• Re: How? ? ?

    From efji@21:1/5 to All on Wed Apr 2 14:49:56 2025
    Le 02/04/2025 à 14:32, Richard Hachel a écrit :
    How can mathematicians come up with such absurdities?

    https://www.youtube.com/watch?v=XZriBHTNPw0


    No mathematician would write \sqrt{i} because the symbol "\sqrt" designs
    the positive square root of a real number, which does not make sense in
    \C since it is not an ordered set and the word "positive" is a nonsense
    in \C.

    Anyway, "i" has 2 square roots : ±(1+i)/\sqrt{2}
    and "-i" too : ±(1-i)/\sqrt{2}
    Thus, the mathematically wrong expression "\sqrt{i}+\sqrt{-i}" is non
    univoque and could be any of these 4 values :

    ±\sqrt{2}, ±i\sqrt{2}

    You're welcome

    --
    F.J.

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  • From efji@21:1/5 to All on Wed Apr 2 15:14:58 2025
    Le 02/04/2025 à 15:05, Richard Hachel a écrit :
    Le 02/04/2025 à 14:49, efji a écrit :
    Le 02/04/2025 à 14:32, Richard Hachel a écrit :
    How can mathematicians come up with such absurdities?

    https://www.youtube.com/watch?v=XZriBHTNPw0


    No mathematician would write \sqrt{i} because the symbol "\sqrt"
    designs the positive square root of a real number, which does not make
    sense in \C since it is not an ordered set and the word "positive" is
    a nonsense in \C.

    Anyway, "i" has 2 square roots : ±(1+i)/\sqrt{2}
    and "-i" too : ±(1-i)/\sqrt{2}
    Thus, the mathematically wrong expression "\sqrt{i}+\sqrt{-i}" is non
    univoque and could be any of these 4 values :

    ±\sqrt{2}, ±i\sqrt{2}

    You're welcome

    Four possible values?

    To think that Python gave us a nervous breakdown when I explained that a function could have multiple roots, which was actually true.

    But here, we're falling into the opposite madness.

    We add two numbers, and we find four answers, which is stupid, to say
    the least.

    We don't add two numbers since \sqrt{i} is not a number because this
    notation is a nonsense ! Can you read carefully what I wrote ???


    No, no, the correct answer is simply √i+√(-i)=0.

    Please, once for all, save us from your shitty delirium, dumbass.



    --
    F.J.

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  • From efji@21:1/5 to All on Wed Apr 2 15:56:28 2025
    Le 02/04/2025 à 15:37, Python a écrit :
    Le 02/04/2025 à 14:49, efji a écrit :
    Le 02/04/2025 à 14:32, Richard Hachel a écrit :
    How can mathematicians come up with such absurdities?

    https://www.youtube.com/watch?v=XZriBHTNPw0


    No mathematician would write \sqrt{i} because the symbol "\sqrt"
    designs the positive square root of a real number, which does not make
    sense in \C since it is not an ordered set and the word "positive" is
    a nonsense in \C.

    Not really, see https://en.wikipedia.org/wiki/Principal_value#Square_root

    OK, it is a definition, but actually, in practice, no one takes the risk
    to use \sqrt{z} for z\in\C in a development since it could be
    misleading. And there is almost no interest to use it.

    --
    F.J.

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  • From sobriquet@21:1/5 to All on Wed Apr 2 16:24:35 2025
    Op 02/04/2025 om 15:14 schreef efji:
    Le 02/04/2025 à 15:05, Richard Hachel a écrit :
    Le 02/04/2025 à 14:49, efji a écrit :
    Le 02/04/2025 à 14:32, Richard Hachel a écrit :
    How can mathematicians come up with such absurdities?

    https://www.youtube.com/watch?v=XZriBHTNPw0


    No mathematician would write \sqrt{i} because the symbol "\sqrt"
    designs the positive square root of a real number, which does not
    make sense in \C since it is not an ordered set and the word
    "positive" is a nonsense in \C.

    Anyway, "i" has 2 square roots : ±(1+i)/\sqrt{2}
    and "-i" too : ±(1-i)/\sqrt{2}
    Thus, the mathematically wrong expression "\sqrt{i}+\sqrt{-i}" is non
    univoque and could be any of these 4 values :

    ±\sqrt{2}, ±i\sqrt{2}

    You're welcome

    Four possible values?

    To think that Python gave us a nervous breakdown when I explained that
    a function could have multiple roots, which was actually true.

