On 5/7/2025 4:30 PM, Richard Heathfield wrote:A faithful simulation would produce the same behaviour as direct
On 07/05/2025 20:35, olcott wrote:
On 5/7/2025 1:59 PM, Richard Heathfield wrote:
On 07/05/2025 19:31, olcott wrote:
If is was true that it is not a faithful simulation then you would beI already know that the contradictory part of the counter-example
input has always been unreachable code.
If the code is unreachable, it can't be part of a working program, so
simply remove it.
It is unreachable by the Halting Problem counter-example input D when
correctly simulated by the simulating termination analyzer H that it
has been defined to thwart.
If the simulation can't reach code that the directly executed program
reaches, then it's not a faithful simulation.
able to show exactly what sequence of instructions would be a faithful simulation.
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