• =?UTF-8?Q?Re=3A_universal_quantification=2C_because_g=E2=A4=A8=28g?= =?

    From Jim Burns@21:1/5 to Ross Finlayson on Wed May 8 14:40:47 2024
    On 5/7/2024 4:22 PM, Ross Finlayson wrote:
    On 05/06/2024 12:36 PM, Ross Finlayson wrote:
    On 05/05/2024 03:02 PM, Jim Burns wrote:

    I think that your wished.for supplements of
    standard.issue quantifiers
    can be defined given
    standard.issue quantifiers.

    For my wish,
    I would like everyone to be clear on what
    standard.issue quantifiers and variables
    mean.

    I think that,
    way off in that glorious future,
    both you and I will be able to be
    satisfactorily understood.

    And what more could there be
    to wish for?

    Well, one might aver that extra-ordinary
    universal quantifiers are merely syntactic sugar,
    yet there's that in the low- and high- orders,
    or the first and final, that what they would
    reflect of the _effects_ of quantification,
    something like

    for-any A?
    for-each A+
    for-every A*
    for-all A$

    My guess is that 'A' is the ASCIIfication of '∀'
    Thus
    for-any ∀?
    for-each ∀+
    for-every ∀*
    for-all ∀$

    Please use each of ∀? ∀+ ∀* ∀$ in a sentence.


    I am familiar with wildcard characters in
    their programming.language context. In that context,
    they look to me more like variables ranging over
    standard.issue.all[1] of a set of characters or
    a set of sequences of characters.

    Maybe if you used ∀? ∀+ ∀* ∀$
    I would see better what you mean.


    [1]
    | ∀x:B(x) ⇒ B(t)
    | ∀x:(B⇒C(x)) ⇒ (B⇒∀x:C(x))
    | B(x) ⊢ ∀x:B(x)
    | ∃x:B(x) ⇔ ¬∀x:¬B(x)

    that it is so that the sputniks or extras
    of the quantification in the extra-ordinary,
    have that a quantifier disambiguation:
    is in the syntax.

    Then for the rest of it, like our discussions
    on continuous domains and continuous topologies,
    i.e. the topology that's initial and final itself,
    then these line-reals field-reals signal-reals,
    about the integer continuum linear continuum
    long-line continuum, ubiquitous ordinals and
    extra-ordinary theory, is that these are objects
    of the universe of mathematics in the
    Hilbert's Infinite Living Museum, of Mathematics.

    When considering someone like Paul do Bois-Reymond,
    who came up with the diagonal argument and the long-line,
    and Mirimanoff, who came up with the axiom of regularity
    and also the extra-ordinary, and for example Peano,
    with his integers and infinitesimals, then one may well
    aver that today's standard is a tenuous sort of course,
    that is much more fully enriched by the first sort of
    nonstandard function like the Dirac Delta, then into
    the greater realm of the superclassical law(s) of large
    numbers, and more replete three definitions of
    continuous domains, and the Cantor space(s).

    That's what I'm talking about.

    I think that you are over.estimating
    how clear you've been.

    I don't see how standard.issue.quantifiers are
    enriched by the examples you give.
    Standard.issue quantifiers are already rich enough
    to describe them, so, huh?


    I have had a bit of fun here in sci.math
    brewing up non.standard notation for
    non.standard quantifiers, among other things.

    My non.standard notations are abbreviations for
    expressions with perfectly standard quantification.
    For example,
    the ordinals are well.ordered.
    If exists any γ: B(γ)
    then, exists first β: B(β)
    ∃γ:B(γ) ⇒ ∃₁β:B(β)

    That's an abbreviation.
    ∃₁β:B(β) ⇔
    ∃β:(B(β) ∧ ¬∃α<β:B(α))

    I am fond of abbreviating.
    But all the interesting stuff is found
    as a consequence of the disabbreviated forms.
    I once spent an entire course studying
    ∫ᵟᶿω = ∫ᶿdω

    the generalized Stokes theorem https://en.wikipedia.org/wiki/Generalized_Stokes_theorem

    It was a very full course.
    A lot is crammed into ∫ᵟᶿω = ∫ᶿdω

    Are ∀? ∀+ ∀* ∀$ abbreviations of
    standard.issue.quantified expressions?

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Wed May 8 17:14:42 2024
    On 5/8/2024 4:20 PM, Ross Finlayson wrote:
    On 05/08/2024 11:40 AM, Jim Burns wrote:

    My guess is that 'A' is the ASCIIfication of '∀'
    Thus
    for-any ∀?
    for-each ∀+
    for-every ∀*
    for-all ∀$

    Please use each of ∀? ∀+ ∀* ∀$ in a sentence.

    If you don't want to use ∀? ∀+ ∀* ∀$ in a sentence,
    that's certainly your choice to make.

    It's not a choice which encourages
    efforts to understand you.

    https://en.wikipedia.org/wiki/Fran%C3%A7ois_Vi%C3%A8te

    François Viète, Seigneur de la Bigotière
    (Latin: Franciscus Vieta; 1540 – 23 February 1603)

    | In his dedication of the Isagoge to
    | Catherine de Parthenay, Viète wrote:
    |
    | "These things which are new are wont in the beginning
    | to be set forth rudely and formlessly and must then
    | be polished and perfected in succeeding centuries.
    | Behold, the art which I present is new,
    | but in truth so old,
    | so spoiled and defiled by the barbarians,
    | that I considered it necessary,
    | in order to introduce an entirely new form into it,
    | to think out and publish a new vocabulary,
    | having gotten rid of all its pseudo-technical terms..."

    Consider
    | ∀x:B(x) ⇒ B(t)
    | ∀x:(B⇒C(x)) ⇒ (B⇒∀x:C(x))
    | B(x) ⊢ ∀x:B(x)
    | ∃x:B(x) ⇔ ¬∀x:¬B(x)

    Is it possible that
    several centuries of polishing and perfecting
    have given us, in 2024, something which
    François Viète had only set out in search of?

