Op 1/03/2025 om 15:15 schreef Python:
I think he has problems with Lorentz features as well :)
A bit of a compensation for his absurd i-rules?
I did a bit of research to see if the structure that Hachel originally proposed, with these multiplication rules:
(a, b) * (a', b') = (aa' + bb', ab' + a'b)
had already been studied. Since it is clearly a ring (but not a field,
as it has divisors of zero), it seemed likely to me.
And indeed, it has! This is called the set of split-complex numbers: https://en.wikipedia.org/wiki/Split-complex_number
I came across it while watching a video by Michael Penn: https://www.youtube.com/watch?v=r5mccK8mNw8
He demonstrates there that there are only three associative R-algebras
over R^2:
- Dual numbers R(epsilon) with epsilon^2 = 0 (i.e. R[X]/(X^2)) -
Complex numbers R(i) with i^2 = -1 \) (i.e. R[X]/(X^2 + 1) -
Split-complex numbers R(j) with j^2 = 1 (i.e.R[X]/(X^2 - 1))
Among these three, only the complex numbers form a field. All three
also have a 2x2 matrix representation.
What should please Hachel is that split-complex numbers naturally
express Lorentz transformations, since their isometries are hyperbolic rotations.
There is even an analogue to Euler’s identity:
e^(i*theta) = cos(theta) + i*sin(theta)
which is:
e^(j*theta) = cosh(theta) + j*sinh(theta)
However, note that while R(j) corresponds to Hachel’s *first* proposed structure, it has *nothing to do* with his *second* proposal of
introducing an element such that (i^2 = i^4 = -1 ). As was pointed out
to him (both here and on fr.sci.maths), this immediately leads to contradictions.
Le 03/03/2025 à 18:31, guido wugi a écrit :
Op 1/03/2025 om 15:15 schreef Python:
I think he has problems with Lorentz features as well :)
Absolutely not.
A bit of a compensation for his absurd i-rules?
I have no problem with Mr. Poincaré's transformations given for the first time
in their positive form well before Mr. Einstein's plagiarism.
My ideas on the nature of the imaginary i are to be classified in the clarity and beauty of mathematics. What do mathematicians say? That i²=-1? What a great
deal! They do not define i, but its square.
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