (2022, 12, 13, 5, 3, 30) but when my program tries to
use it I get the error.

The program is a bit more sophisticated now but here is the update with a sample of the SPECIFICATIONS.txt file: =====================================================================

# This program compares two Timedate values, subtracts the two and
# converts the difference to seconds and hours.
#

# %A Monday # %a Mon # %B January # %b Jan
# %d 05 day # %m month as 01 # %Y 2020 # %y 20
# %H 24 # %I 12 # %M 30 min # %S Seconds

import time
import datetime
from time import gmtime, strftime ##define strftime as time/date right now
# ======================================================

def GetSpecByItem(GetThisOne): #get line by item in column 4 - 7
ItemValue = "--"

with open("SPECIFICATIONS.txt" , 'r') as infile:
for lineEQN in infile: # loop to find each line in the file for that
dose
if ((lineEQN[4:7]== GetThisOne)):
ItemValue = lineEQN[30:60].strip() # Just the Data
return(ItemValue)

"""
SPECIFICATIONS.txt

IYf HRB Humalog R Date (2018, 12, 4, 10, 7, 00) ##
IYf HRG Humulin R Date (2022, 12, 13, 5, 3, 30) ##
"""
# ====================== Main() ======================================
print()
Startt = "404"
Stopp = "404"

Answer = "Y"
Answer = input("Run test A? (" + Answer + ")" )

if Answer == "Y" or Answer == "y" or Answer == "":
print()
print(" Running Test A:")
# Year Mth Day Hour Min Sec
Startt = 2018, 12, 4, 10, 7, 00
Stopp = 2022, 12, 12, 1, 15, 30
NowTime = 2022, 12, 14, 21, 15, 30
else:
print(" Running Test B:")
Startt = GetSpecByItem("HRG")
Stopp = GetSpecByItem("HRB")
NowTime = strftime("(%Y, %m, %d, %H, %M, %S)")

print()
print("55 NowTime = " + str(NowTime))
print("56 Startt = " + str(Startt))
print("57 Stopp = " + str(Stopp))
print()

NowTime = datetime.datetime(*NowTime)
Startt = datetime.datetime(*Startt)
Stopp = datetime.datetime(*Stopp)

#Start == Startt # True"
#print("Startt test = " + Start)
# =================================================
print()
c = NowTime - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print ("77 Hours = <" + str(hours) + ">")
print ("78 Minutes = <" + str(minutes) + ">")
if hours > 7:
print(" Time to inject Humulin R u500.")

pause = input("Pause")
# ======================================================


-----Original Message-----
From: Python-list <python-list-bounces+gronicus=sga.ninja@python.org <mailto:python-list-bounces+gronicus=sga.ninja@python.org> > On
Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org <mailto:python-list@python.org>
Subject: Re: Subtracting dates to get hours and minutes

Your problem is that datetime.datetime does not accept a tuple as an
argument. It expects an integer value for the first argument, but you
supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes the sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
st1 = (2022, 12, 13, 5, 3, 30)
dts1 = datetime.datetime(*st1) # NOT datetime.datetime(st1)
dts1 == Startt # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja <mailto:Gronicus@SGA.Ninja> wrote:


As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report: "TypeError: an integer is required (got type tuple)

How do I fix this?

#---------------------------------------------------------------------
--------
import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30) Stopp = datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

#
----------------------------------------------------------------------
-------


--
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--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)

Yes, it works like a charm. On the tupility of it all.
Special thanks for the explanation too…..



(Originally asked but I found the errors. All is working)

Now that the code no longer produces the errors, I see that the year and month not included in the calculation? How do I fix this?



From: anthony.flury <anthony.flury@btinternet.com>
Sent: Thursday, December 15, 2022 1:47 PM
To: Gronicus@SGA.Ninja
Subject: RE: Subtracting dates to get hours and minutes



What is likely happening is that when you read the data from the file you are not reading a tuple, you are reading a 26 charcter string.

You have to convert that string into a tuple - the easiest way will be somthing like this :



timet = tuple(int(x.strip()) for x in timestring[1:-1].split(','))



where timestring is the data you get from the file

The [1:-1] removes the () from the data

The .split(",") method creates a temporary list from the remaining string breaking the string where there are commas

The x.strip() removes spaces from each item in the temporary list.



Note that the * unpack operator doesn't just unpack tuples, it works on an iterable, so when you read the data from the file currently, and then use * on it, it will pass 26 separate characters to the function.