    I am not a giant.
    However, I can stand on giants' shoulders.
    Since I can, why shouldn't I?

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Thu May 9 18:55:22 2024
    On 5/9/2024 3:56 PM, Ross Finlayson wrote:
    On 05/08/2024 02:14 PM, Jim Burns wrote:

    Consider
    | ∀x:B(x) ⇒ B(t)
    | ∀x:(B⇒C(x)) ⇒ (B⇒∀x:C(x))
    | B(x)  ⊢  ∀x:B(x)
    | ∃x:B(x) ⇔ ¬∀x:¬B(x)

    Is it possible that
    several centuries of polishing and perfecting
    have given us, in 2024, something which
    François Viète had only set out in search of?

    I am not a giant.
    However, I can stand on giants' shoulders.
    Since I can, why shouldn't I?

    Sort of, I suppose.

    | I beseech you, in the bowels of Christ,
    | think it possible that
    | I cannot read your mind.
    |
    <pseudo.Cromwell>

    Like Russell stood on Frege and Peirce,
    and von Neumann and Zermelo stood on Mirimanoff,
    and Cantor stood on duBois-Reymond, well,
    Newton of course is very well-known for
    his quote "I stood on people left and right".

    | If I have seen further
    | it is by standing on ye sholders of Giants.
    |
    <Newton>

    Here it's still "Amicus Plato"

    | Amicus Plato — amicus Aristoteles — magis amica veritas
    <Newton>
    ==
    | Plato is my friend -- Aristotle is my friend --
    | but my best friend is truth.
    |
    <Newton>

    Here it's still "Amicus Plato"
    and it's very old-fashioned,
    yet every few hundred years at least
    it comes back around,
    unsurprisingly much the same.

    So, ye adherents of Russell's retro-thesis and
    semi-Aristotleans of
    the "I say" logical positivist variety,
    too often thinking that
    circa-20'th-century-classical quasi-modal logic
    is either classical or full for DeMorgan:
    can you get down?

    Not.first.false?  Largest.number.ever.

    Compare
    finite sequences of only not.first.false claims
    to
    logarithmic slide rules.

    When used correctly,
    they both give what they're advertised to give.

    Doubts that they give that,
    to the extent that there are doubts that they give that,
    originate from it being less.than.immediately.obvious
    that they give what they're advertised to give.

    But they do give that,
    and it can be shown that they give that,
    even if it is challenge and more.than.a.challenge
    to _immediately_ show that they give that.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Fri May 10 06:59:36 2024
    On 5/9/2024 9:45 PM, Ross Finlayson wrote:
    On 05/09/2024 03:55 PM, Jim Burns wrote:
    On 5/9/2024 3:56 PM, Ross Finlayson wrote:
    On 05/08/2024 02:14 PM, Jim Burns wrote:

    Consider
    | ∀x:B(x) ⇒ B(t)
    | ∀x:(B⇒C(x)) ⇒ (B⇒∀x:C(x))
    | B(x)  ⊢  ∀x:B(x)
    | ∃x:B(x) ⇔ ¬∀x:¬B(x)

    Is it possible that
    several centuries of polishing and perfecting
    have given us, in 2024, something which
    François Viète had only set out in search of?

    I am not a giant.
    However, I can stand on giants' shoulders.
    Since I can, why shouldn't I?

    Sort of, I suppose.

    | I beseech you, in the bowels of Christ,
    | think it possible that
    | I cannot read your mind.
    |
    <pseudo.Cromwell>

    Like Russell stood on Frege and Peirce,
    and von Neumann and Zermelo stood on Mirimanoff,
    and Cantor stood on duBois-Reymond, well,
    Newton of course is very well-known for
    his quote "I stood on people left and right".

    | If I have seen further
    | it is by standing on ye sholders of Giants.
    |
    <Newton>

    Here it's still "Amicus Plato"

    | Amicus Plato — amicus Aristoteles — magis amica veritas
    <Newton>
    ==
    | Plato is my friend -- Aristotle is my friend --
    | but my best friend is truth.
    |
    <Newton>

    Here it's still "Amicus Plato"
    and it's very old-fashioned,
    yet every few hundred years at least
    it comes back around,
    unsurprisingly much the same.

    So, ye adherents of Russell's retro-thesis and
    semi-Aristotleans of
    the "I say" logical positivist variety,
    too often thinking that
    circa-20'th-century-classical quasi-modal logic
    is either classical or full for DeMorgan:
    can you get down?

    Not.first.false?  Largest.number.ever.

    Compare
    finite sequences of only not.first.false claims
    to
    logarithmic slide rules.

    When used correctly,
    they both give what they're advertised to give.

    Doubts that they give that,
    to the extent that there are doubts that they give that,
    originate from it being less.than.immediately.obvious
    that they give what they're advertised to give.

    But they do give that,
    and it can be shown that they give that,
    even if it is challenge and more.than.a.challenge
    to _immediately_ show that they give that.

    Ah, good sir, it's certainly to be appreciated rising
    to a higher level of rhetoric.

    It seems to be a distinctive part of your style
    to remove as many clues to what you mean as you can.
    Who is appreciating?
    Who or what is rising?

    Thanks, I've heard that one before. Here it's
    also "Amicus Plato, fini".

    ?== "Dear Plato, finish it"

    What would you intend to be conveyed by that, here?

    Please don't see my yet not writing terms as for
    SX a set and #X an ordinal, while also SX a usual
    notation for an ordinal in succession, with regards
    to counting, and numbering, where it is so in some
    theory that PX, the powerset of X, is, SX.

    Are you still talking about quantifiers, here?

