• Fusing theory

    From Scott@21:1/5 to All on Wed Mar 5 14:47:11 2025
    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also
    requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

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  • From Jeff Gaines@21:1/5 to Scott on Wed Mar 5 15:35:54 2025
    On 05/03/2025 in message <naogsjl9rtkvch1agtp74sstchoenokcfo@4ax.com>
    Scott wrote:

    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also >requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    I too am curious :-)

    However, an appliance only draws the current that it requires doesn't it?
    I you plug a 2 watt appliance into a supply with a 100 Amp fuse it will
    only demand 2 watts won't it?

    If your 'phone needs charging and requires 10 watts to charge you can use
    a charger rated at 10 watts or more, it will only demand 10 watts. If you
    used a 5 watts charger in these circumstance it would get hot and may
    catch alight.

    You do have to get the voltage right for the charger.

    Genuinely interested and awaiting expert input!

    --
    Jeff Gaines Dorset UK
    There are 3 types of people in this world. Those who can count, and those
    who can't.

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  • From Tim Streater@21:1/5 to Scott on Wed Mar 5 15:38:27 2025
    On 5 Mar 2025 at 14:47:11 GMT, "Scott" <newsgroups@gefion.myzen.co.uk> wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off it. If the plug is rated at 2.5 amps, your device you're connecting the plug to better
    not draw more than 2.5 amps. 2.5 is a lot less than 16, so why d'ye think it would be dangerous? Just because the supply is rated at 16 amps, doesn't mean that it's gonna force 16 amps through your plug. The current taken is determined only by the device you've connected the plug to.

    --
    Tim

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  • From Tim Streater@21:1/5 to Jeff Gaines on Wed Mar 5 15:40:41 2025
    On 5 Mar 2025 at 15:35:54 GMT, ""Jeff Gaines"" <jgnewsid@outlook.com> wrote:

    However, an appliance only draws the current that it requires doesn't it?

    The amount of current it draws is defined by the voltage of the supply divided by the resistance of the device (which may vary depending on whether it's hot or not).

    --
    "What causes poverty?" Wrong question. Poverty is our primordial state. The real question is, "What causes wealth?"

    Hint: it ain't Socialism.

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  • From Tricky Dicky@21:1/5 to Scott on Wed Mar 5 15:43:52 2025
    Scott <newsgroups@gefion.myzen.co.uk> wrote:
    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.


    Most domestic supplies are fused at either 100A or 80A but you will not see that at any socket or light fitting as each circuit has its own maximum breaker. The amount of current in each circuit is determined by current
    draw of the load. So for instance a lighting circuit may be fused at 6A but
    if you only switch one bulb on then the current measured on that circuit
    will be dependant on the wattage of the bulb it will not be 6A.

    A 5A rated cable can be connected to a 32A ring main as long as the load on that cable does not exceed approx. 1150W. A correctly fused plug ensures
    that

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  • From Joe@21:1/5 to Tim Streater on Wed Mar 5 16:03:11 2025
    On 5 Mar 2025 15:38:27 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 14:47:11 GMT, "Scott"
    <newsgroups@gefion.myzen.co.uk> wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off
    it. If the plug is rated at 2.5 amps, your device you're connecting
    the plug to better not draw more than 2.5 amps. 2.5 is a lot less
    than 16, so why d'ye think it would be dangerous? Just because the
    supply is rated at 16 amps, doesn't mean that it's gonna force 16
    amps through your plug. The current taken is determined only by the
    device you've connected the plug to.


    So what happens if a fault occurs in the appliance which draws 12A? The
    16A circuit fuse will not fail, but the appliance flex may be able to
    carry only 5A safely, and overheat dangerously.

    The point of a fuse is to protect anything downstream of it from a
    fault current which may be dangerous. The point in this case is that a Euro-type plug is not fused, and that the flex leading from it must be
    able to safely handle fault currents up to 1.5 times the rating of the
    next upstream fuse, in this case, the circuit fuse. I believe the plug
    itself will probably handle this safely, but it seems unlikely that a
    domestic lamp will be fitted with a flex able to handle 24 Amps for up
    to four hours.

    This is the question which is being asked, and I don't know the answer.
    It may be that not all European circuits are rated at 16A, they may
    have differentiated socket capacities as we did before the 13A plug and
    socket. That is obviously no longer the case in the UK, and the short
    answer in this particular case is to fit a 13A plug fused appropriately
    to the cable size, rather than just using an unfused adaptor. Since the
    cable end will be stripped, the strands can be measured and counted to determine the cable capacity. It must be assumed that any wiring inside
    the lamp is of equal capacity.

    --
    Joe

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  • From David Wade@21:1/5 to Tim Streater on Wed Mar 5 17:06:07 2025
    On 05/03/2025 16:38, Tim Streater wrote:
    On 5 Mar 2025 at 14:47:11 GMT, "Scott" <newsgroups@gefion.myzen.co.uk> wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off it. If the plug is rated at 2.5 amps, your device you're connecting the plug to better not draw more than 2.5 amps. 2.5 is a lot less than 16, so why d'ye think it would be dangerous? Just because the supply is rated at 16 amps, doesn't mean that it's gonna force 16 amps through your plug. The current taken is determined only by the device you've connected the plug to.


    I think the question is why in the UK are we required to fit a fuse
    when in the rest of the world they rely on the Circuit Breaker in the
    "consumer unit".

    Here in Spain the Air Fryer I have just purchased from Aldi has no fuse.
    As its 1.4kw in the UK it will have a 13 amp fuse.

    WHY?

    Dave

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  • From Tim Streater@21:1/5 to Joe on Wed Mar 5 16:07:08 2025
    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A? The
    16A circuit fuse will not fail, but the appliance flex may be able to
    carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.

    --
    Tim

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  • From Tim Streater@21:1/5 to David Wade on Wed Mar 5 16:11:38 2025
    On 5 Mar 2025 at 16:06:07 GMT, "David Wade" <dave@g4ugm.invalid> wrote:

    On 05/03/2025 16:38, Tim Streater wrote:
    On 5 Mar 2025 at 14:47:11 GMT, "Scott" <newsgroups@gefion.myzen.co.uk> wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off it. If the
    plug is rated at 2.5 amps, your device you're connecting the plug to better >> not draw more than 2.5 amps. 2.5 is a lot less than 16, so why d'ye think it >> would be dangerous? Just because the supply is rated at 16 amps, doesn't mean
    that it's gonna force 16 amps through your plug. The current taken is
    determined only by the device you've connected the plug to.

    I think the question is why in the UK are we required to fit a fuse
    when in the rest of the world they rely on the Circuit Breaker in the "consumer unit".

    Here in Spain the Air Fryer I have just purchased from Aldi has no fuse.
    As its 1.4kw in the UK it will have a 13 amp fuse.

    WHY?

    Perhaps we're more safety conscious? The Yanks, with their cheese-paring 110V, are even worse off, with four times the heating effect (for a given device wattage) in the cabling and plugs.

    --
    The reason you think government is the solution is because you think freedom is the problem. But the truth is that government ensures that the most evil, ruthless people end up in control, because the state is a single point of failure, and a high-value
    target of corruption.

    Alan Lovejoy

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  • From Jethro_uk@21:1/5 to Tim Streater on Wed Mar 5 16:38:01 2025
    On Wed, 05 Mar 2025 16:11:38 +0000, Tim Streater wrote:

    On 5 Mar 2025 at 16:06:07 GMT, "David Wade" <dave@g4ugm.invalid> wrote:

    On 05/03/2025 16:38, Tim Streater wrote:
    On 5 Mar 2025 at 14:47:11 GMT, "Scott" <newsgroups@gefion.myzen.co.uk>
    wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off it.
    If the plug is rated at 2.5 amps, your device you're connecting the
    plug to better not draw more than 2.5 amps. 2.5 is a lot less than 16,
    so why d'ye think it would be dangerous? Just because the supply is
    rated at 16 amps, doesn't mean that it's gonna force 16 amps through
    your plug. The current taken is determined only by the device you've
    connected the plug to.

    I think the question is why in the UK are we required to fit a fuse
    when in the rest of the world they rely on the Circuit Breaker in the
    "consumer unit".

    Here in Spain the Air Fryer I have just purchased from Aldi has no
    fuse.
    As its 1.4kw in the UK it will have a 13 amp fuse.

    WHY?

    Perhaps we're more safety conscious? The Yanks, with their cheese-paring 110V,
    are even worse off, with four times the heating effect (for a given
    device wattage) in the cabling and plugs.

    They can get 240V as most houses are supplied by 2 phases. A bit fiddly,
    but you can work with it.

