• The doubled interval (0, =?UTF-8?Q?=CF=89=29?=

    From WM@21:1/5 to All on Wed May 29 17:31:30 2024
    Cantor created the sequence of the ordinal numbers by means of his first
    and second generation principle

    0, 1, 2, 3, ..., ω, ω+1, ω+2, ω+3, ..., 2ω, 2ω+1, 2ω+2, 2ω+3, .., 3ω, ... . (9.1)

    In 1884 he exchanged the positions of multiplier and the number to be multiplied with the result

    0, 1, 2, 3, ..., ω, ω+1, ω+2, ω+3, ..., ω*2, ω*2+1, ω*2+2, ω*2+3,
    ω*3, ... . (9.2)

    This is mentioned only in order to avoid confusion. We will stick to his
    second notation (9.2).

    This sequence, except its very first terms, has no relevance for classical mathematics. But it is important for set theory that in actual infinity
    there does nothing fit between ℕ and ω. Likewise before ω2 and
    ω3 there is no empty space. What is the alternative? Only ordinal
    numbers. According to Hilbert we can simply count beyond the infinite by a quite natural and uniquely determined, consistent continuation of the
    ordinary counting in the finite. But we would proceed even faster, when instead of counting, we doubled numbers by a factor of 2. This leads to
    the central issue of this chapter: Consider the setℕ  {ω} = {1, 2,
    3, ..., ω} and multiply every element by 2 with the result

    {1, 2, 3, ..., ω}*2 = {2, 4, 6, ..., ω*2}.

    What elements fall between ω and ω2? What size has the interval
    between 2ℕ and ω*2? The number of doubled numbers is precisely |ℕ|.
    But half of the natural numbers are not in it. If all natural numbers
    including all even numbers are doubled and if doubling increases the
    value, then not all doubled even numbers fit below ω. Numbers greater
    than all even numbers are not possible.

    The natural answer is (0, ω)2 = (0, ω2) with ω or ω+1 amidst.

    Every other result would violate symmetry and beauty of mathematics, for instance the claim that the result would be ℕ U {ω, ω*2}. All numbers between ω and ω*2 which are precisely as many as in ℕ between 0 and
    ω, would not be in the result? Every structure must be doubled! Like the interval [1, 5] of lengths 4 by doubling gets [1, 5]*2 = [2, 10] of length
    8, the interval (0, ω)2 gets (0, ω*2) with ω*2 = ω + ω =/= ω
    where the whole interval between 0 and ω2 is evenly filled with even numbers like the whole interval between 0 and ω is filled with natural
    numbers before. On the ordinal axis the numbers 0, ω, ω*2, ω*3, ...
    have same distances because same number of ordinals lie between them.

    This means that contrary to the collection of visible natural numbers
    ℕ_def which only are relevant in classical mathematics the whole set ℕ
    is not closed under multiplication. Some natural numbers can become
    transfinite by multiplication. This resembles the displacement of the
    interval (0, 1] by one point to the left-hand side such that the interval
    [0, 1) is covered. Of course these natural numbers are dark like every
    result of ω/k with k in , for instance ω/2 or ω/10^10^100.

    Regards, WM

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