    As well, please don't see that as a lack of cooperation,
    for all the times in all the threads whereas after a
    large amount of my proper presentation of correct
    reasoning, that you've balked and clammed up,

    I doubt that I can haul from my memory
    every instance in which I've balked and clammed up,
    but I can haul a fair sample.

    Broadly speaking,
    when I have balked and clammed up,
    I have failed at using as an explanation
    that which you seem to have intended for me
    to use as an explanation.

    I have, at times, requested help from you,
    such as your using ∀? ∀+ ∀* ∀$ in sentences,
    but you seem to be unable to see these requests,
    and I have made them less and less often.

    I have a few different explanations for
    your responses being how they are.
    The one you'd dislike least, I think, is that
    your intended readers are a group of people
    which does not include me, Jim Burns.
    The upshot of that and also the other explanations
    is that I'll not be getting any farther toward
    understanding what you're saying.
    Therefore, I balk and clam up.

    as what even for a fair-weather formalist and
    dreamy intuitionist, must eventually see that
    flowing the threads, or arguments as it were,
    rhetorically, forensically, here is that I've gotten
    around to it.

    So, this idea of a proper distinguished syntax for
    universal quantifiers as with regards to how they
    apply to the various relations, where in a given theory
    we may aver that all predicates are relations and as
    for vice-versa, that relations are primary, then these
    schemes, of quantification, become higher order,
    if only an order or so, than the usual syntax where
    terms are primary, that it so effects to reflect the
    relations as primary, why it is so that these refined
    universal quantifiers, are elements of a syntax,
    irreducibly.

    Formally, ....



    Hundreds and hundreds of threads on sci.math and sci.logic,
    many last words, ....



    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Fri May 10 18:26:29 2024
    On 5/10/2024 4:12 PM, Ross Finlayson wrote:
    On 05/10/2024 03:59 AM, Jim Burns wrote:

    [...]

    I'd like to suggest a reading from
    Dehaene's "The Number Sense",
    in Chapter 9 "Of Neurons and Numbers",
    in the section
    "When Intuition Outruns Axioms".

    I found a copy online from
    the International Cognition and Culture Institute,
    and about page 238.

    He explains that there _are_
    non-standard models of integers.

    Is "When Intuition Outruns Axioms" concerned with
    other.than.standard.issue quantifiers?
    [1]

    If so,
    since you are currently holding the talking.stick,
    you could use the opportunity to expound on
    what Dehaene has to say.

    Maybe I should clarify:

    I don't say that there aren't non.standard objects.
    That's not the same as saying that
    there aren't non.standard quantifiers.

    I also don't say that there aren't
    non.standard quantifiers.
    There might not be.
    Quantifiers are live near the roots of our logic.
    There might be.
    Mathematicians are smart.

    What I say is
    I don't know yet what sort of
    non.standard.quantification scheme
    you introduced at your "universal quantification"
    post.

    If you wish I had more to say about your posts
    (a big IF, not everyone does)
    helping me to understand your posts seems like
    an effective strategy for bringing that about.

    Just saying.

    Again, what correspondence of yours I see,
    which is any in response to me, I've replied.

    If you have used ∀? ∀+ ∀* ∀$ in sentences,
    I have overlooked them.

    Surely, it would only be a very small favor to me
    to repeat those sentences.
    By doing so, you would increase the chances
    of me NOT balking and clamming up.

    Could you please do so again?

    [1]
    By other.than.standard.issue quantifiers, I mean
    other than those such that:
    | ∀x:B(x) ⇒ B(t)
    | ∀x:(B⇒C(x)) ⇒ (B⇒∀x:C(x))
    | B(x) ⊢ ∀x:B(x)
    | ∃x:B(x) ⇔ ¬∀x:¬B(x)

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Sat May 11 04:18:32 2024
    On 5/10/2024 8:17 PM, Ross Finlayson wrote:
    On 05/10/2024 03:26 PM, Jim Burns wrote:
    On 5/10/2024 4:12 PM, Ross Finlayson wrote:
    On 05/10/2024 03:59 AM, Jim Burns wrote:

    [...]

    I'd like to suggest a reading from
    Dehaene's "The Number Sense",
    in Chapter 9 "Of Neurons and Numbers",
    in the section
    "When Intuition Outruns Axioms".

    I found a copy online from
    the International Cognition and Culture Institute,
    and about page 238.

    He explains that there _are_
    non-standard models of integers.

    Is "When Intuition Outruns Axioms" concerned with
    other.than.standard.issue quantifiers?
    [1]

    If so,
    since you are currently holding the talking.stick,
    you could use the opportunity to expound on
    what Dehaene has to say.

    Maybe I should clarify:

    I don't say that there aren't non.standard objects.
    That's not the same as saying that
    there aren't non.standard quantifiers.

    I also don't say that there aren't
    non.standard quantifiers.
    There might not be.
    Quantifiers are live near the roots of our logic.
    There might be.
    Mathematicians are smart.

    What I say is
    I don't know yet what sort of
    non.standard.quantification scheme
    you introduced at your "universal quantification"
    post.

    If you wish I had more to say about your posts
    (a big IF, not everyone does)
    helping me to understand your posts seems like
    an effective strategy for bringing that about.

    Just saying.

    Again, what correspondence of yours I see,
    which is any in response to me, I've replied.

    If you have used ∀? ∀+ ∀* ∀$ in sentences,
    I have overlooked them.

    Surely, it would only be a very small favor to me
    to repeat those sentences.
    By doing so, you would increase the chances
    of me NOT balking and clamming up.

    Could you please do so again?

    [1]
    By other.than.standard.issue quantifiers, I mean
    other than those such that:
    | ∀x:B(x) ⇒ B(t)
    | ∀x:(B⇒C(x)) ⇒ (B⇒∀x:C(x))
    | B(x)  ⊢  ∀x:B(x)
    | ∃x:B(x) ⇔ ¬∀x:¬B(x)





    Well, first of all, it's after pondering that there
    is quantifier comprehension artifacts of the extra sort,
    as of a set of all sets, order type of ordinals, a universe,
    set of sets that don't contain themself, sets that contain
    themselves, and so on.