------ Original Message ------
From: Gronicus@SGA.Ninja <mailto:Gronicus@SGA.Ninja>
To: "'Thomas Passin'" <list1@tompassin.net <mailto:list1@tompassin.net> >; python-list@python.org <mailto:python-list@python.org>
Sent: Thursday, 15 Dec, 22 At 18:14
Subject: RE: Subtracting dates to get hours and minutes

So far so good , I can now use a variable in datetime.datetime but it only works if I hard-code the time/date information. Now I want to have the code read from a file but I get: TypeError: function takes at most 9 arguments
(26 given)

I figure that the structure in the file is incorrect. What should it be? The entry in the file is (2022, 12, 13, 5, 3, 30) but when my program tries to
use it I get the error.

The program is a bit more sophisticated now but here is the update with a sample of the SPECIFICATIONS.txt file: =====================================================================

# This program compares two Timedate values, subtracts the two and
# converts the difference to seconds and hours.
#

# %A Monday # %a Mon # %B January # %b Jan
# %d 05 day # %m month as 01 # %Y 2020 # %y 20
# %H 24 # %I 12 # %M 30 min # %S Seconds

import time
import datetime
from time import gmtime, strftime ##define strftime as time/date right now
# ======================================================

def GetSpecByItem(GetThisOne): #get line by item in column 4 - 7
ItemValue = "--"

with open("SPECIFICATIONS.txt" , 'r') as infile:
for lineEQN in infile: # loop to find each line in the file for that
dose
if ((lineEQN[4:7]== GetThisOne)):
ItemValue = lineEQN[30:60].strip() # Just the Data
return(ItemValue)

"""
SPECIFICATIONS.txt

IYf HRB Humalog R Date (2018, 12, 4, 10, 7, 00) ##
IYf HRG Humulin R Date (2022, 12, 13, 5, 3, 30) ##
"""
# ====================== Main() ======================================
print()
Startt = "404"
Stopp = "404"

Answer = "Y"
Answer = input("Run test A? (" + Answer + ")" )

if Answer == "Y" or Answer == "y" or Answer == "":
print()
print(" Running Test A:")
# Year Mth Day Hour Min Sec
Startt = 2018, 12, 4, 10, 7, 00
Stopp = 2022, 12, 12, 1, 15, 30
NowTime = 2022, 12, 14, 21, 15, 30
else:
print(" Running Test B:")
Startt = GetSpecByItem("HRG")
Stopp = GetSpecByItem("HRB")
NowTime = strftime("(%Y, %m, %d, %H, %M, %S)")

print()
print("55 NowTime = " + str(NowTime))
print("56 Startt = " + str(Startt))
print("57 Stopp = " + str(Stopp))
print()

NowTime = datetime.datetime(*NowTime)
Startt = datetime.datetime(*Startt)
Stopp = datetime.datetime(*Stopp)

#Start == Startt # True"
#print("Startt test = " + Start)
# =================================================
print()
c = NowTime - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print ("77 Hours = <" + str(hours) + ">")
print ("78 Minutes = <" + str(minutes) + ">")
if hours > 7:
print(" Time to inject Humulin R u500.")

pause = input("Pause")
# ======================================================


-----Original Message-----
From: Python-list <python-list-bounces+gronicus=sga.ninja@python.org <mailto:python-list-bounces+gronicus=sga.ninja@python.org> > On
Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org <mailto:python-list@python.org>
Subject: Re: Subtracting dates to get hours and minutes

Your problem is that datetime.datetime does not accept a tuple as an
argument. It expects an integer value for the first argument, but you
supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes the sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
st1 = (2022, 12, 13, 5, 3, 30)
dts1 = datetime.datetime(*st1) # NOT datetime.datetime(st1)
dts1 == Startt # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja <mailto:Gronicus@SGA.Ninja> wrote:


As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report: "TypeError: an integer is required (got type tuple)

How do I fix this?

#---------------------------------------------------------------------
--------
import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30) Stopp = datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

#
----------------------------------------------------------------------
-------


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Not sure what you mean:

x = datetime.datetime(year=2018,month=12,day=4,hour=10)
y = datetime.datetime(year=2022,month=12,day=13,hour=5)
print(x -y)


-1470 days, 5:00:00

If you want to display years, (x-y).days /365

From: Python-list <python-list-bounces+gweatherby=uchc.edu@python.org> on behalf of Gronicus@SGA.Ninja <Gronicus@SGA.Ninja>
Date: Thursday, December 15, 2022 at 5:02 PM
To: 'anthony.flury' <anthony.flury@btinternet.com>, python-list@python.org <python-list@python.org>
Subject: RE: Subtracting dates to get hours and minutes
*** Attention: This is an external email. Use caution responding, opening attachments or clicking on links. ***

Yes, it works like a charm. On the tupility of it all.
Special thanks for the explanation too…..



