• Re: quintic equation &more

    From bassam karzeddin@21:1/5 to bassam karzeddin on Thu Aug 3 20:45:03 2023
    On Thursday, March 1, 2018 at 4:14:22 PM UTC+2, bassam karzeddin wrote:
    On Wednesday, July 21, 2004 at 9:33:21 PM UTC+3, Bassam karzeddin wrote:
    On 31 May 04 11:44:08 -0400 (EDT), bassam king karzeddin wrote:
    dear sir,
    i have discovered solution (one real root)in 1991 for the following >equation:

    f(x)=x^n+ax^m+b=0 were,f(x)is rational integeral function
    of x
    (a,b) are real rational numbers
    (n,m) are odd positive integers &(n>m)

    would you like to see such solution

    if,yes, please let me know
    thanking you
    sincerely yours
    bassam karzeddin

    subject:obtain one real root for the following odd degree
    equation,that is continious rational function of x

    f(x)=x^n+ax^m+b=0

    solution:case-1)
    let m be odd positive integer less than n
    let (k=n-m)

    let (r=(b^k/a^n)^(1/m) ,where, r is the airthematical mth root of (b^k/a^n) ,(a=/0)
    let (s=(a^n/b^k)^(1/n) ,where, s is the airthematical nth root of (a^n/b^k),(b=/0)

    if, b^k/{abs(a)}^n < m^m*k^k/n^n

    x=-(b/a)^(1/m)[1-r/m+(2n-m+1)r^2/(2!m^2)-(3n-2m+1)(3n-m+1)r^3/(3!m^3) +(4n-3m+1)(4n-2m+1)(4n-m+1)*r^4/(4!*m^4) -(5n-4m+1)(5n-3m+1)(5n-2m+1)(5n-m+1)r^5/(5!m^5)+...]

    if, b^k/{abs(a)}^n > m^m*k^k/n^n

    x=-b^(1/n)[1-s/n+(2m-n+1)s^2/(2!n^2)-(3m-2n+1)(3m-n+1)s^3/(3!n^3) +(4m-3n+1)(4m-2n+1)(4m-n+1)*s^4/(4!*n^4) -(5m-4n+1)(5m-3n+1)(5m-2n+1)(5m-n+1)s^5/(5!n^5)+...]
    case-2
    let, m be even positive integer less than n

    let x=1/y in the above equation,then you get equation of the previous solved form for one real root.

    In fact,this is nothing but a very little introduction to obtain all
    roots to any polynomials and hopefuly by radicals soon.

    Neither,in the third world nor in the first could I convay these ideas
    for so many years,because Iam a (civil Engineer) not a profisional mathematician(I know nothing about Maple,nor that good in computer
    science and English languge) that is why,I find this site the best to learn and convay ideas.

    ANY COUNTER EXAMPLE IS WELCOMED AT THIS SITE

    Thanking to all who care about the the unborn & undying facts.
    Oops, not a single counterexample found yet to my formula? wonder!

    But why this had been ignored by the professional mathematicians till now (after 14 years now), but actually more, since 1990? wonder!

    Isn't that add to your knowledge? wonder!

    Or do you expect a mature (not any professional) to teach everybody separately about it? wonder!

    Or maybe the communication facility that was available many centuries ago for every professional mathematician but not for you in those days? wonder!

    Doesn't mathematics truly (feed, drink and clothes you as well) wonder!

    What a so shameful human category of human being you are indeed topmost alleged genius professional mathematicians? wonder!

    Or maybe working secretly was much more worth for you stupids? wonder!

    But it seems that they like to leave things for future generation since then it becomes more interesting for sure

    Shame upon your alleged (honesty, nobility and intellect as well that is so incomprehensible

    But you have to wake up fast since your mathematics had been long back broken strictly by the KING, for sure

    No regards for cowords absolute incompetent fools, for sure

    Bassam King Karzeddin

    March, 1st, 2018

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  • From bassam karzeddin@21:1/5 to Thomas Richard on Sun Sep 10 13:59:19 2023
    On Tuesday, June 1, 2004 at 10:50:50 AM UTC+3, Thomas Richard wrote:
    "Edwin Clark" <ecl...@math.usf.edu> wrote:
    [...] Actually it would be interesting
    to just see a root for , say, x^7 + x^3 + 1 or x^7 + x^5 + 1.
    Well, the latter polynomial factors into (x^2+x+1)*(x^5-x^4+x^3-x+1),
    so you can easily find two exact roots. :-)
    --
    Thomas Richard
    Maple Support
    Scientific Computers GmbH
    http://www.scientific.de

    However, even we claim that there are two exact roots, which aren't real, but still we have no real existing root for our given factorabl odd degree polynomial

    BKK

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