    Then, English affords "any, "each, "every, "all".

    The -any means for example that "it's always a fragment".
    So in this sense the usual universal quantifier is for-each.

    Then, for-each, means usual comprehension, as if an enumeration,
    or a choice function, each.

    Then, for-every, means as a sort of comprehension, where it
    so establishes itself again, any differently than -each,
    when -each and -every implies both none missing and all gained.

    Then, "for-all", sort of is for that what is so "for-each"
    and "for-every" is so, "for-all", as for the multitude as
    for the individual.

    Then, I sort of ran out of words, "any", "each", "every", "all",
    then that seems their sort of ordering, about comprehension,
    in quantification, in the universals, of each particular.

    About sums it up, ...." -- Monday

    Date: Tue, 7 May 2024 15:16:27 -0400.
    Are there differences in syntax between
    'for.any' 'for.each' 'for.every' 'for.all' ?

    If your answer, if it ever comes, is "no",
    then I do not know what is meant by
    quantifier comprehension artifacts of the extra sort
    That looks to me like
    quantifiers used in several domains, full stop.

    If your answer, if it ever comes, is "yes",
    then I would like to know different how.
    Syntax is pretty intimately entangled with semantics.

    If your answer never comes,
    why don't I just balk and clam up, because,
    without it, I don't have much to say.


    I'd like to think of my internet production as
    carefully.curated stretches of silence
    artfully.punctuated with non.silences,
    something in the direction of John Cage's 4'33"

    I try to indicate not.having something to say
    by not.saying it.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Sat May 11 10:40:08 2024
    On 5/11/2024 9:38 AM, Ross Finlayson wrote:
    On 05/11/2024 01:18 AM, Jim Burns wrote:

    Date: Tue, 7 May 2024 15:16:27 -0400.
    Are there differences in syntax between
    'for.any' 'for.each' 'for.every' 'for.all' ?

    If your answer, if it ever comes, is "no",
    then I do not know what is meant by
    quantifier comprehension artifacts of the extra sort
    That looks to me like
    quantifiers used in several domains, full stop.

    If your answer, if it ever comes, is "yes",
    then I would like to know different how.
    Syntax is pretty intimately entangled with semantics.

    If your answer never comes,
    why don't I just balk and clam up, because,
    without it, I don't have much to say.

    Now of course such a notion or idea or concept or
    pensee or thought didn't just erupt fully-formed,
    like Conrad from the tin of corned beef,
    that it starts rather more like 'for-any, or, for-all',
    about things like "for-any well-founded set, it's a set in
    the well-founded universe", then, "for-all well-founded
    or non-well-founded sets, they are sets in the set-theoretic
    universal set".

    Then, it's not necessary to invoke the entire universe of
    sets, the entire domain of discourse that is anything that
    is a set, though is reasonably brief when in a theory with
    only logical sets, logically, sets of sets.

    I.e., it applies as closely to "sets of sets", and the n'th order
    about quantification, and comprehension.


    Let's be clearly understood that I am a formalist,
    if though not a nominalist yet a platonist,
    because mathematics its truths are discovered
    not invented, while our language and terms and
    derivations are as yet technique.

    So, constructivism is regarded as the rulial in
    the standard, and intutionism is that which
    revolves in the abductive inference, as what
    makes for embracing the fuller dialectic.

    Thusly, the "standard" is "our standard",
    while what's of interest in the fuller dialectic
    is the "extra-ordinary" or "super-standard",
    that the "non-standard", must be in these
    classes of classes, yet formalist, and rulial
    again, in the competing regularities, which
    comprise "it", the thing, the universe of the
    mathematical and logical objects, a theory,
    to which we attain, "A Theory", the theory,
    of the things, the theory of every thing.

    So, just saying, there's a greater mathematics
    than "our standard", with "R, standard", and
    modern mathematics as it's usually known,
    a paleo-classical post-modern mathematics,
    which mathematics owes physics for the
    greater context of continuity, convergence,
    and the laws of large numbers.

    I'm a formalist: and in natural language.

    Date: Tue, 7 May 2024 15:16:27 -0400.
    Are there differences in syntax between
    'for.any' 'for.each' 'for.every' 'for.all' ?

    If your answer, if it ever comes, is "no",
    then I do not know what is meant by
    quantifier comprehension artifacts of the extra sort
    That looks to me like
    quantifiers used in several domains, full stop.

    If your answer, if it ever comes, is "yes",
    then I would like to know different how.
    Syntax is pretty intimately entangled with semantics.

    If your answer never comes,
    why don't I just balk and clam up, because,
    without it, I don't have much to say.

    So, it's door number 3.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Sat May 11 15:24:37 2024
    On 5/11/2024 11:47 AM, Ross Finlayson wrote:
    On 05/11/2024 07:40 AM, Jim Burns wrote:

    [...]

    In the logical, the purely logical,
    the syntax "is" the semantics.

    If what makes logic impure is
    to be about something,
    then it would make some sense to say that
    pure logic has no semantics

    ...which leads, by default?
    to syntax being the missing semantics, I guess?

    Sorry, I will not sign your petition.
    Syntax and semantics are more different than
    cabbages and kings.

    It seems to me that
    the purest of ultra.pure logic is actually
    _about_ claims,
    analogous to geometry being _about_ points,
    lines, plane.figures, and so on.

    It is an unbreakable law that
    the sum of the squares of the two shorter sides
    of a right.triangle is equal to
    the square of the third and longest side.

    It is an unbreakable law that
    a finite sequence of only not.first.false claims
    holds only true claims.