    But here, we're falling into the opposite madness.

    We add two numbers, and we find four answers, which is stupid, to say
    the least.

    We don't add two numbers since \sqrt{i} is not a number because this
    notation is a nonsense ! Can you read carefully what I wrote ???

    It seems to work just fine in wolfram alpha (desmos in complex mode
    gives the same answer).

    https://www.wolframalpha.com/input?i=sqrt%28i%29

    https://www.desmos.com/calculator/ztfet88jmu

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  • From efji@21:1/5 to All on Wed Apr 2 16:37:47 2025
    Le 02/04/2025 à 16:24, sobriquet a écrit :
    Op 02/04/2025 om 15:14 schreef efji:


    We don't add two numbers since \sqrt{i} is not a number because this
    notation is a nonsense ! Can you read carefully what I wrote ???

    It seems to work just fine in wolfram alpha (desmos in complex mode
    gives the same answer).

    https://www.wolframalpha.com/input?i=sqrt%28i%29

    https://www.desmos.com/calculator/ztfet88jmu


    The fact that online tools give an answer is not a proof.
    These tools are made to give an answer to almost everything. I bet you
    could not find any research paper using this notation. Same as \sqrt{-1}
    which is never used.

    --
    F.J.

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  • From efji@21:1/5 to All on Wed Apr 2 22:11:17 2025
    Le 02/04/2025 à 21:53, Chris M. Thomasson a écrit :
    On 4/2/2025 5:49 AM, efji wrote:
    Le 02/04/2025 à 14:32, Richard Hachel a écrit :
    How can mathematicians come up with such absurdities?

    https://www.youtube.com/watch?v=XZriBHTNPw0


    No mathematician would write \sqrt{i} because the symbol "\sqrt"
    designs the positive square root of a real number, which does not make
    sense in \C since it is not an ordered set and the word "positive" is
    a nonsense in \C.

    Anyway, "i" has 2 square roots : ±(1+i)/\sqrt{2}
    and "-i" too : ±(1-i)/\sqrt{2}
    Thus, the mathematically wrong expression "\sqrt{i}+\sqrt{-i}" is non
    univoque and could be any of these 4 values :

    ±\sqrt{2}, ±i\sqrt{2}

    You're welcome


    sqrt(0+1i) has two roots:

    [0] = sqrt(0+1i)
    [1] = -sqrt(0+1i)

    any of them raised to the the 2'nd power equals 0+1i.

    wow, the dumb Hachel has got a dumb cousin :)


    --
    F.J.

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  • From Moebius@21:1/5 to All on Thu Apr 3 02:10:46 2025
    Am 02.04.2025 um 16:30 schrieb Python:
    Le 02/04/2025 à 14:32, Richard Hachel a écrit :
    How can mathematicians come up with such absurdities?

    https://www.youtube.com/watch?v=XZriBHTNPw0

    Il n'y a rien d'absurde. Le raisonnement est un peu rapide, certes, à un moment (à 8mn 15s) quand il dit "it is obvious that you can factorize by
    +/- 1/sqrt(2)" en réalité en faisant cela l'auteur de la vidéo fait en sorte que c'est la même branche de la fonction sqrt qui est prise en
    compte pour les deux racines, et du coup le résultat final est correct
    (il y a deux valeurs possibles).

    Le maniement de fonction telles que sqrt est délicat dans C, et même
    dans R ! 4 a déjà deux "racines" 2 et -2 ! On sélectionne la valeur positive dans R comme "valeur principale" tandis que dans C le critère
    est d'avoir l'argument dans ]-pi, pi]

    voir : https://fr.wikipedia.org/wiki/ D%C3%A9termination_d%27une_fonction_multivalu%C3%A9e#Racine_carr%C3%A9e_complexe

    https://en.wikipedia.org/wiki/Principal_value#Square_root

    C'est pour cela que dans le cas des nombres complexes on évite
    d'utiliser sqrt comme une fonction mono-valuée et on parle de racines
    (au pluriel) n-èmes et on sait qu'il y en a toujours exactement n.

    What did you say?

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  • From Moebius@21:1/5 to All on Thu Apr 3 02:08:55 2025
    Am 02.04.2025 um 22:11 schrieb efji:

    wow, the dumb Hachel has got a dumb cousin :)

    Keep cool, Chris M. Thomasson is a programmer who is sometimes quite
    stubborn [...], but he's not a crank [I'd say].

    He seems to lack a thorough mathematical education thought and it shows.

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