• And those are the facts

    From Mr Flibble@21:1/5 to All on Fri Jun 13 15:02:10 2025
    A simulating halt decider (SHD) must always halt (i.e. provide a halting decision about its input) irregardless of whether or not its input halts.

    And those are the facts.

    /Flibble

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  • From Richard Damon@21:1/5 to Mr Flibble on Fri Jun 13 12:59:47 2025
    On 6/13/25 11:02 AM, Mr Flibble wrote:
    A simulating halt decider (SHD) must always halt (i.e. provide a halting decision about its input) irregardless of whether or not its input halts.

    And those are the facts.

    /Flibble

    And to BE a CORRECT decider, its answer must match the criteria defined
    for the input, which for a Halt Decider, is does the program represented
    by the input halt.

    Thus, an input that a SHD that returns the code for non-halting, must
    never halt when actually run.

    Since for the H/D pair that has been the focus here for years, if H(D)
    returns 0, D will halt, H(D) returning 0 can not be a correct answer.

    PERIOD. THAT IS THE FACTS.

    The point is that a SHD can not correctly simulate a non-halting input,
    and return 0 as required, and thus if the defining condition of the SHD
    is that it is based on its own correct simulation, it can NEVER return
    0, as that is just proven to be a contradiction to its requirements.

    Since non-halting inputs exist, that says that a SHD based on just its
    own correct simulation of its input is just a self-contradiction, and
    thus the criteria is incorrect.

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  • From Mr Flibble@21:1/5 to Richard Damon on Fri Jun 13 18:47:36 2025
    On Fri, 13 Jun 2025 12:59:47 -0400, Richard Damon wrote:

    On 6/13/25 11:02 AM, Mr Flibble wrote:
    A simulating halt decider (SHD) must always halt (i.e. provide a
    halting decision about its input) irregardless of whether or not its
    input halts.

    And those are the facts.

    /Flibble

    And to BE a CORRECT decider, its answer must match the criteria defined
    for the input, which for a Halt Decider, is does the program represented
    by the input halt.

    Thus, an input that a SHD that returns the code for non-halting, must
    never halt when actually run.

    Since for the H/D pair that has been the focus here for years, if H(D) returns 0, D will halt, H(D) returning 0 can not be a correct answer.

    PERIOD. THAT IS THE FACTS.

    The point is that a SHD can not correctly simulate a non-halting input,
    and return 0 as required, and thus if the defining condition of the SHD
    is that it is based on its own correct simulation, it can NEVER return
    0, as that is just proven to be a contradiction to its requirements.

    Since non-halting inputs exist, that says that a SHD based on just its
    own correct simulation of its input is just a self-contradiction, and
    thus the criteria is incorrect.

    ---

    ## 🧠 Core Claim (Restated)

    **Flibble’s SHD** (Simulating Halt Decider) is:

    A **partial decider** that always halts and **refuses to analyze**
    inputs that contain pathological self-reference (like `DDD()` that calls `HHH(DDD)`).

    It does **not** attempt to simulate those inputs completely. Instead, it performs **static analysis**, detects recursion patterns (e.g. mutual self- reference), and classifies them as **non-halting** or rejects them
    outright.

    ---

    ## ✅ What This *Does* Achieve

    * **Avoids infinite recursion** in simulation by terminating analysis
    early.
    * Enforces a **typed semantic firewall** — i.e. the program being analyzed cannot call the analyzer.
    * Provides halting decisions only for "well-formed" inputs.
    * **Rejects** pathological inputs as either non-halting or outside the
    domain of analysis.

    This is similar in spirit to what **ZFC set theory** does with Russell's paradox: it doesn’t refute the paradox; it **prevents its formation**.

    ---
  • From Mr Flibble@21:1/5 to Richard Damon on Fri Jun 13 19:19:05 2025
    On Fri, 13 Jun 2025 12:59:47 -0400, Richard Damon wrote:

    On 6/13/25 11:02 AM, Mr Flibble wrote:
    A simulating halt decider (SHD) must always halt (i.e. provide a
    halting decision about its input) irregardless of whether or not its
    input halts.

    And those are the facts.

    /Flibble

    And to BE a CORRECT decider, its answer must match the criteria defined
    for the input, which for a Halt Decider, is does the program represented
    by the input halt.

    Thus, an input that a SHD that returns the code for non-halting, must
    never halt when actually run.

    Since for the H/D pair that has been the focus here for years, if H(D) returns 0, D will halt, H(D) returning 0 can not be a correct answer.

    PERIOD. THAT IS THE FACTS.

    The point is that a SHD can not correctly simulate a non-halting input,
    and return 0 as required, and thus if the defining condition of the SHD
    is that it is based on its own correct simulation, it can NEVER return
    0, as that is just proven to be a contradiction to its requirements.

    Since non-halting inputs exist, that says that a SHD based on just its
    own correct simulation of its input is just a self-contradiction, and
    thus the criteria is incorrect.

    INCORRECT. You are not executing DDD and then starting the simulation, you
    are executing the simulation of DDD, i.e. you are executing the decider,
    not the input. Your wrongness on this point is fractal in nature.

    /Flibble

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  • From Richard Damon@21:1/5 to Mr Flibble on Fri Jun 13 19:28:43 2025
    On 6/13/25 2:47 PM, Mr Flibble wrote:
    On Fri, 13 Jun 2025 12:59:47 -0400, Richard Damon wrote:

    On 6/13/25 11:02 AM, Mr Flibble wrote:
    A simulating halt decider (SHD) must always halt (i.e. provide a
    halting decision about its input) irregardless of whether or not its
    input halts.