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  • From Scott@21:1/5 to jethro_uk@hotmailbin.com on Wed Mar 5 17:32:22 2025
    On Wed, 5 Mar 2025 16:38:01 -0000 (UTC), Jethro_uk
    <jethro_uk@hotmailbin.com> wrote:

    On Wed, 05 Mar 2025 16:11:38 +0000, Tim Streater wrote:

    On 5 Mar 2025 at 16:06:07 GMT, "David Wade" <dave@g4ugm.invalid> wrote:

    On 05/03/2025 16:38, Tim Streater wrote:
    On 5 Mar 2025 at 14:47:11 GMT, "Scott" <newsgroups@gefion.myzen.co.uk> >>>> wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off it. >>>> If the plug is rated at 2.5 amps, your device you're connecting the
    plug to better not draw more than 2.5 amps. 2.5 is a lot less than 16, >>>> so why d'ye think it would be dangerous? Just because the supply is
    rated at 16 amps, doesn't mean that it's gonna force 16 amps through
    your plug. The current taken is determined only by the device you've
    connected the plug to.

    I think the question is why in the UK are we required to fit a fuse
    when in the rest of the world they rely on the Circuit Breaker in the
    "consumer unit".

    Here in Spain the Air Fryer I have just purchased from Aldi has no
    fuse.
    As its 1.4kw in the UK it will have a 13 amp fuse.

    WHY?

    Perhaps we're more safety conscious? The Yanks, with their cheese-paring
    110V,
    are even worse off, with four times the heating effect (for a given
    device wattage) in the cabling and plugs.

    They can get 240V as most houses are supplied by 2 phases. A bit fiddly,
    but you can work with it.

    Can you use European appliances designed for one live and one neutral
    when there would be two live inputs (presumably out of phase)?

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  • From Joe@21:1/5 to Tim Streater on Wed Mar 5 17:43:57 2025
    On 5 Mar 2025 16:07:08 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A?
    The 16A circuit fuse will not fail, but the appliance flex may be
    able to carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.


    This case was a Europlug, no fuse.

    What now?

    --
    Joe

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  • From nib@21:1/5 to Joe on Wed Mar 5 17:26:17 2025
    On 2025-03-05 16:03, Joe wrote:
    On 5 Mar 2025 15:38:27 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 14:47:11 GMT, "Scott"
    <newsgroups@gefion.myzen.co.uk> wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off
    it. If the plug is rated at 2.5 amps, your device you're connecting
    the plug to better not draw more than 2.5 amps. 2.5 is a lot less
    than 16, so why d'ye think it would be dangerous? Just because the
    supply is rated at 16 amps, doesn't mean that it's gonna force 16
    amps through your plug. The current taken is determined only by the
    device you've connected the plug to.


    So what happens if a fault occurs in the appliance which draws 12A? The
    16A circuit fuse will not fail, but the appliance flex may be able to
    carry only 5A safely, and overheat dangerously.

    The point of a fuse is to protect anything downstream of it from a
    fault current which may be dangerous. The point in this case is that a Euro-type plug is not fused, and that the flex leading from it must be
    able to safely handle fault currents up to 1.5 times the rating of the
    next upstream fuse, in this case, the circuit fuse. I believe the plug
    itself will probably handle this safely, but it seems unlikely that a domestic lamp will be fitted with a flex able to handle 24 Amps for up
    to four hours.

    This is the question which is being asked, and I don't know the answer.
    It may be that not all European circuits are rated at 16A, they may
    have differentiated socket capacities as we did before the 13A plug and socket. That is obviously no longer the case in the UK, and the short
    answer in this particular case is to fit a 13A plug fused appropriately
    to the cable size, rather than just using an unfused adaptor. Since the
    cable end will be stripped, the strands can be measured and counted to determine the cable capacity. It must be assumed that any wiring inside
    the lamp is of equal capacity.


    I think the theory is that it is very unlikely that a fault in the
    appliance will result, in your example, in a 12A continuous draw.
    Usually it will either work properly, or it will develop a short circuit.

    In the case of a short circuit, the appliance wiring and plug will be
    able to carry the short-duration very large fault current without
    failing, as the heat generated in the short time will not be sufficient
    to melt anything.

    But the UK idea of a fuse in the plug is obviously better.

    nib

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  • From John Rumm@21:1/5 to Scott on Wed Mar 5 18:01:22 2025
    On 05/03/2025 14:47, Scott wrote:

    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also requires a fuse?

    If it required a fuse, then it would need to be in the lamp. In most
    countries there won't be the option of a fused plug, so *fault*
    protection will need to be provided by the circuit breaker at the origin
    of the whole circuit (typically 16A) [1].

    For something like a lamp there is no real need for overload protection
    since the characteristics of the load limit the maximum load. There is
    not much you can plug into a ES or BC lamp holder that would draw more
    than saw 150W unless you want to get very creative. (The lamp itself may
    also specify a maximum wattage, but this is likely to be a thermal
    constraint to stop the shade melting etc).

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    The key is the different types of over current protection. Normally you consider two scenarios: "overload" and "fault".

    Overload is when you can expect a scenario that could cause more than
    the expected design current to be drawn for an extended period of time.

    Fault current is when there is a (close to) short circuit event -
    typically L connected to N or L connected to E caused by an abnormal
    event (like nail through a hidden cable, chair leg crushing a flex etc).

    So all circuits can experience fault currents. But not all are liable to overload. A lamp on its own is very unlikely to need to be protected
    against overload. A circuit with 100 lamps on it however may.

    With a fault current the only limit on the current flow is the
    resistance of the fault path - this could be fractions of an ohm, and
    the current could be 1000s of amps. That means thing will get very hot
    very quickly (in a really bad case it could even explode (aka an arc
    fault)). So here you need a very fast active protection since you need
    to limit the amount of energy that is "let through". Fuses can do this
    if they are the right type. Circuit breakers normally have a separate
    mechanism for handling fault currents - typically a magnetic solenoid
    that will fire at a particular threshold and interrupt the circuit. (for
    a normal "type B" circuit breakers this is 5x nominal current - so to
    trip a B32 MCB "instantly" you would need >= 160A of fault current.

    An overload situation can occur on something like a socket circuit. The
    user can do things that the designer has no contrl over. To many large
    loads plugged in and running at once for example. However if you load up
    a 32A ring circuit with 50A of load, bad stuff is not going to happen immediately. Things will start warming up, but it is not until the cable conductors get to over 70 deg C that you might start degrading the life expectancy of the cable. So the protective device can impose a more
    leisurely protection scheme - tripping on a thermal response that takes
    account of the size of the load and the duration. They usually use a
    bi-metal strip like in a thermostat for this.

    If you look at :

    https://wiki.diyfaq.org.uk/index.php/MCB#Types_B.2CC.2CD

    You can get a feel for the response times to overloads from the
    "curves". So on:

    https://wiki.diyfaq.org.uk/images/d/d4/Curve-MCBTypeB.png

    You can see a 16A MCB will probably allow 20A indefinitely. 30A would
    trip it in 5 mins, 40A in 60 secs etc. Reach 80 however and you activate
    the fault response and get a trip in under 0.1 sec.


    [1] There are exceptions for old UK appliances that were designed just
    for our market, see:

    https://wiki.diyfaq.org.uk/index.php/Choosing_a_plug_fuse



    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

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  • From Theo@21:1/5 to Scott on Wed Mar 5 18:24:22 2025
    Scott <newsgroups@gefion.myzen.co.uk> wrote:
    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    The general European idea is the socket would be on a 16A MCB radial, so
    fault currents would be limited to 16A. The UK has a 32A ring main, from
    which you could draw a 32A fault current - that's bad.

    So instead plugs are fused at 13A. When you plug in an appliance, either it
    has an internal fuse (often non replaceable) or an internal design that inherently limits the current. So really the plugtop fuse protects from a
    nail through the flex or similar short circuit before the appliance.

    Once you have a plug fuse, you can then replace it with a lower rated one,
    to match a thinner cable. You can't do that woth a Europlug, but the cable
    may ultimately act as its own fuse.

    It's about risks, failure modes and cost/benefit. UK and other countries' designs just land in different places on the spectrum.

    Theo

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  • From Jeff Layman@21:1/5 to John Rumm on Wed Mar 5 18:17:37 2025
    On 05/03/2025 18:01, John Rumm wrote:

    For something like a lamp there is no real need for overload protection
    since the characteristics of the load limit the maximum load. There is
    not much you can plug into a ES or BC lamp holder that would draw more
    than saw 150W unless you want to get very creative.