Now that the code no longer produces the errors, I see that the year and month not included in the calculation? How do I fix this?



From: anthony.flury <anthony.flury@btinternet.com>
Sent: Thursday, December 15, 2022 1:47 PM
To: Gronicus@SGA.Ninja
Subject: RE: Subtracting dates to get hours and minutes



What is likely happening is that when you read the data from the file you are not reading a tuple, you are reading a 26 charcter string.

You have to convert that string into a tuple - the easiest way will be somthing like this :



timet = tuple(int(x.strip()) for x in timestring[1:-1].split(','))



where timestring is the data you get from the file

The [1:-1] removes the () from the data

The .split(",") method creates a temporary list from the remaining string breaking the string where there are commas

The x.strip() removes spaces from each item in the temporary list.



Note that the * unpack operator doesn't just unpack tuples, it works on an iterable, so when you read the data from the file currently, and then use * on it, it will pass 26 separate characters to the function.





------ Original Message ------
From: Gronicus@SGA.Ninja <mailto:Gronicus@SGA.Ninja>
To: "'Thomas Passin'" <list1@tompassin.net <mailto:list1@tompassin.net> >; python-list@python.org <mailto:python-list@python.org>
Sent: Thursday, 15 Dec, 22 At 18:14
Subject: RE: Subtracting dates to get hours and minutes

So far so good , I can now use a variable in datetime.datetime but it only works if I hard-code the time/date information. Now I want to have the code read from a file but I get: TypeError: function takes at most 9 arguments
(26 given)

I figure that the structure in the file is incorrect. What should it be? The entry in the file is (2022, 12, 13, 5, 3, 30) but when my program tries to
use it I get the error.

The program is a bit more sophisticated now but here is the update with a sample of the SPECIFICATIONS.txt file: =====================================================================

# This program compares two Timedate values, subtracts the two and
# converts the difference to seconds and hours.
#

# %A Monday # %a Mon # %B January # %b Jan
# %d 05 day # %m month as 01 # %Y 2020 # %y 20
# %H 24 # %I 12 # %M 30 min # %S Seconds

import time
import datetime
from time import gmtime, strftime ##define strftime as time/date right now
# ======================================================

def GetSpecByItem(GetThisOne): #get line by item in column 4 - 7
ItemValue = "--"

with open("SPECIFICATIONS.txt" , 'r') as infile:
for lineEQN in infile: # loop to find each line in the file for that
dose
if ((lineEQN[4:7]== GetThisOne)):
ItemValue = lineEQN[30:60].strip() # Just the Data
return(ItemValue)

"""
SPECIFICATIONS.txt

IYf HRB Humalog R Date (2018, 12, 4, 10, 7, 00) ##
IYf HRG Humulin R Date (2022, 12, 13, 5, 3, 30) ##
"""
# ====================== Main() ======================================
print()
Startt = "404"
Stopp = "404"

Answer = "Y"
Answer = input("Run test A? (" + Answer + ")" )

if Answer == "Y" or Answer == "y" or Answer == "":
print()
print(" Running Test A:")
# Year Mth Day Hour Min Sec
Startt = 2018, 12, 4, 10, 7, 00
Stopp = 2022, 12, 12, 1, 15, 30
NowTime = 2022, 12, 14, 21, 15, 30
else:
print(" Running Test B:")
Startt = GetSpecByItem("HRG")
Stopp = GetSpecByItem("HRB")
NowTime = strftime("(%Y, %m, %d, %H, %M, %S)")

print()
print("55 NowTime = " + str(NowTime))
print("56 Startt = " + str(Startt))
print("57 Stopp = " + str(Stopp))
print()

NowTime = datetime.datetime(*NowTime)
Startt = datetime.datetime(*Startt)
Stopp = datetime.datetime(*Stopp)

#Start == Startt # True"
#print("Startt test = " + Start)
# =================================================
print()
c = NowTime - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print ("77 Hours = <" + str(hours) + ">")
print ("78 Minutes = <" + str(minutes) + ">")
if hours > 7:
print(" Time to inject Humulin R u500.")

pause = input("Pause")
# ======================================================


-----Original Message-----
From: Python-list <python-list-bounces+gronicus=sga.ninja@python.org <mailto:python-list-bounces+gronicus=sga.ninja@python.org> > On
Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org <mailto:python-list@python.org>
Subject: Re: Subtracting dates to get hours and minutes

Your problem is that datetime.datetime does not accept a tuple as an
argument. It expects an integer value for the first argument, but you
supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes the sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13, 5, 3, 30)
st1 = (2022, 12, 13, 5, 3, 30)
dts1 = datetime.datetime(*st1) # NOT datetime.datetime(st1)
dts1 == Startt # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja <mailto:Gronicus@SGA.Ninja> wrote:


As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report: "TypeError: an integer is required (got type tuple)

How do I fix this?