    It is an unbreakable law that
    Q preceded by P and P⇒Q is not.first.false.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Sat May 11 19:25:55 2024
    On 5/11/2024 5:44 PM, Ross Finlayson wrote:
    On 05/11/2024 02:05 PM, Ross Finlayson wrote:
    On 05/11/2024 12:24 PM, Jim Burns wrote:

    [...]
    [...]

    It's like two inductive analysts were contradicting
    each other. One says "base case, subsequent
    case, case closed", and the other says "base case,
    subsequent case, case not closed".

    You just pick one?

    Pick the one in a finite sequence of
    only not.first.false claims.
    It is a true claim.


    "Base case, subsequent case" is cisfinite induction.

    Today, elsewhere, I gave an argument ==
    a finite.sequence of only not.first.false.claims
    for cisfinite induction.
    Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how
    Date: Sat, 11 May 2024 14:49:46 -0400

    But there is also transfinite induction, which also
    is in a finite.sequence of only not.first.false claims,
    claims about ordinals instead of naturals.

    The sequence about ordinals is shorter,
    and I don't think this is about the sequences themselves,
    anyway, but about justification by the existence of
    such sequences. I think the shorter will shed more light.


    1.
    Ordinals are well.ordered.
    ∃γ: p(γ) ⟹ ∃β: (p(β) ∧ ¬∃α<β:p(α))

    2.
    Transfinite.induction is true for ordinals
    ∀β: (̅p(β) ⇐ ∀α<β:̅p(α)) ⟹ ∀γ: ̅p(γ)


    (2.) is not.first.false in that sequence
    because
    (2.) is merely a re.written version of (1.)
    ¬H ⟹ ¬C for H ⟹ C
    ∀¬ for ¬∃
    C ⇐ H for ¬(¬C ∧ H)
    ̅p for ¬p


    (1.) is not.first.false in that sequence
    because
    (1.) is not.false (there or anywhere)

    If Q is first.false, then Q is false ==
    If Q is not.false, then Q is not.first.false.

    (1.) "Ordinals are well.ordered" is true
    because _that's what "ordinal" means_

    (1.) (2.) is a finite sequence of
    only not.first.false claims.

    Because (1.) (2.) is finite,
    if (1.) (2.) held a false claim,
    (1.) (2.) would hold a first.false claim.

    (1.) (2.) doesn't hold a first.false claim
    (1.) (2.) doesn't hold a false claim

    (2.) is true.

    Transfinite.induction is true for ordinals
    ∀β: (̅p(β) ⇐ ∀α<β:̅p(α)) ⟹ ∀γ: ̅p(γ)

    It's exactly about "not.ultimately.untrue" that
    describes how there are "inductive impasses"
    that belie their finite inputs.

    Please explain "not.ultimately.untrue" and
    "inductive impasse". I would welcome examples.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Sat May 11 19:47:38 2024
    On 5/11/2024 7:11 PM, Ross Finlayson wrote:
    On 05/11/2024 02:44 PM, Ross Finlayson wrote:
    On 05/11/2024 02:05 PM, Ross Finlayson wrote:
    On 05/11/2024 12:24 PM, Jim Burns wrote:

    [...]
    [...]
    [...]

    The case is that induction goes through,
    an inviolable law you call it:
    does it go all the way through?
    Does it complete?

    It is complete.
    There is no completing.activity,
    so I wouldn't say it completes.

    Compare to right triangles:
    Are all the squares of two shorter sides
    summed to the square of the longest side?

    That's a tricky question to answer because
    there is no summing done.
    That relationship between the sides
    is simply something true about right triangles.

    And it is complete == it is true for each.

    We don't typically ask the tricky question
    about right triangles.
    We ask the tricky question about cisfinite induction
    because we imagine it as a process,
    which we don't for right triangles.

    Cisfinite induction is NOT a process.
    Cisfinite induction is an argument,
    completely correct or completely incorrect.

    See, the contrary inductive analyst just says
    "in case you don't have a deductive argument why
    something is so, induction is so much shifting-sands
    and slippery-slope." He just has "the base case is
    you haven't completed induction, and so is the
    subsequent case, case closed: case not closed".

    When the argument is completed,
    induction is completed.

    ----
    There is something completely different
    which is also called induction.
    The completely.different induction is physics.

    Physics.induction is not unbreakable.
    Physics.induction isn't cisfinite or transfinite induction.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Sun May 12 13:46:15 2024
    On 5/11/2024 9:17 PM, Ross Finlayson wrote:
    On 05/11/2024 04:47 PM, Jim Burns wrote:
    On 5/11/2024 7:11 PM, Ross Finlayson wrote:

    The case is that induction goes through,
    an inviolable law you call it:
    does it go all the way through?
    Does it complete?

    It is complete.
    There is no completing.activity,
    so I wouldn't say it completes.

    Compare to right triangles:
    Are all the squares of two shorter sides
    summed to the square of the longest side?

    That's a tricky question to answer because
    there is no summing done.
    That relationship between the sides
    is simply something true about right triangles.

    And it is complete == it is true for each.

    We don't typically ask the tricky question
    about right triangles.
    We ask the tricky question about cisfinite induction
    because we imagine it as a process,
    which we don't for right triangles.

    Cisfinite induction is NOT a process.
    Cisfinite induction is an argument,
    completely correct or completely incorrect.

    What I recall of the context of the Pythagorean theorem,

    Let's refresh our memories.

    ͨₐ🭢🭕🭞🭜🭘ᵇ = ͨₐ🭢🭕ͩ + ͩₐ🭞🭜🭘ᵇ

    The right triangle 🞃cab is split into
    two right triangles ◥cda ◤adb
    by segment a͞d perpendicular to b͞c

    🞃cab ◥cda ◤adb are _similar_
    [1]
    Corresponding sides have equal ratios.