    You obviously weren't around in the 50s, John! I can remember my mother
    ironing using the overhead lighting socket to power the iron. She
    removed the 60W bulb and put a two-way bayonet splitter into light
    socket. The bulb went into one side of the splitter and the iron was
    plugged into the other side. I've a feeling, though, that irons in those
    days were much smaller and of a much lower wattage (700W?) than they are
    today. The fuse box had 5A fuse wire to protect the circuit (and no, we
    didn't used foil from a fag packet as the fuse like many others did!).
    So the fuse wire was easily able to cope with the 3A used by the iron
    and bulb.

    --
    Jeff

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  • From John Rumm@21:1/5 to Jeff Layman on Wed Mar 5 18:30:25 2025
    On 05/03/2025 18:17, Jeff Layman wrote:
    On 05/03/2025 18:01, John Rumm wrote:

    For something like a lamp there is no real need for overload protection
    since the characteristics of the load limit the maximum load. There is
    not much you can plug into a ES or BC lamp holder that would draw more
    than saw 150W unless you want to get very creative.

    You obviously weren't around in the 50s, John!

    True, not even a twinkle in the eye :-)

    I can remember my mother
    ironing using the overhead lighting socket to power the iron.

    Yes I had those in mind when adding the "unless you want to get very
    creative." rider... not something you see in common use today, and I
    expect not something that many would even think of as an option. I
    suppose you might consider a cheap 4 way extension lead a more modern
    day equivalent!

    She
    removed the 60W bulb and put a two-way bayonet splitter into light
    socket. The bulb went into one side of the splitter and the iron was
    plugged into the other side. I've a feeling, though, that irons in those
    days were much smaller and of a much lower wattage (700W?) than they are today. The fuse box had 5A fuse wire to protect the circuit (and no, we didn't used foil from a fag packet as the fuse like many others did!).
    So the fuse wire was easily able to cope with the 3A used by the iron
    and bulb.

    Indeed but that is just another example of the circuit as a whole
    needing overload and fault protection.



    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

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  • From Jethro_uk@21:1/5 to Scott on Wed Mar 5 18:18:24 2025
    On Wed, 05 Mar 2025 17:32:22 +0000, Scott wrote:

    On Wed, 5 Mar 2025 16:38:01 -0000 (UTC), Jethro_uk
    <jethro_uk@hotmailbin.com> wrote:

    On Wed, 05 Mar 2025 16:11:38 +0000, Tim Streater wrote:

    On 5 Mar 2025 at 16:06:07 GMT, "David Wade" <dave@g4ugm.invalid>
    wrote:

    On 05/03/2025 16:38, Tim Streater wrote:
    On 5 Mar 2025 at 14:47:11 GMT, "Scott"
    <newsgroups@gefion.myzen.co.uk>
    wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps. >>>>>> How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off
    it.
    If the plug is rated at 2.5 amps, your device you're connecting the
    plug to better not draw more than 2.5 amps. 2.5 is a lot less than
    16,
    so why d'ye think it would be dangerous? Just because the supply is
    rated at 16 amps, doesn't mean that it's gonna force 16 amps through >>>>> your plug. The current taken is determined only by the device you've >>>>> connected the plug to.

    I think the question is why in the UK are we required to fit a fuse
    when in the rest of the world they rely on the Circuit Breaker in the
    "consumer unit".

    Here in Spain the Air Fryer I have just purchased from Aldi has no
    fuse.
    As its 1.4kw in the UK it will have a 13 amp fuse.

    WHY?

    Perhaps we're more safety conscious? The Yanks, with their
    cheese-paring 110V,
    are even worse off, with four times the heating effect (for a given
    device wattage) in the cabling and plugs.

    They can get 240V as most houses are supplied by 2 phases. A bit fiddly, >>but you can work with it.

    Can you use European appliances designed for one live and one neutral
    when there would be two live inputs (presumably out of phase)?

    I have no idea. But it's how they get the heftier kit to run (HVAC etc).

    https://youtu.be/jMmUoZh3Hq4

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  • From SteveW@21:1/5 to Jeff Gaines on Wed Mar 5 18:53:24 2025
    On 05/03/2025 15:35, Jeff Gaines wrote:
    On 05/03/2025 in message <naogsjl9rtkvch1agtp74sstchoenokcfo@4ax.com>
    Scott wrote:

    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also
    requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    I too am curious :-)

    However, an appliance only draws the current that it requires doesn't
    it? I you plug a 2 watt appliance into a supply with a 100 Amp fuse it
    will only demand 2 watts won't it?

    While the lamp will only take what it needs normally, there is no
    guarantee that under a fault condition, it may not take considerably
    more and overload the flex.

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  • From The Natural Philosopher@21:1/5 to Jeff Gaines on Wed Mar 5 18:56:22 2025
    On 05/03/2025 15:35, Jeff Gaines wrote:
    On 05/03/2025 in message <naogsjl9rtkvch1agtp74sstchoenokcfo@4ax.com>
    Scott wrote:

    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also
    requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    I too am curious :-)

    However, an appliance only draws the current that it requires doesn't
    it? I you plug a 2 watt appliance into a supply with a 100 Amp fuse it
    will only demand 2 watts won't it?

    If your 'phone needs charging and requires 10 watts to charge you can
    use a charger rated at 10 watts or more, it will only demand 10 watts.
    If you used a 5 watts charger in these circumstance it would get hot and
    may catch alight.

    You do have to get the voltage right for the charger.

    Genuinely interested and awaiting expert input!

    UK standards are WAY above EU standards

    As has been pointed out the idea of a plug fuse is to protect the cable
    from catching fire under fault conditions.

    The unit itself should have an internal fuse to protect itself.,

    Frankly US style and Europlug style electrics are sketchy as fuck


    --
    "Nature does not give up the winter because people dislike the cold."

    ― Confucius

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  • From John Rumm@21:1/5 to Joe on Wed Mar 5 18:53:36 2025
    On 05/03/2025 17:43, Joe wrote:
    On 5 Mar 2025 16:07:08 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A?
    The 16A circuit fuse will not fail, but the appliance flex may be
    able to carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.


    This case was a Europlug, no fuse.

    What now?

    That is when you apply the adiabatic equation... [1]


    You can do a "fault withstand" calculation to check that the amount of
    metal available in the conductors will safely handle the fault condition.

    For example, let's say you have a table lamp with 2m of 0.5mm^2 flex on
    it. It is on the end of a long circuit with a 32A MCB at the origin. The
    plug has a 13A fuse in it. What happens when you cut through the flex
    next to the lamp with wire cutters when it is powered on?

    The first thing you work out the prospective fault current. So you need
    to add up the external earth loop impedance, the circuit resistance to
    the socket, and the resistance to the far end of the flex.

    Let's say that is 0.35 ohms for the external earth loop, another ohm in
    the circuit wires, and another 0.15 ohms for the far end of the flex.
    That is 1.5 ohms. So the fault current at the far end of the flex could
    be 230 / 1.5 = 153A. Sounds like a lot for a 3A flex!

    However on the bright side that is comfortably enough to blow the fuse
    in the plug, so it will only carry that current for a very short time.
    Let's assume 0.1 secs (in reality it could be much less - fuses can be
    very fast for massive fault currents).

    We can assume all the cables have PVC insulation - so we can use the "k
    factor" of 115, in the equation:

    s = sqrt( I^2 . t ) / k

    s = sqrt( 153^2 x 0.1 ) / 115

    s = 0.42mm^2

    So you need at least 0.42mm^2 of copper cable area to be able to safely
    clear the fault by blowing the plug fuse, and we can conclude that the
    0.5mm^2 flex will live to fight another day.


    [1] https://wiki.diyfaq.org.uk/index.php/Calculating_A_Cable_Size#Adiabatic_Check

    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

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  • From The Natural Philosopher@21:1/5 to Joe on Wed Mar 5 18:57:47 2025
    On 05/03/2025 16:03, Joe wrote:


    So what happens if a fault occurs in the appliance which draws 12A? The
    16A circuit fuse will not fail, but the appliance flex may be able to
    carry only 5A safely, and overheat dangerously.

    The internal fuse in the device will blow




    --
    Outside of a dog, a book is a man's best friend. Inside of a dog it's
    too dark to read.

    Groucho Marx

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  • From TimW@21:1/5 to John Rumm on Wed Mar 5 19:07:45 2025
    On 05/03/2025 18:30, John Rumm wrote:
    On 05/03/2025 18:17, Jeff Layman wrote:
    On 05/03/2025 18:01, John Rumm wrote:

    For something like a lamp there is no real need for overload protection
    since the characteristics of the load limit the maximum load. There is
    not much you can plug into a ES or BC lamp holder that would draw more
    than saw 150W unless you want to get very creative.