#---------------------------------------------------------------------
--------
import datetime
#=================================================
# Test A Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13, 5, 3, 30) Stopp = datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
# Test B Date/Time data as a variable
#Startt = (2022, 12, 13, 5, 3, 30)
#Stopp = (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp = datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print()
print (" Hours = <" + str(hours) + ">")
print (" Minutes = <" + str(minutes) + ">")

#
----------------------------------------------------------------------
-------


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Oops,

"items = dstr[1:-2].split(',')"

should have read

"items = dstr[1:-1].split(',')".

On 12/15/2022 1:56 PM, Thomas Passin wrote:

It's hard to be sure from what you have offered, but I suspect that you
are taking the string "(2022, 12, 13,  5,  3, 30)" from the file and
using it as is.  When you feed that in as a starred argument, the string gets treated as a sequence where each item is a character in the string.
 Your example contains 26 characters, which matches the error message,
so that's probably what is going on.

You need to convert the string into the correct integers, because is the datetime function expects to get integers, not strings.  It isn't going
to work with a string that looks like a tuple when it is printed.

Here is one way you could do this.  From the input file, extract the
string. Call it dstr.  Then you have to get rid of the parentheses and separate out each item so you can convert it into an integer.  So:

items = dstr[1:-2].split(',')  # This creates a list of strings.
# print(items) --> ['2022', ' 12', ' 13', '  5', '  3', ' 3']

# Create a tuple of integers from the string items
seq = (int(n) for n in items)
# or make it a list instead: seq = [int(n) for n in items]

# And here is the datetime object you wanted
d1 = datetime.datetime(*seq)

On 12/15/2022 1:14 PM, Gronicus@SGA.Ninja wrote:

So far so good , I can now use a variable in datetime.datetime but it
only
works if I hard-code the time/date information. Now I want to have the
code
read from a file but I get: TypeError: function takes at most 9 arguments
(26 given)

I figure that the structure in the file is incorrect. What should it
be? The
entry in the file is (2022, 12, 13,  5,  3, 30) but when my program
tries to
use it I get the error.

The program is a bit more sophisticated now but here is the update with a
sample of the SPECIFICATIONS.txt file:
=====================================================================

# This program compares two Timedate values, subtracts the two and
# converts the difference to seconds and hours.
#

#  %A Monday    #  %a Mon           #  %B January   #  %b Jan
#  %d 05 day    #  %m month as 01   #  %Y 2020      #  %y 20 >> #  %H 24        #  %I 12            #  %M 30 min    #  %S Seconds

import time
import datetime
from time import gmtime, strftime ##define strftime as time/date right
now
# ======================================================

def GetSpecByItem(GetThisOne):  #get line by item in column 4 - 7
     ItemValue = "--"
     with open("SPECIFICATIONS.txt" , 'r') as infile:
      for lineEQN in infile: # loop to find each line in the file for >> that
dose
         if ((lineEQN[4:7]== GetThisOne)):
            ItemValue = lineEQN[30:60].strip()   # Just the Data
     return(ItemValue)

"""
SPECIFICATIONS.txt

IYf HRB Humalog R Date           (2018, 12, 4, 10,  7, 00)           ##
IYf HRG Humulin R Date           (2022, 12, 13,  5,  3, 30)          ##
"""
# ====================== Main() ======================================
print()
Startt = "404"
Stopp  = "404"

Answer = "Y"
Answer = input("Run test A? (" + Answer + ")" )

if Answer == "Y" or Answer == "y" or Answer == "":
    print()
    print("     Running Test A:")
#           Year  Mth Day Hour Min Sec
    Startt  =   2018, 12, 4, 10,  7, 00
    Stopp   =   2022, 12, 12, 1, 15, 30
    NowTime =   2022, 12, 14, 21, 15, 30
else:
    print("     Running Test B:")
    Startt = GetSpecByItem("HRG")
    Stopp =  GetSpecByItem("HRB")
    NowTime = strftime("(%Y, %m, %d, %H, %M, %S)")
print()
print("55    NowTime = " + str(NowTime))
print("56     Startt = " + str(Startt))
print("57      Stopp = " + str(Stopp))
print()

NowTime =  datetime.datetime(*NowTime)
Startt =   datetime.datetime(*Startt)
Stopp =    datetime.datetime(*Stopp)