    ∠acb = ∠dca
    ∟cab = ∟cda
    🞃cab ≚ ◥cda
    c͡b/c͡a = c͡a/c͡d

    ∠cba = ∠abd
    ∟cab = ∟adb
    🞃cab ≚ ◤adb
    c͡b/b͡a = b͡a/d͡b

    c͡b⋅c͡d = c͡a²
    c͡b⋅d͡b = b͡a²
    c͡b⋅(c͡d+d͡b) = c͡b² = c͡a² + b͡a²
    QED

    [1] needs its own proof,
    but that can be done, too.

    What I recall of the context of the Pythagorean theorem,
    was that after algebra already was trigonometry, and
    the definitions of the trigonometric functions, for
    sine and cosine and tangent, about the opposite and
    adjacent and hypotenuse, then as of a right triangle
    with its hypotenuse the radius of a unit circle, that
    the right angle is as with regards to the abscissa
    and ordinates or where the lines drop or slide to
    the x or y axis of the usual X-Y coordinate setting
    of a circle centered at the origin, it was of the
    secondary school's first three years of geometry,
    algebra, and trigonometry, or along those lines.

    So, we computed a bunch of ready things about
    those often with the Pythagorean theorem,
    which is as an addition-formula, mostly about
    30-60-90 triangles, and, isosceles triangles,
    or 45-45-90, then those got used throughout
    precalculus and a couple years of calculus
    or high school.

    I agree that the Pythagorean theorem
    gets used in a lot of different ways.

    How we know that the Pythagorean theorem
    is a fact about each right triangle
    has important similarities to
    how we know that we cisfinitely.induced claims
    are facts about each natural number.

    So anyways one time I see a diagram about
    Pythagorean triples, those being tuples of
    three integers that have a^2 + b^2 = c^2,
    and what they'd done was right triangle,
    then draw a square as of the square alongside
    it, and counting the boxes of the squares of
    a b c it's that the boxes of the squares of a
    and b equals the boxes of the square of c.

    Actually,
    that works in the opposite direction.
    We know that 3:4:5 is a right triangle
    because of the Pythagorean theorem.

    If that's not a proof of the Pythagorean theorem
    and least it's graphically intuitive for some values,
    where of course there are hundreds of known
    proofs of the Pythagorean theorem, since the
    time of Pythagoras as some even have as from
    greater antiquity, then it reminds of things
    like Rodriguez formula, Vieta's formulas,
    Nicomachus' theorem and formulas,
    Pascal triangle and bonomial theorem,
    all what are sorts of addition formulas,
    like an addition formula of the product
    of exponents as the sum of the powers.

    So, that Pythagorean triples exist, and it results
    that the rightness of a triangle with sides length
    the Pythagorean triple can be established without
    invoking the Pythagorean theorem, doesn't so
    much make it so the other way around, from
    induction over Pythagorean triples, without
    showing as how all right triangles are somehow
    as some congruence to what is some Pythagorean
    triple,

    We shouldn't want to show that
    each right triangle has a Pythagorean triple,
    because we know that isn't true.
    Famously, Pythagoras executed one of his disciples
    for proving that the right isosceles triangle 1:1:√̅2
    has no Pythagorean triple.

    of the equivalence class of all the triples
    and all the congruences to triangles with a
    unit length longest side, establishing infinite
    expressions, and closures, of completion,
    to make a case for the Pythagorean theorem
    as via induction from an explication after
    the enumeration of Pythagorean triples,
    which via inspection have a^2+b^2 = c^2,
    as for that it results congruences that
    "go to" any given dimensions of a right
    triangle.

    About the cisfinite and transfinite induction,
    and I know it's not the languages fault that
    there's the associated psychosexual connotation,
    I'm glad you make the point though that
    it just is what it is, and, a case for induction
    more or less needs some reason its tendency,
    to succeed as it were, then that induction
    is given its course, then that the course-of--passage,
    of what the plain old infinite induction, arrives.

    Induction does not arrive,
    unless you are talking about arriving at
    the end of _expressing the argument_

    I.e., it's always "infinite induction", after cause-and-effect,
    with that also being induction or a case, mathematical
    induction, and there can't be any reasonable counterclaims
    or they'd be just as guaranteed as the contradistinct opposite.


    So, it makes for a very strong perceived requirement
    for deductive reasoning _why_ convergence criteria
    exist, besides that "given an infinite expression,
    it's an infinite expression".

    Here then that's most Zeno's about geometric series,
    and then about things like Stirling numbers and of
    course the discussions we've been having over the
    past few months about the convergence and
    the slooowwwly convergent and all this,
    the "scaffolding" of the infinite expressions
    we've been discussing and at length.

    Warm regards



    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Mon May 13 00:11:50 2024
    On 5/12/2024 3:34 PM, Ross Finlayson wrote:
    On 05/12/2024 11:21 AM, Ross Finlayson wrote:
    On 05/12/2024 10:46 AM, Jim Burns wrote:

    [...]

    Geometry's "similar" is often related to
    "congruency, thoroughly",
    where "congruent" means "similar".

    You have confused me.
    I agree that "similar" is related to "similar"
    but I don't see why you tell us this.

    ͨₐ🭢🭕🭞🭜🭘ᵇ = ͨₐ🭢🭕ͩ + ͩₐ🭞🭜🭘ᵇ

    The right triangle 🞃cab is split into
    two right triangles ◥cda ◤adb
    by segment a͞d perpendicular to b͞c

    🞃cab ◥cda ◤adb are _similar_
    [1]
    Corresponding sides have equal ratios.

    Because triangles, here "similar" means
    corresponding sides have equal ratios and
    corresponding angles are equal.

    You can know that a triangle is a right triangle
    if you have the trigonometric functions of its angles,
    here as where it doesn't necessarily require
    the apparatus of Pythagoren theorem proper,
    "its own theory", ....