    You obviously weren't around in the 50s, John!

    True, not even a twinkle in the eye :-)

    I can remember my mother ironing using the overhead lighting socket to
    power the iron.

    Yes I had those in mind when adding the "unless you want to get very creative." rider... not something you see in common use today, and I
    expect not something that many would even think of as an option. I
    suppose you might consider a cheap 4 way extension lead a more modern
    day equivalent!

    She removed the 60W bulb and put a two-way bayonet splitter into light
    socket. The bulb went into one side of the splitter and the iron was
    plugged into the other side. I've a feeling, though, that irons in
    those days were much smaller and of a much lower wattage (700W?) than
    they are today. The fuse box had 5A fuse wire to protect the circuit
    (and no, we didn't used foil from a fag packet as the fuse like many
    others did!). So the fuse wire was easily able to cope with the 3A
    used by the iron and bulb.

    Indeed but that is just another example of the circuit as a whole
    needing overload and fault protection.


    Fumbling around in the dark trying to turn on a standard lamp I plugged
    my finger into a bulb holder once. It was 1975, and I can still
    remember, vividly the sensation.

    TW

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  • From The Natural Philosopher@21:1/5 to David Wade on Wed Mar 5 18:59:20 2025
    On 05/03/2025 16:06, David Wade wrote:
    On 05/03/2025 16:38, Tim Streater wrote:
    On 5 Mar 2025 at 14:47:11 GMT, "Scott" <newsgroups@gefion.myzen.co.uk>
    wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off it.
    If the
    plug is rated at 2.5 amps, your device you're connecting the plug to
    better
    not draw more than 2.5 amps. 2.5 is a lot less than 16, so why d'ye
    think it
    would be dangerous? Just because the supply is rated at 16 amps,
    doesn't mean
    that it's gonna force 16 amps through your plug. The current taken is
    determined only by the device you've connected the plug to.


    I think the question is why in the UK are we required to fit a fuse when
    in the rest of the world they rely on the Circuit Breaker in the
    "consumer unit".

    And the answer is simple.
    We use a ring main, rated at 32A to drive sockets rated at 13A max.

    The rest of the world uses switched spurs.

    --
    Outside of a dog, a book is a man's best friend. Inside of a dog it's
    too dark to read.

    Groucho Marx

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  • From The Natural Philosopher@21:1/5 to All on Wed Mar 5 18:59:55 2025
    On 05/03/2025 16:38, Jethro_uk wrote:
    On Wed, 05 Mar 2025 16:11:38 +0000, Tim Streater wrote:

    On 5 Mar 2025 at 16:06:07 GMT, "David Wade" <dave@g4ugm.invalid> wrote:

    On 05/03/2025 16:38, Tim Streater wrote:
    On 5 Mar 2025 at 14:47:11 GMT, "Scott" <newsgroups@gefion.myzen.co.uk> >>>> wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off it. >>>> If the plug is rated at 2.5 amps, your device you're connecting the
    plug to better not draw more than 2.5 amps. 2.5 is a lot less than 16, >>>> so why d'ye think it would be dangerous? Just because the supply is
    rated at 16 amps, doesn't mean that it's gonna force 16 amps through
    your plug. The current taken is determined only by the device you've
    connected the plug to.

    I think the question is why in the UK are we required to fit a fuse
    when in the rest of the world they rely on the Circuit Breaker in the
    "consumer unit".

    Here in Spain the Air Fryer I have just purchased from Aldi has no
    fuse.
    As its 1.4kw in the UK it will have a 13 amp fuse.

    WHY?

    Perhaps we're more safety conscious? The Yanks, with their cheese-paring
    110V,
    are even worse off, with four times the heating effect (for a given
    device wattage) in the cabling and plugs.

    They can get 240V as most houses are supplied by 2 phases. A bit fiddly,
    but you can work with it.

    Not 2 phases. One centre tapped phase.

    --
    Outside of a dog, a book is a man's best friend. Inside of a dog it's
    too dark to read.

    Groucho Marx

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  • From John Rumm@21:1/5 to David Wade on Wed Mar 5 19:01:30 2025
    On 05/03/2025 16:06, David Wade wrote:
    On 05/03/2025 16:38, Tim Streater wrote:
    On 5 Mar 2025 at 14:47:11 GMT, "Scott" <newsgroups@gefion.myzen.co.uk>
    wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off it.
    If the
    plug is rated at 2.5 amps, your device you're connecting the plug to
    better
    not draw more than 2.5 amps. 2.5 is a lot less than 16, so why d'ye
    think it
    would be dangerous? Just because the supply is rated at 16 amps,
    doesn't mean
    that it's gonna force 16 amps through your plug. The current taken is
    determined only by the device you've connected the plug to.


    I think the question is why in the UK are we required to fit a fuse when
    in the rest of the world they rely on the Circuit Breaker in the
    "consumer unit".

    Because they have use relatively low current circuit breakers in the CU
    on the understanding that the circuit breaker will have to protect not
    just the circuit cables from fault currents, but also the (potentially
    much smaller) appliance flexes.

    This leads to needing lots of small circuits to provide adequate numbers
    of sockets, and the extra inconvenience for the users since it is not
    difficult to find a selection of appliances that will trip the MCB.

    Here with a 32A circuit, we can festoon the place with sockets (100m^2
    worth on a ring) knowing it is quite hard to conjure up enough load to
    trip that on overload, and that the plug fuses will offer fault current protection to the appliance flexes.

    Here in Spain the Air Fryer I have just purchased from Aldi has no fuse.
    As its 1.4kw in the UK it will have a 13 amp fuse.

    WHY?

    See my reply elsewhere in this thread about adiabatic calculations.

    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

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  • From The Natural Philosopher@21:1/5 to SteveW on Wed Mar 5 19:02:11 2025
    On 05/03/2025 18:53, SteveW wrote:
    On 05/03/2025 15:35, Jeff Gaines wrote:
    On 05/03/2025 in message <naogsjl9rtkvch1agtp74sstchoenokcfo@4ax.com>
    Scott wrote:

    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also
    requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    I too am curious :-)

    However, an appliance only draws the current that it requires doesn't
    it? I you plug a 2 watt appliance into a supply with a 100 Amp fuse it
    will only demand 2 watts won't it?

    While the lamp will only take what it needs normally, there is no
    guarantee that under a fault condition, it may not take considerably
    more and overload the flex.
    In practice there will be a far more fragile link in the device itself.
    IN the case of a filament lamp, the filament

    --
    "I guess a rattlesnake ain't risponsible fer bein' a rattlesnake, but ah
    puts mah heel on um jess the same if'n I catches him around mah chillun".

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  • From Chris Hogg@21:1/5 to newsgroups@gefion.myzen.co.uk on Wed Mar 5 19:11:05 2025
    On Wed, 05 Mar 2025 14:47:11 +0000, Scott
    <newsgroups@gefion.myzen.co.uk> wrote:

    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also >requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    I always understood that the fuse was there to protect the house
    wiring i.e. the ring main, so that if a short develops in the flex
    coming from the socket to the table lamp or whatever (the dog chews
    through it, for example) then the ring main doesn't end up overloaded, overheats, catches fire and burns the house down. Never mind what
    happens to the dog!

    --

    Chris

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  • From John Rumm@21:1/5 to Tricky Dicky on Wed Mar 5 19:07:30 2025
    On 05/03/2025 15:43, Tricky Dicky wrote:
    Scott <newsgroups@gefion.myzen.co.uk> wrote:
    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also
    requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.


    Most domestic supplies are fused at either 100A or 80A but you will not see that at any socket or light fitting as each circuit has its own maximum breaker. The amount of current in each circuit is determined by current
    draw of the load. So for instance a lighting circuit may be fused at 6A but if you only switch one bulb on then the current measured on that circuit
    will be dependant on the wattage of the bulb it will not be 6A.

    Indeed.

    A 5A rated cable can be connected to a 32A ring main as long as the load on that cable does not exceed approx. 1150W. A correctly fused plug ensures
    that

    Remember fuses don't limit current (they have no mechanism to do so),
    all they can do is limit the duration of fault conditions.

    So a fault current can be 1000A and the fitted fuse will not change
    that. What the correctly sized fuse will ensure is that the 1000A is not allowed to flow for long enough to cause damage.




    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

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  • From Theo@21:1/5 to Scott on Wed Mar 5 18:30:56 2025
    Scott <newsgroups@gefion.myzen.co.uk> wrote:

    Can you use European appliances designed for one live and one neutral
    when there would be two live inputs (presumably out of phase)?

