• Re: Rotated relativistic disk

    From mitchrae3323@gmail.com@21:1/5 to All on Mon Aug 14 21:40:46 2023
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  • From mitchrae3323@gmail.com@21:1/5 to Richard Hachel on Thu Aug 17 11:26:54 2023
    On Thursday, August 17, 2023 at 3:51:12 AM UTC-7, Richard Hachel wrote:
    Le 16/08/2023 à 23:45, Stephan Lerner a écrit :
    Richard Hachel wrote:

    Is it a rigid disk or not.

    It's not a question of rigidity or not.
    Ideally, an absolutely non-deformable disk is taken.
    It is admitted that it is made of such a material, so indeformable, so
    rigid, that it will not deform by one millimeter.
    And yet Dr. Hachel asserts that the disk will deform, and that a disk
    with a radius of 5 meters will become a disk with a radius of 3 meters, >> if it is rotated until a tangential speed of Vo=0.8c is obtained.

    hi my friend, nice to meet you. So the middle will go at 0.4c, which will contract too. No spiralling, unless you think it exceeds. You are so cool. I love you so much.
    Hi my friend.

    It is important to clarify something.

    We assume that the disk at rest has 5 meters of radius, and,
    if you ask a competent relativist physicist (there must be some), he will answer that if you spin the disk at Vo=0.8c of tangential speed, the circumference of the disk will become 3 meters.

    This is what excellent posters like Sylvia Else, Paul B.Andersen, Julien Arlandis will say.

    You are going to add, as you have just done here, that, if we take a circumference at mid-radius of the revolving disc, the tangential speed
    will be two times less. Let Vo=0.4c.

    It's just as fair.

    But we must add this: this contraction is not homogeneous, and the
    external part of the disc (cortical part) contracts much more than the medullary part (medullary part).

    It's so logical that I wonder why I have to explain it.

    Thus, if we draw a circumference at mid-radius on the disc at rest,
    this circumference will no longer be at mid-radius, but no longer "inside" when the disk turns.

    The calculations are very simple, and anyone can do them.

    R.H.

    How do you accelerate rotation and to how high?
    No in the Unified field rotation does not manifest high.
    Rotation is only slow... a space ship can be high...

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  • From Richard Hachel@21:1/5 to All on Thu Aug 17 21:19:19 2023
    Le 17/08/2023 à 20:26, "mitchr...@gmail.com" a écrit :

    How do you accelerate rotation and to how high?
    No in the Unified field rotation does not manifest high.
    Rotation is only slow... a space ship can be high...

    You're absolutely right, but we're only talking about thought experiments
    here, and supposedly undeformable discs.

    R.H.

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  • From Jim Pennino@21:1/5 to mitchr...@gmail.com on Thu Aug 17 14:37:02 2023
    mitchr...@gmail.com <mitchrae3323@gmail.com> wrote:
    On Thursday, August 17, 2023 at 3:51:12 AM UTC-7, Richard Hachel wrote:
    Le 16/08/2023 à 23:45, Stephan Lerner a écrit :
    Richard Hachel wrote:

    Is it a rigid disk or not.

    It's not a question of rigidity or not.
    Ideally, an absolutely non-deformable disk is taken.
    It is admitted that it is made of such a material, so indeformable, so
    rigid, that it will not deform by one millimeter.
    And yet Dr. Hachel asserts that the disk will deform, and that a disk
    with a radius of 5 meters will become a disk with a radius of 3 meters, >> >> if it is rotated until a tangential speed of Vo=0.8c is obtained.

    hi my friend, nice to meet you. So the middle will go at 0.4c, which will >> > contract too. No spiralling, unless you think it exceeds. You are so cool. >> > I love you so much.
    Hi my friend.

    It is important to clarify something.

    We assume that the disk at rest has 5 meters of radius, and,
    if you ask a competent relativist physicist (there must be some), he will
    answer that if you spin the disk at Vo=0.8c of tangential speed, the
    circumference of the disk will become 3 meters.

    This is what excellent posters like Sylvia Else, Paul B.Andersen, Julien
    Arlandis will say.

    You are going to add, as you have just done here, that, if we take a
    circumference at mid-radius of the revolving disc, the tangential speed
    will be two times less. Let Vo=0.4c.

    It's just as fair.

    But we must add this: this contraction is not homogeneous, and the
    external part of the disc (cortical part) contracts much more than the
    medullary part (medullary part).

    It's so logical that I wonder why I have to explain it.

    Thus, if we draw a circumference at mid-radius on the disc at rest,
    this circumference will no longer be at mid-radius, but no longer "inside" >> when the disk turns.

    The calculations are very simple, and anyone can do them.

    R.H.

    How do you accelerate rotation and to how high?
    No in the Unified field rotation does not manifest high.
    Rotation is only slow... a space ship can be high...


    Moron babble.

    How did you become so blazingly stupid?

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