    Pythagoras says
    ∠cab = 90° ⟹ c͡b² = c͡a² + b͡a²

    That means
    ∠cab = 90° ∨ c͡b² ≠ c͡a² + b͡a²

    One side of that disjunction is true
    for any triangle.
    Thus, we don't need to know it's a right triangle
    in order to know Pythagoras is correct.

    The most usual tools, of classical constructions:
    are: compass and edge.

    If 🞃cab CAN be classically constructed
    then ∠cab = 90° ⟹ c͡b² = c͡a² + b͡a²

    If 🞃cab canNOT be classically constructed
    then ∠cab = 90° ⟹ c͡b² = c͡a² + b͡a²

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Wed May 15 10:10:38 2024
    On 5/14/2024 4:15 PM, Ross Finlayson wrote:

    They're not all quite so strong,
    the many, many examples
    of the balking and clamming,
    the actually quite a few very many,
    though, these are pretty good.

    You don't want to talk about
    what I want to talk about.
    And there's nothing wrong with that.
    Really.

    However, it's just as true
    in the other direction.

    Date: Sat, 11 May 2024 19:47:38 -0400
    Message-ID: <a4700775-be6c-46db-ad41-361eee6a3b67@att.net>
    <JB<RF>>

    The case is that induction goes through,
    an inviolable law you call it:
    does it go all the way through?
    Does it complete?

    It is complete.
    There is no completing.activity,
    so I wouldn't say it completes.

    Compare to right triangles:
    Are all the squares of two shorter sides
    summed to the square of the longest side?

    That's a tricky question to answer because
    there is no summing done.
    That relationship between the sides
    is simply something true about right triangles.

    And it is complete == it is true for each.

    We don't typically ask the tricky question
    about right triangles.
    We ask the tricky question about cisfinite induction
    because we imagine it as a process,
    which we don't for right triangles.

    Cisfinite induction is NOT a process.
    Cisfinite induction is an argument,
    completely correct or completely incorrect.

    </JB<RF>>

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Wed May 15 16:57:49 2024
    On 5/15/2024 3:56 PM, Ross Finlayson wrote:
    On 05/15/2024 07:10 AM, Jim Burns wrote:
    On 5/14/2024 4:15 PM, Ross Finlayson wrote:

    They're not all quite so strong,
    the many, many examples
    of the balking and clamming,
    the actually quite a few very many,
    though, these are pretty good.

    You don't want to talk about
    what I want to talk about.
    And there's nothing wrong with that.
    Really.

    However, it's just as true
    in the other direction.

    Date: Sat, 11 May 2024 19:47:38 -0400
    Message-ID: <a4700775-be6c-46db-ad41-361eee6a3b67@att.net>
    <JB<RF>>

    The case is that induction goes through,
    an inviolable law you call it:
    does it go all the way through?
    Does it complete?

    It is complete.
    There is no completing.activity,
    so I wouldn't say it completes.

    Compare to right triangles:
    Are all the squares of two shorter sides
    summed to the square of the longest side?

    That's a tricky question to answer because
    there is no summing done.
    That relationship between the sides
    is simply something true about right triangles.

    And it is complete == it is true for each.

    We don't typically ask the tricky question
    about right triangles.
    We ask the tricky question about cisfinite induction
    because we imagine it as a process,
    which we don't for right triangles.

    Cisfinite induction is NOT a process.
    Cisfinite induction is an argument,
    completely correct or completely incorrect.

    </JB<RF>>

    You mean "not.ultimately.untrue"?

    I don't know.
    What does "not.ultimately.untrue" mean?


    Is this thing where I ask a question
    and you don't answer
    an instance of my balking and clamming up?

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Thu May 16 12:50:57 2024
    On 5/16/2024 5:03 AM, Ross Finlayson wrote:
    On 05/15/2024 01:57 PM, Jim Burns wrote:
    On 5/15/2024 3:56 PM, Ross Finlayson wrote:
    On 05/15/2024 07:10 AM, Jim Burns wrote:

    [Cisfinite induction] is complete.
    There is no completing.activity,
    so I wouldn't say it completes.

    Cisfinite induction is NOT a process.
    Cisfinite induction is an argument,
    completely correct or completely incorrect.

    You mean "not.ultimately.untrue"?

    I don't know.
    What does "not.ultimately.untrue" mean?

    It's just an introdunce of introduction,
    not contradicted by deduction.

    Thank you for answering my question.

    'introdunce' looks like a typo or a neologism.
    But I get "not contradicted by deduction".

    ----
    _In its correct context_
    complete cisfinite induction
    is NOT contradicted by deduction.

    Outside of its correct context,
    we do not assert complete cisfinite induction.
    ⎛ To be pedantic, some people assert it there.
    ⎝ The technical term for them is "wrong".


    We can say more than that, though.

    _In its correct context_
    DENYING complete cisfinite induction
    IS contradicted by deduction.

    Those who deny its completeness there
    are, as we say, "wrong".

    _In its correct context_
    That is the essential qualification.

    Context provides _true claims_ about
    the objects of cisfinite induction.

    If the context is of the correct type,
    those true claims can be followed by
    only not.first.false claims, bread crumbs
    leading us to the statement of induction.

    Because of the way in which we arrive at
    the statement of induction,
    we know it is a true statement.
    But the way in which we arrive
    must start with the correct context.

    Other things, maybe darkᵂᴹ numbers, who knows?
    which canNOT be followed by
    a finite sequence of
    only not.first.false claims
    leading us to the statement of induction
    are NOT asserted by us to have
    complete cisfinite induction available.

    You mean "not.ultimately.untrue"?

    For complete.cisfinite.induction in correct.context,
    I mean "not.first.false", which I take to be
    stronger than "not.ultimately.untrue".