    Yes, assuming they'll work on 60Hz. And they don't do things like tie 'neutral' to earth/ground (the appliance neutral will be hot in this
    scenario) - which would trip an RCD nowadays anyway.

    Importing European kettles to the US is a thing people do.

    Theo

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  • From Andy Burns@21:1/5 to The Natural Philosopher on Wed Mar 5 19:09:26 2025
    The Natural Philosopher wrote:

    The internal fuse in the device will blow

    And a lot of LED lamps have a low value resistor (1 or 2 ohm) as the
    first component in their internal PSU to act as a fuse (and an inrush
    current limiter).

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  • From John Rumm@21:1/5 to Chris Hogg on Wed Mar 5 19:24:50 2025
    On 05/03/2025 19:11, Chris Hogg wrote:
    On Wed, 05 Mar 2025 14:47:11 +0000, Scott
    <newsgroups@gefion.myzen.co.uk> wrote:

    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also
    requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    I always understood that the fuse was there to protect the house
    wiring i.e. the ring main, so that if a short develops in the flex
    coming from the socket to the table lamp or whatever (the dog chews
    through it, for example) then the ring main doesn't end up overloaded, overheats, catches fire and burns the house down. Never mind what
    happens to the dog!

    Na, generally that is what the MCB / Fuse / RCD in the CU is for.

    (although there are cases where you can delegate overload protection downstream, fault protection must always be upstream)

    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

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  • From John Rumm@21:1/5 to Theo on Wed Mar 5 19:22:03 2025
    On 05/03/2025 18:24, Theo wrote:
    Scott <newsgroups@gefion.myzen.co.uk> wrote:
    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also
    requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    The general European idea is the socket would be on a 16A MCB radial, so fault currents would be limited to 16A. The UK has a 32A ring main, from which you could draw a 32A fault current - that's bad.

    With respect, that's nonsense!

    MCBs don't limit fault currents (or any other current) - only ohms can
    limit current.


    So instead plugs are fused at 13A. When you plug in an appliance, either it has an internal fuse (often non replaceable) or an internal design that inherently limits the current. So really the plugtop fuse protects from a nail through the flex or similar short circuit before the appliance.

    Once you have a plug fuse, you can then replace it with a lower rated one,
    to match a thinner cable. You can't do that woth a Europlug, but the cable may ultimately act as its own fuse.

    It is one of the reasons that many appliances have short cables. It
    means the maker can cheap out on thin flex, and still stay just inside
    the threshold where the flex will survive the anticipated fault current
    for long enough to operate the circuit protective device.

    It's about risks, failure modes and cost/benefit. UK and other countries' designs just land in different places on the spectrum.

    Or just maths :-)

    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Scott@21:1/5 to TimW on Wed Mar 5 19:57:12 2025
    On Wed, 5 Mar 2025 19:07:45 +0000, TimW <timw@nomailta.co.uk> wrote:

    On 05/03/2025 18:30, John Rumm wrote:
    On 05/03/2025 18:17, Jeff Layman wrote:
    On 05/03/2025 18:01, John Rumm wrote:

    For something like a lamp there is no real need for overload protection >>>> since the characteristics of the load limit the maximum load. There is >>>> not much you can plug into a ES or BC lamp holder that would draw more >>>> than saw 150W unless you want to get very creative.

    You obviously weren't around in the 50s, John!

    True, not even a twinkle in the eye :-)

    I can remember my mother ironing using the overhead lighting socket to
    power the iron.

    Yes I had those in mind when adding the "unless you want to get very
    creative." rider... not something you see in common use today, and I
    expect not something that many would even think of as an option. I
    suppose you might consider a cheap 4 way extension lead a more modern
    day equivalent!

    She removed the 60W bulb and put a two-way bayonet splitter into light
    socket. The bulb went into one side of the splitter and the iron was
    plugged into the other side. I've a feeling, though, that irons in
    those days were much smaller and of a much lower wattage (700W?) than
    they are today. The fuse box had 5A fuse wire to protect the circuit
    (and no, we didn't used foil from a fag packet as the fuse like many
    others did!). So the fuse wire was easily able to cope with the 3A
    used by the iron and bulb.

    Indeed but that is just another example of the circuit as a whole
    needing overload and fault protection.

    Fumbling around in the dark trying to turn on a standard lamp I plugged
    my finger into a bulb holder once. It was 1975, and I can still
    remember, vividly the sensation.

    When I was a student I came home for an overnight stay. My bed had one
    of the old-fashioned bedlamps that clipped on to the headboard. I
    reached up and received an electric shock. When I examined the lamp, I
    found half of the lightbulb was missing with the filament exposed.

    In the morning, I mentioned this and my brother said that 'Davie' had
    slept in my bed the night before when the bulb exploded. I asked what
    he did about it and he said they swept away the glass. I asked about
    the bulb and he said he assumed my dad's housekeeper would check the
    lightbulbs each morning.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Scott@21:1/5 to tnp@invalid.invalid on Wed Mar 5 20:12:09 2025
    On Wed, 5 Mar 2025 18:59:55 +0000, The Natural Philosopher <tnp@invalid.invalid> wrote:

    On 05/03/2025 16:38, Jethro_uk wrote:
    On Wed, 05 Mar 2025 16:11:38 +0000, Tim Streater wrote:

    On 5 Mar 2025 at 16:06:07 GMT, "David Wade" <dave@g4ugm.invalid> wrote:

    On 05/03/2025 16:38, Tim Streater wrote:
    On 5 Mar 2025 at 14:47:11 GMT, "Scott" <newsgroups@gefion.myzen.co.uk> >>>>> wrote:

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps. >>>>>> How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    If it's a 16-amp supply, you better not draw more than 16 amps off it. >>>>> If the plug is rated at 2.5 amps, your device you're connecting the
    plug to better not draw more than 2.5 amps. 2.5 is a lot less than 16, >>>>> so why d'ye think it would be dangerous? Just because the supply is
    rated at 16 amps, doesn't mean that it's gonna force 16 amps through >>>>> your plug. The current taken is determined only by the device you've >>>>> connected the plug to.

    I think the question is why in the UK are we required to fit a fuse
    when in the rest of the world they rely on the Circuit Breaker in the
    "consumer unit".

    Here in Spain the Air Fryer I have just purchased from Aldi has no
    fuse.
    As its 1.4kw in the UK it will have a 13 amp fuse.

    WHY?

    Perhaps we're more safety conscious? The Yanks, with their cheese-paring >>> 110V,
    are even worse off, with four times the heating effect (for a given
    device wattage) in the cabling and plugs.

    They can get 240V as most houses are supplied by 2 phases. A bit fiddly,
    but you can work with it.

    Not 2 phases. One centre tapped phase.

    The video describes it as two phases: +120V / -120V

    --- SoupGate-Win32 v1.05
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  • From Theo@21:1/5 to John Rumm on Wed Mar 5 21:07:46 2025
    John Rumm <see.my.signature@nowhere.null> wrote:
    On 05/03/2025 18:24, Theo wrote:
    The general European idea is the socket would be on a 16A MCB radial, so fault currents would be limited to 16A. The UK has a 32A ring main, from which you could draw a 32A fault current - that's bad.

    With respect, that's nonsense!

    MCBs don't limit fault currents (or any other current) - only ohms can
    limit current.

    They interrupt the current if you draw too much, ie the fault current is time-limited. If you draw very too much, the time is limited even more.
    The damage done by a fault current is usually due to heating and that's a function of both current and time. So the MCB limits the integral of
    current over time, which is what causes damage, if not the instantaneous
    peak current. Indeed, many appliances wouldn't work if they did trip based
    on an instantaneous peak current.

    (I'm glossing over the fact that a 16A MCB won't trip at 16.01A even continuous, but it's highly likely that a fault current will be
    substantially higher than the rated current so this won't matter)

    So instead plugs are fused at 13A. When you plug in an appliance, either it has an internal fuse (often non replaceable) or an internal design that inherently limits the current. So really the plugtop fuse protects from a nail through the flex or similar short circuit before the appliance.

    Once you have a plug fuse, you can then replace it with a lower rated one, to match a thinner cable. You can't do that woth a Europlug, but the cable may ultimately act as its own fuse.

    It is one of the reasons that many appliances have short cables. It
    means the maker can cheap out on thin flex, and still stay just inside
    the threshold where the flex will survive the anticipated fault current
    for long enough to operate the circuit protective device.

    That's notable on power tools - and of course people put them on extension leads.

    Theo

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From John Rumm@21:1/5 to Theo on Wed Mar 5 21:24:00 2025
    On 05/03/2025 21:07, Theo wrote:
    John Rumm <see.my.signature@nowhere.null> wrote:
    On 05/03/2025 18:24, Theo wrote:
    The general European idea is the socket would be on a 16A MCB radial, so >>> fault currents would be limited to 16A. The UK has a 32A ring main, from >>> which you could draw a 32A fault current - that's bad.

