• Re: Try this at home....

    From Jim Pennino@21:1/5 to Sam Wormley on Wed Feb 7 20:23:04 2024
    Sam Wormley <swormley1@gmail.com> wrote:

    1. Pick any number between 1 and 100: write it down.
    2. Add 17 to that the previous number and write that down.
    3. Add 17 to that the previous sum and write that down.

    4. Take all the digits from your three numbers and scramble
    their order anyway you like. Be careful not to lose any
    of the digets.

    5. If you carefully devide your resulting number by three (3)
    the remainder after dividing will be exactly zero (0).

    Ta Da!

    6. No matter how you scramble those digits — the division
    by three (3) will have no remainder.

    Ta Da! Ta Da!

    Now if you were to show why this happens, you might have something,
    though it should be in sci.math not sci.phyics.

    --- SoupGate-Win32 v1.05
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  • From Jim Pennino@21:1/5 to mitchr...@gmail.com on Fri Feb 9 12:57:22 2024
    mitchr...@gmail.com <mitchrae3323@gmail.com> wrote:
    On Wednesday, February 7, 2024 at 7:18:00 PM UTC-8, Sam Wormley wrote:
    1. Pick any number between 1 and 100: write it down.
    2. Add 17 to that the previous number and write that down.
    3. Add 17 to that the previous sum and write that down.

    4. Take all the digits from your three numbers and scramble
    their order anyway you like. Be careful not to lose any
    of the digets.

    5. If you carefully devide your resulting number by three (3)
    the remainder after dividing will be exactly zero (0).

    Ta Da!

    6. No matter how you scramble those digits — the division
    by three (3) will have no remainder.

    Ta Da! Ta Da!

    Its possible to have a remainder.
    3*.333 gives short of 1. or .999 repeating
    1/3*3 has an infinitesimal remainder that brings
    it to the first integer... or all of the way to 1.


    Confused, incoherent gibberish.

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