• Re: Infinite set of HHH/DDD pairs

    From joes@21:1/5 to All on Mon Jul 22 14:32:20 2024
    Am Mon, 22 Jul 2024 09:13:33 -0500 schrieb olcott:
    On 7/22/2024 3:01 AM, Mikko wrote:
    On 2024-07-21 13:50:17 +0000, olcott said:
    On 7/21/2024 4:38 AM, Mikko wrote:
    On 2024-07-20 13:28:36 +0000, olcott said:
    On 7/20/2024 3:54 AM, Mikko wrote:
    On 2024-07-19 14:39:25 +0000, olcott said:
    On 7/19/2024 3:51 AM, Mikko wrote:

    Anyway you did not say that some HHHᵢ can simulate the
    corresponding DDDᵢ to its termination. And each DDDᵢ does
    terminate, whether simulated or not.


    Then DDD correctly simulated by any pure function HHH cannot possibly
    reach its own return instruction and halt, therefore every HHH is
    correct to reject its DDD as non-halting.
    That does not follow. It is never correct to reject a halting
    comoputation as non-halting.
    In each of the above instances DDD never reaches its return instruction
    and halts. This proves that HHH is correct to report that its DDD never halts.
    It can't return if the simulation of it is aborted.

    Within the hypothetical scenario where DDD is correctly emulated by its
    HHH and this HHH never aborts its simulation neither DDD nor HHH ever
    stops running.
    In actuality HHH DOES abort simulating.

    This conclusively proves that HHH is required to abort the simulation of
    its corresponding DDD as required by the design spec that every partial
    halt decider must halt and is otherwise not any kind of decider at all.
    Like Fred recognised a while ago, you are arguing as if HHH didn't abort.

    That HHH is required to abort its simulation of DDD conclusively proves
    that this DDD never halts.
    You've got it the wrong way around.

    --
    Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
    It is not guaranteed that n+1 exists for every n.

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