    With respect, that's nonsense!

    MCBs don't limit fault currents (or any other current) - only ohms can
    limit current.

    They interrupt the current if you draw too much, ie the fault current is time-limited.

    Indeed - that is the key, the MCB can only limit duration not magnitude.

    If you draw very too much, the time is limited even more.

    Once you hit the fault current threshold, the response time will be
    pretty much the same regardless of magnitude. Fuses get faster with
    higher fault currents.

    The damage done by a fault current is usually due to heating and that's a function of both current and time. So the MCB limits the integral of
    current over time, which is what causes damage, if not the instantaneous

    Yup the so called "let through" energy - I^2 x t

    peak current. Indeed, many appliances wouldn't work if they did trip based on an instantaneous peak current.

    Hence why the fault trip kicks in at 5x, 10x, or 20x nominal current on
    a type B, C, or D MCB

    (I'm glossing over the fact that a 16A MCB won't trip at 16.01A even continuous, but it's highly likely that a fault current will be
    substantially higher than the rated current so this won't matter)

    So instead plugs are fused at 13A. When you plug in an appliance, either it >>> has an internal fuse (often non replaceable) or an internal design that
    inherently limits the current. So really the plugtop fuse protects from a >>> nail through the flex or similar short circuit before the appliance.

    Once you have a plug fuse, you can then replace it with a lower rated one, >>> to match a thinner cable. You can't do that woth a Europlug, but the cable >>> may ultimately act as its own fuse.

    It is one of the reasons that many appliances have short cables. It
    means the maker can cheap out on thin flex, and still stay just inside
    the threshold where the flex will survive the anticipated fault current
    for long enough to operate the circuit protective device.

    That's notable on power tools - and of course people put them on extension leads.

    Power tool leads are not usually that skinny IME although some do have
    too short leads (or too stiff). 4m is a decent length I find.


    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From ARW@21:1/5 to John Rumm on Tue Mar 11 20:10:38 2025
    On 05/03/2025 18:53, John Rumm wrote:
    On 05/03/2025 17:43, Joe wrote:
    On 5 Mar 2025 16:07:08 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A?
    The 16A circuit fuse will not fail, but the appliance flex may be
    able to carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.


    This case was a Europlug, no fuse.

    What now?

    That is when you apply the adiabatic equation... [1]


    You can do a "fault withstand" calculation to check that the amount of
    metal available in the conductors will safely handle the fault condition.

    For example, let's say you have a table lamp with 2m of 0.5mm^2 flex on
    it. It is on the end of a long circuit with a 32A MCB at the origin. The
    plug has a 13A fuse in it. What happens when you cut through the flex
    next to the lamp with wire cutters when it is powered on?

    The first thing you work out the prospective fault current. So you need
    to add up the external earth loop impedance, the circuit resistance to
    the socket, and the resistance to the far end of the flex.

    Let's say that is 0.35 ohms for the external earth loop, another ohm in
    the circuit wires, and another 0.15 ohms for the far end of the flex.
    That is 1.5 ohms. So the fault current at the far end of the flex could
    be 230 / 1.5 = 153A. Sounds like a lot for a 3A flex!

    However on the bright side that is comfortably enough to blow the fuse
    in the plug, so it will only carry that current for a very short time.
    Let's assume 0.1 secs (in reality it could be much less - fuses can be
    very fast for massive fault currents).

    We can assume all the cables have PVC insulation - so we can use the "k factor" of 115, in the equation:

    s = sqrt( I^2 . t ) / k

    s = sqrt( 153^2 x 0.1 ) / 115

    s = 0.42mm^2

    So you need at least 0.42mm^2 of copper cable area to be able to safely
    clear the fault by blowing the plug fuse, and we can conclude that the 0.5mm^2 flex will live to fight another day.


    [1] https://wiki.diyfaq.org.uk/index.php/ Calculating_A_Cable_Size#Adiabatic_Check



    You can check the adiabatic current if you want. But there’s not much
    you can do about the current that is drawn in a fault condition....

    Says he who just knocked out a substation in Leeds:-)

    It probably needed new fuses anyway so it keeps people in a job.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Andy Burns@21:1/5 to ARW on Tue Mar 11 21:16:48 2025
    ARW wrote:

    Says he who just knocked out a substation in Leeds :-)

    So have you got copper-coated eyebrows?

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From John Rumm@21:1/5 to ARW on Wed Mar 12 11:02:34 2025
    On 11/03/2025 20:10, ARW wrote:

    You can check the adiabatic current if you want. But there’s not much
    you can do about the current that is drawn in a fault condition....

    Says he who just knocked out a substation in Leeds:-)

    Nice :-)

    How did that happen?

    It probably needed new fuses anyway so it keeps people in a job.


    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

    --- SoupGate-Win32 v1.05
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  • From Timatmarford@21:1/5 to John Rumm on Wed Mar 12 14:37:06 2025
    On 12/03/2025 11:02, John Rumm wrote:
    On 11/03/2025 20:10, ARW wrote:

    You can check the adiabatic current if you want. But there’s not much
    you can do about the current that is drawn in a fault condition....

    Says he who just knocked out a substation in Leeds:-)

    Nice :-)

    How did that happen?

    It probably needed new fuses anyway so it keeps people in a job.

    Hmm.. I had just *reluctantly* taken over as Chief Electrical Engineer
    when building contractors put a digger bucket through the factory 11kV
    ring main. Normally run open to limit fault current.

    The senior electrical foreman was confident the fault could be overcome
    by re-routing the supplies and closed the ring into the fault! This shut
    down the entire factory!

    During substation maintenance next Summer we discovered the 11kV switch contacts and the 132kV incomer contacts needed replacement!

    The contractors insurers got a significant bill as they had been told to
    dig by hand.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From SH@21:1/5 to ARW on Thu Mar 13 20:11:50 2025
    On 11/03/2025 20:10, ARW wrote:
    On 05/03/2025 18:53, John Rumm wrote:
    On 05/03/2025 17:43, Joe wrote:
    On 5 Mar 2025 16:07:08 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A?
    The 16A circuit fuse will not fail, but the appliance flex may be
    able to carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.


    This case was a Europlug, no fuse.

    What now?

    That is when you apply the adiabatic equation... [1]


    You can do a "fault withstand" calculation to check that the amount of
    metal available in the conductors will safely handle the fault condition.

    For example, let's say you have a table lamp with 2m of 0.5mm^2 flex
    on it. It is on the end of a long circuit with a 32A MCB at the
    origin. The plug has a 13A fuse in it. What happens when you cut
    through the flex next to the lamp with wire cutters when it is powered
    on?

    The first thing you work out the prospective fault current. So you
    need to add up the external earth loop impedance, the circuit
    resistance to the socket, and the resistance to the far end of the flex.

    Let's say that is 0.35 ohms for the external earth loop, another ohm
    in the circuit wires, and another 0.15 ohms for the far end of the
    flex. That is 1.5 ohms. So the fault current at the far end of the
    flex could be 230 / 1.5 = 153A. Sounds like a lot for a 3A flex!

    However on the bright side that is comfortably enough to blow the fuse
    in the plug, so it will only carry that current for a very short time.
    Let's assume 0.1 secs (in reality it could be much less - fuses can be
    very fast for massive fault currents).

    We can assume all the cables have PVC insulation - so we can use the
    "k factor" of 115, in the equation:

    s = sqrt( I^2 . t ) / k

    s = sqrt( 153^2 x 0.1 ) / 115

    s = 0.42mm^2

    So you need at least 0.42mm^2 of copper cable area to be able to
    safely clear the fault by blowing the plug fuse, and we can conclude
    that the 0.5mm^2 flex will live to fight another day.


    [1] https://wiki.diyfaq.org.uk/index.php/
    Calculating_A_Cable_Size#Adiabatic_Check



    You can check the adiabatic current if you want. But there’s not much
    you can do about the current that is drawn in a fault condition....

    Says he who just knocked out a substation in Leeds:-)

    It probably needed new fuses anyway so it keeps people in a job.




    Did this involve you being sarcastic to an apprentice along the lines of
    "Yeah, it is OK to put a metal bar across L & N before the cutout fuse
    as a safe means of isolating a house before working on the CU"?

    And said Apprentice went and put a tyre lever across said cutout?

