So are you the Quora guy?
I will ask you this 10,000 times until you answer.
On 8/12/2025 1:42 PM, Mr Flibble wrote:
Flaw In Olcott's Thinking
Even if we assume that Olcott's HHH(DD) result of non-halting due to the
albeit "aborted" infinite regress is correct it doesn't help Olcott as
DD() will still do the opposite (halt) proving that HHH is not a halt
decider and confirming the validity of the Halting Problem proofs.
/Flibble
Yes it does because non-inputs such as the
directly executed DD() have never been in
the domain of any halt decider.
On 8/12/2025 2:27 PM, dbush wrote:
On 8/12/2025 3:23 PM, olcott wrote:
On 8/12/2025 2:15 PM, dbush wrote:
On 8/12/2025 3:01 PM, olcott wrote:Except in the case where DD correctly simulated by HHH
On 8/12/2025 1:56 PM, dbush wrote:
On 8/12/2025 2:48 PM, olcott wrote:This point has already been fully addressed.
On 8/12/2025 1:42 PM, Mr Flibble wrote:
Flaw In Olcott's Thinking
Even if we assume that Olcott's HHH(DD) result of non-halting
due to the
albeit "aborted" infinite regress is correct it doesn't help
Olcott as
DD() will still do the opposite (halt) proving that HHH is not a >>>>>>>> halt
decider and confirming the validity of the Halting Problem proofs. >>>>>>>>
/Flibble
Yes it does because non-inputs such as the
directly executed DD() have never been in
the domain of any halt decider.
Just like Turing machines can't do arithmetic
Then you agree that Turing machines can take a description of an
algorithm to decide on the algorithm just like Turing machines can
take a description of a number to decide on a number, and therefore
Turing machines are in the domain of Turing machines via a description. >>>
specifies different behavior than DD().
But algorithm HHH doesn't do a correct simulation of algorithm DD, so
that case doesn't exist.
Only because your are using a definition of
correct simulation that requires stupidly
disagreeing with the semantics of the x86 language.
So are you the Quora guy?
I will ask you this 10,000 times until you answer.
On 8/12/2025 3:28 PM, dbush wrote:
On 8/12/2025 4:13 PM, olcott wrote:
On 8/12/2025 2:27 PM, dbush wrote:
On 8/12/2025 3:23 PM, olcott wrote:
On 8/12/2025 2:15 PM, dbush wrote:
On 8/12/2025 3:01 PM, olcott wrote:
On 8/12/2025 1:56 PM, dbush wrote:
On 8/12/2025 2:48 PM, olcott wrote:This point has already been fully addressed.
On 8/12/2025 1:42 PM, Mr Flibble wrote:
Flaw In Olcott's Thinking
Even if we assume that Olcott's HHH(DD) result of non-halting >>>>>>>>>> due to the
albeit "aborted" infinite regress is correct it doesn't help >>>>>>>>>> Olcott as
DD() will still do the opposite (halt) proving that HHH is not >>>>>>>>>> a halt
decider and confirming the validity of the Halting Problem >>>>>>>>>> proofs.
/Flibble
Yes it does because non-inputs such as the
directly executed DD() have never been in
the domain of any halt decider.
Just like Turing machines can't do arithmetic
Then you agree that Turing machines can take a description of an
algorithm to decide on the algorithm just like Turing machines can >>>>>> take a description of a number to decide on a number, and
therefore Turing machines are in the domain of Turing machines via >>>>>> a description.
Except in the case where DD correctly simulated by HHH
specifies different behavior than DD().
But algorithm HHH doesn't do a correct simulation of algorithm DD,
so that case doesn't exist.
Only because your are using a definition of
correct simulation that requires stupidly
disagreeing with the semantics of the x86 language.
UTM by definition simulates according to the semantics of the x86
language.
An aborted simulation violates the semantics of the x86 language.
Only if you are trying to simulate a non-terminating
input to its non-existent conclusion otherwise a
correct simulation of N instructions *IS* a
correct simulation of N instructions.
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