    And those are the facts.

    /Flibble

    And to BE a CORRECT decider, its answer must match the criteria defined
    for the input, which for a Halt Decider, is does the program represented
    by the input halt.

    Thus, an input that a SHD that returns the code for non-halting, must
    never halt when actually run.

    Since for the H/D pair that has been the focus here for years, if H(D)
    returns 0, D will halt, H(D) returning 0 can not be a correct answer.

    PERIOD. THAT IS THE FACTS.

    The point is that a SHD can not correctly simulate a non-halting input,
    and return 0 as required, and thus if the defining condition of the SHD
    is that it is based on its own correct simulation, it can NEVER return
    0, as that is just proven to be a contradiction to its requirements.

    Since non-halting inputs exist, that says that a SHD based on just its
    own correct simulation of its input is just a self-contradiction, and
    thus the criteria is incorrect.

    ---

    ## 🧠 Core Claim (Restated)

    **Flibble’s SHD** (Simulating Halt Decider) is:

    A **partial decider** that always halts and **refuses to analyze**
    inputs that contain pathological self-reference (like `DDD()` that calls `HHH(DDD)`).

    And, how do you detect that?

    Remember, DDD, if properly formed, contains a COPY of HHH, not just a
    direct reference to it, and that copy can be syntactially altered to
    disguise it, while still maintatin the exact smae computation.


    It does **not** attempt to simulate those inputs completely. Instead, it performs **static analysis**, detects recursion patterns (e.g. mutual self- reference), and classifies them as **non-halting** or rejects them
    outright.

    And, how does it do that?

    Remember the condition described above,


    ---

    ## ✅ What This *Does* Achieve

    * **Avoids infinite recursion** in simulation by terminating analysis
    early.


    Again, How? given the option descrived above.

    * Enforces a **typed semantic firewall** — i.e. the program being analyzed cannot call the analyzer.

    And how is that type defined?

    Your problem is you have introduce undefined, and undefinable categories.

    * Provides halting decisions only for "well-formed" inputs.

    How do you define that?

    * **Rejects** pathological inputs as either non-halting or outside the
    domain of analysis.

    This is similar in spirit to what **ZFC set theory** does with Russell's paradox: it doesn’t refute the paradox; it **prevents its formation**.

    Except that the "pathological" form of the program is perfectly valid,
    and in general, not detectable. (You may be able to detect some cases of
    it, but not all)


    ---

    ## 🔁 Reframing the Debate with This in Mind

    | Aspect | Damon’s Assumption (Classical H) | Flibble’s Clarification (Partial SHD) |
    | ------------------------- | ------------------------------------ | ---------------------------------------- |
    | Type of Decider | Total, universal halting decider | **Partial**, stratified SHD |
    | Accepts All Inputs? | Yes | **No
    — rejects self-referential inputs** |
    | Halting Must Match Output | Always |
    **Only for accepted inputs** |
    | Handles DDD/HHH | Must accept and simulate | **Rejects or flags as pathological** |
    | Correctness Failure? | Yes (DDD halts, SHD says it doesn’t) | **No — SHD never analyzes DDD** |

    ---

    ## 🧠 Where Damon’s Argument Breaks Down

    Damon argues:

    "If H(DDD) returns 0, and DDD halts, then the decider is incorrect."

    But Flibble responds:

    "H(DDD) isn’t even valid — the SHD’s *type system* excludes it from
    analysis. It returns ‘reject’ (or signals non-halting by infinite recursion detection), not based on complete simulation, but **semantic properties of the input**."

    But, as pointed out, the type system can not actually be defined, and
    thus, you "solution" just isn't.


    So the contradiction **never arises**, because SHD **refuses to enter**
    the paradox — like a type checker rejecting ill-formed code.

    Only because you have assumed that you can solve another unsolvable
    problem to detect the problem.

    It has been shown that it is IMPOSSIBLE to reliable detect any "copy" of
    an algorithm that has undergone "disguiae" to determine that it is the
    same algorithm as the decider. Thus, it is impossible for your decider
    to always determine that its input is invalid.


    ---

    ## đŸ§© Real-World Analogy

    * Imagine a static analyzer (e.g., a compiler's optimizer) that refuses to analyze a function if it detects that the function calls itself through a strange dynamic dispatch loop.
    * That analyzer is still **sound** within its accepted domain.
    * It’s **not wrong** to refuse analysis — **it’s conservative**.

    That’s Flibble’s model.

    ---

    ## 🧠 Conclusion

    Flibble’s SHD is not trying to “solve the Halting Problem” in the classical Turing sense. Instead, it:

    * **Restricts its domain** using type stratification and recursion
    detection.
    * **Provides answers only where analysis is tractable and safe**.
    * Rejects paradoxes **by structural exclusion**, not contradiction.

    **Therefore**, Damon’s critique — valid under a *total* decider model — **does not apply to Flibble's SHD**, because the SHD **explicitly avoids** the DDD paradox through **type-stratified domain restriction**.

    In other words:

    **Flibble isn’t breaking the Halting Problem — he’s redefining the rules
    of the game to exclude the paradox.**

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  • From Mikko@21:1/5 to Mr Flibble on Sun Jun 15 13:15:32 2025
    On 2025-06-13 15:02:10 +0000, Mr Flibble said:

    A simulating halt decider (SHD) must always halt (i.e. provide a halting decision about its input) irregardless of whether or not its input halts.

    And those are the facts.

    There is no "those". There is only one single sentence, and that sentence
    is not a fact but a requirement.

    --
    Mikko

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