    Its one way of getting rid of the apprentices you don't think much of I guess...... :-D

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Scott@21:1/5 to newsgroups@gefion.myzen.co.uk on Fri Mar 14 09:29:00 2025
    On Wed, 05 Mar 2025 14:47:11 +0000, Scott
    <newsgroups@gefion.myzen.co.uk> wrote:

    Returning to my lamp, this was bought in Denmark and is fitted with a
    two pin Europlug.

    I was taught (probably at primary school) that the purpose of the fuse
    was to protect the appliance including its lead from overload. It is
    always said on this group and elsewhere that the fuse is intended to
    protect the flex not the appliance. I can understand that a five amp
    flex cannot be connected to a 32 amp ring main. However, how do we
    know that the internal wiring is not restricted to three amps and also >requires a fuse?

    In the case of the lamp, I believe a Europlug is rated at 2.5 amps.
    How do the Danes conclude it is safe to plug this into a 16 amp
    supply? I have fitted a two amp fuse.

    I am genuinely curious.

    As an aside, I found an old pack of plug fuses marked 240V 50Hz. Does
    the fuse relate to the frequency? I assumed as a thermal device it
    would not. Also, do any 60Hz countries use BS fuses anyway?

    --- SoupGate-Win32 v1.05
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  • From ARW@21:1/5 to All on Fri Mar 14 23:25:39 2025
    On 13/03/2025 20:11, SH wrote:
    On 11/03/2025 20:10, ARW wrote:
    On 05/03/2025 18:53, John Rumm wrote:
    On 05/03/2025 17:43, Joe wrote:
    On 5 Mar 2025 16:07:08 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A? >>>>>> The 16A circuit fuse will not fail, but the appliance flex may be
    able to carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.


    This case was a Europlug, no fuse.

    What now?

    That is when you apply the adiabatic equation... [1]


    You can do a "fault withstand" calculation to check that the amount
    of metal available in the conductors will safely handle the fault
    condition.

    For example, let's say you have a table lamp with 2m of 0.5mm^2 flex
    on it. It is on the end of a long circuit with a 32A MCB at the
    origin. The plug has a 13A fuse in it. What happens when you cut
    through the flex next to the lamp with wire cutters when it is
    powered on?

    The first thing you work out the prospective fault current. So you
    need to add up the external earth loop impedance, the circuit
    resistance to the socket, and the resistance to the far end of the flex. >>>
    Let's say that is 0.35 ohms for the external earth loop, another ohm
    in the circuit wires, and another 0.15 ohms for the far end of the
    flex. That is 1.5 ohms. So the fault current at the far end of the
    flex could be 230 / 1.5 = 153A. Sounds like a lot for a 3A flex!

    However on the bright side that is comfortably enough to blow the
    fuse in the plug, so it will only carry that current for a very short
    time. Let's assume 0.1 secs (in reality it could be much less - fuses
    can be very fast for massive fault currents).

    We can assume all the cables have PVC insulation - so we can use the
    "k factor" of 115, in the equation:

    s = sqrt( I^2 . t ) / k

    s = sqrt( 153^2 x 0.1 ) / 115

    s = 0.42mm^2

    So you need at least 0.42mm^2 of copper cable area to be able to
    safely clear the fault by blowing the plug fuse, and we can conclude
    that the 0.5mm^2 flex will live to fight another day.


    [1] https://wiki.diyfaq.org.uk/index.php/
    Calculating_A_Cable_Size#Adiabatic_Check



    You can check the adiabatic current if you want. But there’s not much
    you can do about the current that is drawn in a fault condition....

    Says he who just knocked out a substation in Leeds:-)

    It probably needed new fuses anyway so it keeps people in a job.




    Did this involve you being sarcastic to an apprentice along the lines of "Yeah, it is OK to put a metal bar across L & N before the cutout fuse
    as a safe means of isolating a house before working on the CU"?

    And said Apprentice went and put a tyre lever across said cutout?

    Its one way of getting rid of the apprentices you don't think much of I guess......   :-D



    Worse than LN.

    It was LL.

    Something dropped down a badly designed/installed incoming main isolator.

    Not sure what the something was as it melted.

    Anyway it was an expensive repair as it involved digging up the road to
    replace the isolator.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Vir Campestris@21:1/5 to John Rumm on Mon Mar 17 16:00:05 2025
    On 05/03/2025 18:53, John Rumm wrote:
    On 05/03/2025 17:43, Joe wrote:
    On 5 Mar 2025 16:07:08 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A?
    The 16A circuit fuse will not fail, but the appliance flex may be
    able to carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.


    This case was a Europlug, no fuse.

    What now?

    That is when you apply the adiabatic equation... [1]


    You can do a "fault withstand" calculation to check that the amount of
    metal available in the conductors will safely handle the fault condition.

    For example, let's say you have a table lamp with 2m of 0.5mm^2 flex on
    it. It is on the end of a long circuit with a 32A MCB at the origin. The
    plug has a 13A fuse in it. What happens when you cut through the flex
    next to the lamp with wire cutters when it is powered on?

    The first thing you work out the prospective fault current. So you need
    to add up the external earth loop impedance, the circuit resistance to
    the socket, and the resistance to the far end of the flex.

    Let's say that is 0.35 ohms for the external earth loop, another ohm in
    the circuit wires, and another 0.15 ohms for the far end of the flex.
    That is 1.5 ohms. So the fault current at the far end of the flex could
    be 230 / 1.5 = 153A. Sounds like a lot for a 3A flex!

    However on the bright side that is comfortably enough to blow the fuse
    in the plug, so it will only carry that current for a very short time.
    Let's assume 0.1 secs (in reality it could be much less - fuses can be
    very fast for massive fault currents).

    We can assume all the cables have PVC insulation - so we can use the "k factor" of 115, in the equation:

    s = sqrt( I^2 . t ) / k

    s = sqrt( 153^2 x 0.1 ) / 115

    s = 0.42mm^2

    So you need at least 0.42mm^2 of copper cable area to be able to safely
    clear the fault by blowing the plug fuse, and we can conclude that the 0.5mm^2 flex will live to fight another day.


    [1] https://wiki.diyfaq.org.uk/index.php/ Calculating_A_Cable_Size#Adiabatic_Check


    Yes... but... up top he was talking about Euro circuits where there is
    no plug fuse. Surely Euro regs don't require a cable capable of taking
    the full output of the circuit on a lamp?

    Andy

    --
    Do not listen to rumour, but, if you do, do not believe it.
    Ghandi.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From John Rumm@21:1/5 to Vir Campestris on Mon Mar 17 23:18:55 2025
    On 17/03/2025 16:00, Vir Campestris wrote:
    On 05/03/2025 18:53, John Rumm wrote:
    On 05/03/2025 17:43, Joe wrote:
    On 5 Mar 2025 16:07:08 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A?
    The 16A circuit fuse will not fail, but the appliance flex may be
    able to carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.


    This case was a Europlug, no fuse.

    What now?

    That is when you apply the adiabatic equation... [1]


    You can do a "fault withstand" calculation to check that the amount of
    metal available in the conductors will safely handle the fault condition.

    For example, let's say you have a table lamp with 2m of 0.5mm^2 flex
    on it. It is on the end of a long circuit with a 32A MCB at the
    origin. The plug has a 13A fuse in it. What happens when you cut
    through the flex next to the lamp with wire cutters when it is powered
    on?

    The first thing you work out the prospective fault current. So you
    need to add up the external earth loop impedance, the circuit
    resistance to the socket, and the resistance to the far end of the flex.

    Let's say that is 0.35 ohms for the external earth loop, another ohm
    in the circuit wires, and another 0.15 ohms for the far end of the
    flex. That is 1.5 ohms. So the fault current at the far end of the
    flex could be 230 / 1.5 = 153A. Sounds like a lot for a 3A flex!

    However on the bright side that is comfortably enough to blow the fuse
    in the plug, so it will only carry that current for a very short time.
    Let's assume 0.1 secs (in reality it could be much less - fuses can be
    very fast for massive fault currents).

    We can assume all the cables have PVC insulation - so we can use the
    "k factor" of 115, in the equation:

    s = sqrt( I^2 . t ) / k

    s = sqrt( 153^2 x 0.1 ) / 115

    s = 0.42mm^2

    So you need at least 0.42mm^2 of copper cable area to be able to
    safely clear the fault by blowing the plug fuse, and we can conclude
    that the 0.5mm^2 flex will live to fight another day.


    [1] https://wiki.diyfaq.org.uk/index.php/
    Calculating_A_Cable_Size#Adiabatic_Check


    Yes... but... up top he was talking about Euro circuits where there is
    no plug fuse. Surely Euro regs don't require a cable capable of taking
    the full output of the circuit on a lamp?