#Start == Startt  # True"
#print("Startt test = " + Start)
# =================================================
print()
c = NowTime - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
         minutes = minutes - 60
         hours += 1
minutes = round(minutes)
print ("77 Hours =     <" + str(hours) + ">")
print ("78 Minutes =   <" + str(minutes) + ">")
if hours > 7:
     print(" Time to inject Humulin R u500.")

pause = input("Pause")
# ======================================================


-----Original Message-----
From: Python-list <python-list-bounces+gronicus=sga.ninja@python.org> On
Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org
Subject: Re: Subtracting dates to get hours and minutes

Your problem is that datetime.datetime does not accept a tuple as an
argument.  It expects an integer value for the first argument, but you
supplied a tuple.  In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk.  This causes the >> sequence of items to be treated as individual arguments. So:

Startt = datetime.datetime(2022, 12, 13,  5,  3, 30)
st1 = (2022, 12, 13,  5,  3, 30)
dts1 = datetime.datetime(*st1)  # NOT datetime.datetime(st1)
dts1 == Startt  # True

On 12/13/2022 10:43 PM, Gronicus@SGA.Ninja wrote:

   As is, Test A works.
   Comment out Test A and uncomment Test B it fails.
   In Test B, I move the data into a variable resulting with the report: >>>               "TypeError: an integer is required (got type tuple)

How do I fix this?

#---------------------------------------------------------------------
--------
import datetime
#=================================================
#         Test A   Hard coded Date/Time
Startt = datetime.datetime(2022, 12, 13,  5,  3, 30) Stopp =
datetime.datetime(2022, 12, 12, 21, 15, 30)

# =================================================
#         Test B   Date/Time data as a variable
#Startt = (2022, 12, 13,  5,  3, 30)
#Stopp =  (2022, 12, 12, 21, 15, 30)

#Startt = datetime.datetime(Startt)
#Stopp =  datetime.datetime(Stopp)

# =================================================
c = Startt - Stopp
minutes = c.total_seconds() / 60
minutes = c.seconds / 60
hours = 0

while (minutes > 59):
          minutes = minutes - 60
          hours += 1
minutes = round(minutes)
print()
print ("       Hours =  <" + str(hours) + ">")
print ("     Minutes =  <" + str(minutes) + ">")

#
----------------------------------------------------------------------
-------

--
https://mail.python.org/mailman/listinfo/python-list

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On 2022-12-15 22:49, Gronicus@SGA.Ninja wrote:

Yes, it works like a charm. On the tupility of it all.
Special thanks for the explanation too…..

(Originally asked but I found the errors. All is working)

Now that the code no longer produces the errors, I see that the year and month not included in the calculation? How do I fix this?

How long is a month? How many months are there until January 1? On
December 25, many months will there be until January 1? And how many
years are there until January 1?

[snip]

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On 12/15/2022 11:34 PM, MRAB wrote:

On 2022-12-15 22:49, Gronicus@SGA.Ninja wrote:

Yes, it works like a charm. On the tupility of it all.
Special thanks for the explanation too…..


(Originally asked but I found the errors. All is working)

Now that the code no longer produces the errors, I see that the year
and month not included in the calculation? How do I fix this?

First you should read about the function you are using. In this case,
it is at

https://docs.python.org/3.10/library/datetime.html

I found this page using an internet search for "python datetime.datetime".

All Python functions, classes, and methods will normally be found in the documentation for the standard library, as this one is.

You should also look at datetime.timedelta, as various people have
posted here. Try to understand what is being described. Then try to
make simple examples that will show if you can get what you want, or if
not, what more information you need. Look through the rest of the documentation of (in this case) the datetime module and see if any of
the other functionality looks like it will produce what you want.

It is important to understand clearly what your input data is like, and
what results you need to achieve. If you are not clear, or do not
express yourself clearly, it will be hard and frustrating for others on
the list to assist you.

For example, you wrote "I see that the year and month not included in
the calculation". I don't know what you mean. You already include the
month in the tuple that you feed to datetime.datetime(). That is, in
the input string you showed, "(2022, 12, 13, 5, 3, 30)", it seems that
"2022" represents a year, "12" represents a month, "13" represents a day
of the month, and so forth.

So I don't understand how year and month not included. I see that you
do think that something is not coming out right, but you need to be more precise about what you mean so that others can understand too.

To succeed at programming, you need to be very precise about attending
to details because the computer cannot know what you have in your mind.
To succeed at getting help, you have to be precise and accurate about
what you want to achieve and what is not coming out right, and describe
those things simply and clearly to other people.

In other words, please help us to help you.

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