1. Pick any number between 1 and 100: write it down.
2. Add 17 to that the previous number and write that down.
3. Add 17 to that the previous sum and write that down.
4. Take all the digits from your three numbers and scramble
their order anyway you like. Be careful not to lose any
of the digets.
5. If you carefully devide your resulting number by three (3)
the remainder after dividing will be exactly zero (0).
Ta Da!
6. No matter how you scramble those digits — the division
by three (3) will have no remainder.
Ta Da! Ta Da!
On Wednesday, February 7, 2024 at 7:18:00 PM UTC-8, Sam Wormley wrote:
1. Pick any number between 1 and 100: write it down.
2. Add 17 to that the previous number and write that down.
3. Add 17 to that the previous sum and write that down.
4. Take all the digits from your three numbers and scramble
their order anyway you like. Be careful not to lose any
of the digets.
5. If you carefully devide your resulting number by three (3)
the remainder after dividing will be exactly zero (0).
Ta Da!
6. No matter how you scramble those digits — the division
by three (3) will have no remainder.
Ta Da! Ta Da!
Its possible to have a remainder.
3*.333 gives short of 1. or .999 repeating
1/3*3 has an infinitesimal remainder that brings
it to the first integer... or all of the way to 1.
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