• Improved version: New proof of dark numbers

    From WM@21:1/5 to All on Mon May 12 11:27:28 2025
    New proof of dark numbers by means of the thinned out harmonic series

    Wolfgang Mückenheim
    Technische Hochschule Augsburg
    wolfgang.mueckenheim@tha.de


    Abstract: It is shown by the intersection of the complements of all
    Kempner series belonging to definable natural numbers that not all
    natural numbers can be defined. We call them dark.


    1. Dark Numbers

    Not all numbers can be chosen, expressed, and communicated as
    individuals such that the receiver knows what the sender has meant. We
    call those numbers dark numbers. Much evidence has been collected and
    discussed [1]. But in the following we will present the shortest proof
    of their existence. Of course the facilities to express numbers depend
    on the environment and the power of the applied system. But this proof
    shows that, independent of the system, infinitely many natural numbers
    will remain dark forever.

    A simple example is provided already by the denominators of the harmonic
    series (1/n)n∈. Whatever attempts are made to express denominators m as large as possible, the sum from 1/1 to 1/m is finite while the remaining
    part of the series diverges.


    2. Kempner Series

    The harmonic series diverges. But as Kempner [2] has shown in 1914,
    deleting all terms containing the digit 9 turns it into a converging
    series, the Kempner series, here abbreviated as K(9). That means that
    the complement C(9) of removed terms

    ,

    all containing the digit 9, carries the divergence alone. All other
    terms can be removed. Same is true when all terms containing the digit 8
    are removed. That means that the complement C(8)

    .

    of the Kempner series K(8) carries the divergence alone. Since here
    those terms containing the digits 9 without digits 8 belong to the
    converging series K(8) we can conclude that the divergence is caused by
    the intersection only, i.e., by all terms containing the digits 8 and 9 simultaneously:


    3. Proof

    But not all terms containing 8 and 9 are needed. We can continue and
    remove all terms containing 1, 2, 3, 4, 5, 6, 7, or 0 in the denominator without changing this result because the ten corresponding Kempner
    series K(0), K(1), ..., K(9) are converging and their complements C(0),
    C(1), ..., C(9) are diverging. But only the intersection of all
    complements carries the divergence. That means that only the terms
    containing all the digits 0 to 9 simultaneously constitute the diverging series.

    But that is not the end! We can remove any natural number k, like 2025,
    and the remaining Kempner series will converge. For proof use base 2026
    where 2025 is a digit. This extends to every defined number, i.e., every
    number k that can be defined, chosen, and communicated such that the
    receiver knows what the sender has meant. When the terms containing k
    are deleted, then the remaining series converges.


    4. Result

    The diverging part of the harmonic series is constituted only by
    intersection of all complements C(k) of Kempner series K(k) of defined
    natural numbers k, i.e., by all the terms containing the digit sequences
    of all defined natural numbers. No defined natural number exists which
    must be left out. Terms which, although being larger than every defined
    number, do not contain all defined digit sequences, for instance not
    Ramsey's number, belong to converging Kempner series and not to the
    diverging series of the intersection of all complements. All infinitely
    many terms containing not the digit 1 or not the digit sequence 2025 or
    not the digit sequence of Ramsey's number can be deleted without
    violating the divergence.

    All Kempner series K(k) of defined, i.e., finite numbers k split off in
    this way are converging and therefore the sum of their always finite
    sums is finite too although it can be very large [3]. The divergence
    however remains. It is carried only by terms which are dark and greater
    than all digit sequences of all defined numbers  we can even say
    greater than all digit sequences of all definable numbers because, when
    larger numbers will be defined in future, they will behave in the same
    way. It is impossible to choose a natural number such that the
    intersection of the complements of all Kempner series of larger numbers
    is finite.

    This is a proof of the huge set of undefinable or dark numbers.


    Literature

    [1] W. Mückenheim: "Evidence for Dark Numbers", ELIVA Press, Chisinau,
    2024, pp. 1-36.
    [2] A. J. Kempner: "A Curious Convergent Series", American Mathematical
    Monthly 21 (2), 1914, pp. 48–50.
    [3] T. Schmelzer, R. Baillie: "Summing a Curious, Slowly Convergent
    Series", American Mathematical Monthly 115 (6), 2008, pp. 525–540.

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