A simulating halt decider (SHD) must always halt (i.e. provide a halting decision about its input) irregardless of whether or not its input halts.
And those are the facts.
/Flibble
On 6/13/25 11:02 AM, Mr Flibble wrote:
A simulating halt decider (SHD) must always halt (i.e. provide a
halting decision about its input) irregardless of whether or not its
input halts.
And those are the facts.
/Flibble
And to BE a CORRECT decider, its answer must match the criteria defined
for the input, which for a Halt Decider, is does the program represented
by the input halt.
Thus, an input that a SHD that returns the code for non-halting, must
never halt when actually run.
Since for the H/D pair that has been the focus here for years, if H(D) returns 0, D will halt, H(D) returning 0 can not be a correct answer.
PERIOD. THAT IS THE FACTS.
The point is that a SHD can not correctly simulate a non-halting input,
and return 0 as required, and thus if the defining condition of the SHD
is that it is based on its own correct simulation, it can NEVER return
0, as that is just proven to be a contradiction to its requirements.
Since non-halting inputs exist, that says that a SHD based on just its
own correct simulation of its input is just a self-contradiction, and
thus the criteria is incorrect.
A **partial decider** that always halts and **refuses to analyze**inputs that contain pathological self-reference (like `DDD()` that calls `HHH(DDD)`).
On 6/13/25 11:02 AM, Mr Flibble wrote:
A simulating halt decider (SHD) must always halt (i.e. provide a
halting decision about its input) irregardless of whether or not its
input halts.
And those are the facts.
/Flibble
And to BE a CORRECT decider, its answer must match the criteria defined
for the input, which for a Halt Decider, is does the program represented
by the input halt.
Thus, an input that a SHD that returns the code for non-halting, must
never halt when actually run.
Since for the H/D pair that has been the focus here for years, if H(D) returns 0, D will halt, H(D) returning 0 can not be a correct answer.
PERIOD. THAT IS THE FACTS.
The point is that a SHD can not correctly simulate a non-halting input,
and return 0 as required, and thus if the defining condition of the SHD
is that it is based on its own correct simulation, it can NEVER return
0, as that is just proven to be a contradiction to its requirements.
Since non-halting inputs exist, that says that a SHD based on just its
own correct simulation of its input is just a self-contradiction, and
thus the criteria is incorrect.
On Fri, 13 Jun 2025 12:59:47 -0400, Richard Damon wrote:
On 6/13/25 11:02 AM, Mr Flibble wrote:
A simulating halt decider (SHD) must always halt (i.e. provide a
halting decision about its input) irregardless of whether or not its
input halts.
And those are the facts.
/Flibble
And to BE a CORRECT decider, its answer must match the criteria defined
for the input, which for a Halt Decider, is does the program represented
by the input halt.
Thus, an input that a SHD that returns the code for non-halting, must
never halt when actually run.
Since for the H/D pair that has been the focus here for years, if H(D)
returns 0, D will halt, H(D) returning 0 can not be a correct answer.
PERIOD. THAT IS THE FACTS.
The point is that a SHD can not correctly simulate a non-halting input,
and return 0 as required, and thus if the defining condition of the SHD
is that it is based on its own correct simulation, it can NEVER return
0, as that is just proven to be a contradiction to its requirements.
Since non-halting inputs exist, that says that a SHD based on just its
own correct simulation of its input is just a self-contradiction, and
thus the criteria is incorrect.
---
## đ§ Core Claim (Restated)
**Flibbleâs SHD** (Simulating Halt Decider) is:
A **partial decider** that always halts and **refuses to analyze**inputs that contain pathological self-reference (like `DDD()` that calls `HHH(DDD)`).
It does **not** attempt to simulate those inputs completely. Instead, it performs **static analysis**, detects recursion patterns (e.g. mutual self- reference), and classifies them as **non-halting** or rejects them
outright.
---
## â What This *Does* Achieve
* **Avoids infinite recursion** in simulation by terminating analysis
early.
* Enforces a **typed semantic firewall** â i.e. the program being analyzed cannot call the analyzer.
* Provides halting decisions only for "well-formed" inputs.
* **Rejects** pathological inputs as either non-halting or outside the
domain of analysis.
This is similar in spirit to what **ZFC set theory** does with Russell's paradox: it doesnât refute the paradox; it **prevents its formation**.
---
## đ Reframing the Debate with This in Mind
| Aspect | Damonâs Assumption (Classical H) | Flibbleâs Clarification (Partial SHD) |
| ------------------------- | ------------------------------------ | ---------------------------------------- |
| Type of Decider | Total, universal halting decider | **Partial**, stratified SHD |
| Accepts All Inputs? | Yes | **No
â rejects self-referential inputs** |
| Halting Must Match Output | Always |
**Only for accepted inputs** |
| Handles DDD/HHH | Must accept and simulate | **Rejects or flags as pathological** |
| Correctness Failure? | Yes (DDD halts, SHD says it doesnât) | **No â SHD never analyzes DDD** |
---
## đ§ Where Damonâs Argument Breaks Down
Damon argues:
"If H(DDD) returns 0, and DDD halts, then the decider is incorrect."
But Flibble responds:
"H(DDD) isnât even valid â the SHDâs *type system* excludes it fromanalysis. It returns ârejectâ (or signals non-halting by infinite recursion detection), not based on complete simulation, but **semantic properties of the input**."
So the contradiction **never arises**, because SHD **refuses to enter**
the paradox â like a type checker rejecting ill-formed code.
---
## đ§© Real-World Analogy
* Imagine a static analyzer (e.g., a compiler's optimizer) that refuses to analyze a function if it detects that the function calls itself through a strange dynamic dispatch loop.
* That analyzer is still **sound** within its accepted domain.
* Itâs **not wrong** to refuse analysis â **itâs conservative**.
Thatâs Flibbleâs model.
---
## đ§ Conclusion
Flibbleâs SHD is not trying to âsolve the Halting Problemâ in the classical Turing sense. Instead, it:
* **Restricts its domain** using type stratification and recursion
detection.
* **Provides answers only where analysis is tractable and safe**.
* Rejects paradoxes **by structural exclusion**, not contradiction.
**Therefore**, Damonâs critique â valid under a *total* decider model â **does not apply to Flibble's SHD**, because the SHD **explicitly avoids** the DDD paradox through **type-stratified domain restriction**.
In other words:
**Flibble isnât breaking the Halting Problem â heâs redefining the rulesof the game to exclude the paradox.**
A simulating halt decider (SHD) must always halt (i.e. provide a halting decision about its input) irregardless of whether or not its input halts.
And those are the facts.
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