    The flex to the lamp does not need to be capable of taking the full
    output of the circuit *continuously*, it just needs to be able to
    survive the full prospective short circuit current[1] for long enough to
    open the circuit protective device.

    So here, that would usually be to survive until the 13A fuse in the plug
    blows, and elsewhere, until the 16A breaker in the CU trips. (so in
    reality, not that different)

    That is what the adiabatic calc will attempt to predict.


    [1] Which will be significantly *more* than the full circuit capacity

    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Scott@21:1/5 to see.my.signature@nowhere.null on Tue Mar 18 10:01:05 2025
    On Mon, 17 Mar 2025 23:18:55 +0000, John Rumm
    <see.my.signature@nowhere.null> wrote:

    On 17/03/2025 16:00, Vir Campestris wrote:
    On 05/03/2025 18:53, John Rumm wrote:
    On 05/03/2025 17:43, Joe wrote:
    On 5 Mar 2025 16:07:08 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A? >>>>>> The 16A circuit fuse will not fail, but the appliance flex may be
    able to carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.


    This case was a Europlug, no fuse.

    What now?

    That is when you apply the adiabatic equation... [1]


    You can do a "fault withstand" calculation to check that the amount of
    metal available in the conductors will safely handle the fault condition. >>>
    For example, let's say you have a table lamp with 2m of 0.5mm^2 flex
    on it. It is on the end of a long circuit with a 32A MCB at the
    origin. The plug has a 13A fuse in it. What happens when you cut
    through the flex next to the lamp with wire cutters when it is powered
    on?

    The first thing you work out the prospective fault current. So you
    need to add up the external earth loop impedance, the circuit
    resistance to the socket, and the resistance to the far end of the flex. >>>
    Let's say that is 0.35 ohms for the external earth loop, another ohm
    in the circuit wires, and another 0.15 ohms for the far end of the
    flex. That is 1.5 ohms. So the fault current at the far end of the
    flex could be 230 / 1.5 = 153A. Sounds like a lot for a 3A flex!

    However on the bright side that is comfortably enough to blow the fuse
    in the plug, so it will only carry that current for a very short time.
    Let's assume 0.1 secs (in reality it could be much less - fuses can be
    very fast for massive fault currents).

    We can assume all the cables have PVC insulation - so we can use the
    "k factor" of 115, in the equation:

    s = sqrt( I^2 . t ) / k

    s = sqrt( 153^2 x 0.1 ) / 115

    s = 0.42mm^2

    So you need at least 0.42mm^2 of copper cable area to be able to
    safely clear the fault by blowing the plug fuse, and we can conclude
    that the 0.5mm^2 flex will live to fight another day.


    [1] https://wiki.diyfaq.org.uk/index.php/
    Calculating_A_Cable_Size#Adiabatic_Check


    Yes... but... up top he was talking about Euro circuits where there is
    no plug fuse. Surely Euro regs don't require a cable capable of taking
    the full output of the circuit on a lamp?

    That was me !!! And indeed, this is what I was wondering about (as
    well as the 2.5A rated Europlug).

    The flex to the lamp does not need to be capable of taking the full
    output of the circuit *continuously*, it just needs to be able to
    survive the full prospective short circuit current[1] for long enough to
    open the circuit protective device.

    So here, that would usually be to survive until the 13A fuse in the plug >blows, and elsewhere, until the 16A breaker in the CU trips. (so in
    reality, not that different)

    If it is a 13A fuse. When I was a boy, we used 2, 3 and 5 amp fuses
    for the smaller appliances. I still fit the smaller fuses where I know
    I can (as I have a big stock of them).

    That is what the adiabatic calc will attempt to predict.

    [1] Which will be significantly *more* than the full circuit capacity

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From John Rumm@21:1/5 to Scott on Sat Mar 22 23:49:24 2025
    On 18/03/2025 10:01, Scott wrote:
    On Mon, 17 Mar 2025 23:18:55 +0000, John Rumm
    <see.my.signature@nowhere.null> wrote:

    On 17/03/2025 16:00, Vir Campestris wrote:
    On 05/03/2025 18:53, John Rumm wrote:
    On 05/03/2025 17:43, Joe wrote:
    On 5 Mar 2025 16:07:08 GMT
    Tim Streater <tim@streater.me.uk> wrote:

    On 5 Mar 2025 at 16:03:11 GMT, "Joe" <joe@jretrading.com> wrote:

    So what happens if a fault occurs in the appliance which draws 12A? >>>>>>> The 16A circuit fuse will not fail, but the appliance flex may be >>>>>>> able to carry only 5A safely, and overheat dangerously.

    Then the fuse in your plug blows.


    This case was a Europlug, no fuse.

    What now?

    That is when you apply the adiabatic equation... [1]


    You can do a "fault withstand" calculation to check that the amount of >>>> metal available in the conductors will safely handle the fault condition. >>>>
    For example, let's say you have a table lamp with 2m of 0.5mm^2 flex
    on it. It is on the end of a long circuit with a 32A MCB at the
    origin. The plug has a 13A fuse in it. What happens when you cut
    through the flex next to the lamp with wire cutters when it is powered >>>> on?

    The first thing you work out the prospective fault current. So you
    need to add up the external earth loop impedance, the circuit
    resistance to the socket, and the resistance to the far end of the flex. >>>>
    Let's say that is 0.35 ohms for the external earth loop, another ohm
    in the circuit wires, and another 0.15 ohms for the far end of the
    flex. That is 1.5 ohms. So the fault current at the far end of the
    flex could be 230 / 1.5 = 153A. Sounds like a lot for a 3A flex!

    However on the bright side that is comfortably enough to blow the fuse >>>> in the plug, so it will only carry that current for a very short time. >>>> Let's assume 0.1 secs (in reality it could be much less - fuses can be >>>> very fast for massive fault currents).

    We can assume all the cables have PVC insulation - so we can use the
    "k factor" of 115, in the equation:

    s = sqrt( I^2 . t ) / k

    s = sqrt( 153^2 x 0.1 ) / 115

    s = 0.42mm^2

    So you need at least 0.42mm^2 of copper cable area to be able to
    safely clear the fault by blowing the plug fuse, and we can conclude
    that the 0.5mm^2 flex will live to fight another day.


    [1] https://wiki.diyfaq.org.uk/index.php/
    Calculating_A_Cable_Size#Adiabatic_Check


    Yes... but... up top he was talking about Euro circuits where there is
    no plug fuse. Surely Euro regs don't require a cable capable of taking
    the full output of the circuit on a lamp?

    That was me !!! And indeed, this is what I was wondering about (as
    well as the 2.5A rated Europlug).

    The flex to the lamp does not need to be capable of taking the full
    output of the circuit *continuously*, it just needs to be able to
    survive the full prospective short circuit current[1] for long enough to
    open the circuit protective device.

    So here, that would usually be to survive until the 13A fuse in the plug
    blows, and elsewhere, until the 16A breaker in the CU trips. (so in
    reality, not that different)

    If it is a 13A fuse. When I was a boy, we used 2, 3 and 5 amp fuses
    for the smaller appliances. I still fit the smaller fuses where I know
    I can (as I have a big stock of them).

    Nothing wrong with using more closely matched fuses and it is still good practice. However these days a maker of an appliance will want to sell
    it in multiple markets, and so has to accept that in many of those, the
    plug fuse won't be there.

    Hence why you design your product so that when bad stuff happens it
    still fails safe.

    --
    Cheers,

    John.

    /=================================================================\
    | Internode Ltd - http://www.internode.co.uk | |-----------------------------------------------------------------|
    | John Rumm - john(at)internode(dot)co(dot)uk | \=================================================================/

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Scott@21:1/5 to see.my.signature@nowhere.null on Sun Mar 23 15:53:35 2025
    On Sat, 22 Mar 2025 23:49:24 +0000, John Rumm
    <see.my.signature@nowhere.null> wrote:
    On 18/03/2025 10:01, Scott wrote:
    [snip]

    If it is a 13A fuse. When I was a boy, we used 2, 3 and 5 amp fuses
    for the smaller appliances. I still fit the smaller fuses where I know
    I can (as I have a big stock of them).

    Nothing wrong with using more closely matched fuses and it is still good >practice. However these days a maker of an appliance will want to sell
    it in multiple markets, and so has to accept that in many of those, the
    plug fuse won't be there.

    Hence why you design your product so that when bad stuff happens it
    still fails safe.

    This was my understanding of the term 'harmonised' employed by the EU.

    I take your point entirely about knowledge. I remember at my first
    conveyancing lecture, the professor said that any citizen is entitled
    to do their own conveyancing 'just as you are entitled to take out
    your own appendix but this does not mean it is a good idea'.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)