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Sat May 18 14:16:20 2024
    On 5/18/2024 12:09 PM, Ross Finlayson wrote:
    On 05/16/2024 09:50 AM, Jim Burns wrote:

    [...]

    I think that "correct", in context, is the entire
    context, which is exactly what deductive inference
    contains, explaining when inductive inference either
    must complete, or meets its juxtaposition, with
    regards to any two forces that balance and align
    in symmetry.

    So, what you are claiming is that inductive inference
    is invincibly ignorant,

    I am claiming that inductive inference
    is invincibly modest.
    Post.inference, we only assert claims about
    whatever.it.is we described pre.inference.

    Perhaps that doesn't seem modest,
    because whatever.it.is is infinitely.many,
    but induction holds for infinitely.many cisfinite ordinals
    in the same way that geometry holds for infinitely.many
    right triangles. Completely.

    A given schema for induction has no more correctness,
    in its own vacuum, than any other,

    Induction on the cisfinite ordinals
    ⎛ those countable.back.to.0 after only
    ⎜ those countable.back.to.0
    ⎝ and also 0
    is a theorem.
    Theorems are not optional.

    and when they're put together and don't
    agree, then either they don't, and don't, or
    don't, and do.

    "Not.ultimately.untrue", ....

    Induction on the cisfinite ordinals
    is not.first.false in a finite sequence of
    only not.first.false claims
    which begins "A cisfinite ordinal is ... ".

    One can contrive simple inductive arguments
    that _nothing_ is so.

    An example of such an argument would be clarifying here.

    So, I'd say your definition of "correct", isn't,
    and is simply a declaration of "relative" and "blind".

    No offense meant, of course, it's so that paradoxes
    are to be resolved, not obviated.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Jim Burns@21:1/5 to Ross Finlayson on Sun May 19 13:28:12 2024
    On 5/18/2024 4:11 PM, Ross Finlayson wrote:
    On 05/18/2024 11:16 AM, Jim Burns wrote:
    On 5/18/2024 12:09 PM, Ross Finlayson wrote:

    One can contrive simple inductive arguments
    that _nothing_ is so.

    An example of such an argument
    would be clarifying here.

    Says nothing,
    says nothing,
    says nothing,
    says nothing,
    ....

    See,
    just saying so doesn't make it so,
    something that _goes_ has a _place_ to go.

    Explain to me how that is an inductive argument.

    ----
    Here is an inductive argument for n⁺¹≠n

    BASE CASE.
    ⎛ Background for finite ordinals
    ⎝ k⁺¹≠0

    for k=0
    0⁺¹≠0

    STEP CASE.
    ⎛ Background for finite ordinals
    ⎝ j≠k ⇒ j⁺¹≠k⁺¹

    for j=n⁺¹ k=n
    n⁺¹≠n ⇒ n⁺¹⁺¹≠n⁺¹

    Therefore,
    for each finite ordinal n, n⁺¹≠n
    by induction.

    ----
    In the context of finite ordinals,
    that is complete, in that
    we know by that argument that,
    for each finite ordinal n, n⁺¹≠n


    There exists a fuller argument which
    details _how_ we know that,
    the part which we don't often see,
    because that part is essentially unchanged
    from invocation to invocation of "induction"

    Here is the fuller inductive argument for n⁺¹≠n

    | Assume a finite.ordinal counter.example nₓ
    | nₓ⁺¹=nₓ
    |
    | ⎛ Background for ordinals
    | ⎜ The set of counter.examples
    | ⎝ holds a first or is empty.
    |
    | There is a counter.example nₓ
    | There is a first counter.example n₁
    | n₁⁺¹=n₁
    | k < n₁ ⇒ k⁺¹≠k
    |
    | ⎛ Background for finite.ordinals
    | ⎜ Finite.ordinal n is 0 or
    | ⎜ it can be decremented and
    | ⎝ each before.ordinal can be decremented or is 0
    |
    | finite.ordinal nₓ
    | n₁ < nₓ
    | n₁=0 or n₁ can be decremented.
    |
    | 1.
    | n₁=0
    | 0⁺¹=0
    | BASE CASE: 0⁺¹≠0
    | Contradiction.
    |
    | 2.
    | n₁ can be decremented.
    | n₁⁻¹ < n₁
    | (n₁⁻¹)⁺¹ ≠ n₁⁻¹
    | STEP CASE: n⁺¹≠n ⇒ n⁺¹⁺¹≠n⁺¹
    | n₁⁺¹≠n₁
    | However,
    | n₁⁺¹=n₁
    | Contradiction.
    |
    | Contradiction or contradiction.

    Therefore,
    a finite.ordinal counter.example nₓ not.exists

    For each finite.ordinal n: n⁺¹≠n
    Completely.

    ----
    Suppose we want a proof of some property P(n)
    for the complete domain of finite.ordinals

    We can swap out
    proofs of 0⁺¹≠0 and of n⁺¹≠n ⇒ n⁺¹⁺¹≠n⁺¹
    and swap in
    proofs of P(0) and of P(n) ⇒ P(n⁺¹)
    and we will have a correct proof with
    a necessarily correct conclusion.

    A proof.by.induction is a _general_ form
    into which details can be inserted which
    make it a correct proof of a _particular_ claim
    not unlike a proof.by.contradiction,
    in that respect.

    What we often _call_ a proof.by.induction is
    the details to be swapped into the fuller proof.
    It's the _whole_ proof, seen and unseen,
    which makes the conclusion invincibly complete.

    See,
    just saying so doesn't make it so,
    something that _goes_ has a _place_ to go.

    Yes,
    just saying so doesn't _make_ it so.

    Even
    saying so within
    a finite sequence of only not.first.false claims
    doesn't _make_ it so.

    However,
    that allows us to _know_ that it's so.

    Proof.by.induction is a telescope, not a ray gun.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)